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Using ALL of the numbers 12, 4, 7, 1, 2, 5, 21, 88, create an expression that equals 109. You must use each number exactly once. You may use +, -, *, /.
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{"numbers": [12, 4, 7, 1, 2, 5, 21, 88], "target": 109, "operators_used": ["/", "+", "/", "/", "/", "*", "+"], "expression": "12 / 4 + 7 / 1 / 2 / 5 * 21 + 88"}
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"content": "You are a helpful assistant that solves math problems by reasoning step-by-step. Show your work clearly and provide complete solutions. You MUST use ALL of the given numbers exactly once in your solution. When you have a final answer, wrap it in <answer></answer> tags.",
"role": "system"
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{
"content": "Using ALL of the numbers 12, 4, 7, 1, 2, 5, 21, 88, create an expression that equals 109. You must use each number exactly once. You may use +, -, *, /.",
"role": "user"
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"Okay, let's see. I need to use all the numbers 12, 4, 7, 1, 2, 5, 21, 88 exactly once with +, -, *, / to make 109. Hmm, this might take a while. Let me start by listing out the numbers again to make sure I have them all: 12, 4, 7, 1, 2, 5, 21, 88. Eight numbers total. So, I need to combine them with operations to reach 109.\n\nFirst thought: 88 is a big number, maybe it's part of the main addition. If I take 88 and add some other numbers to get close to 109. Let's see, 109 - 88 = 21. Wait, but 21 is one of the numbers. Wait, but if I do 88 + 21, that's 109 already. But then I still have to use all the other numbers: 12, 4, 7, 1, 2, 5. So that's a problem. So 88 + 21 is 109, but I can't just ignore the rest. So maybe 88 + something else equals 109, and then somehow incorporate the other numbers in a way that cancels out or adds zero? Wait, but we have to use all numbers exactly once, so we can't just have 88 + 21 and then do something like *1 or +0, because we have to use the other numbers. Hmm.\n\nWait, maybe 88 plus some combination that equals 21. Wait, but 88 + (some expression with the rest of the numbers) = 109. So the rest of the numbers need to sum to 21. Let's check: total of the other numbers: 12 + 4 + 7 + 1 + 2 + 5 = 31. So 31. But we need 21. So maybe 31 minus something? Wait, but if we have to use all numbers, maybe we need to combine them with operations, not just add. So maybe 88 + (something) = 109, where \"something\" uses the other numbers. Let's think.\n\nAlternatively, maybe multiply some numbers. Let's see. 88 is the largest number. Let's see if we can get 109 by adding 88 to a smaller number. 109 - 88 = 21. But 21 is already a number. Wait, but if we do 88 + 21 = 109, but then we have to use the other numbers. So maybe 88 + 21 + (some expression with the rest that equals 0). But how? For example, (12 - 12), but we don't have two 12s. Wait, we have to use each number once. So maybe something like (12 - 4 - 7 - 1 - 2 - 5) but that would be 12 - 4=8, 8-7=1, 1-1=0, 0-2=-2, -2-5=-7. Not zero. Hmm.\n\nAlternatively, maybe multiply some numbers to get a larger value. Wait, 88 is big. Let's see. Let's think of other combinations. What if we take 88 + 21 = 109, but then we need to use the other numbers in a way that their total effect is zero. But how? Like multiplying by 1 or adding zero. Wait, for example, if we have (88 + 21) * (something that equals 1), but we need to use all numbers. Wait, but we have to use all numbers in the expression. So maybe 88 + 21 + (12 - 12), but again, duplicates. Not allowed.\n\nWait, maybe I need to not use 88 and 21 directly. Let's think differently. Let's consider that 109 is a prime number, so maybe it's a sum of a few larger numbers. Let's see. Let's list all numbers: 88, 21, 12, 7, 5, 4, 2, 1.\n\nAnother idea: 88 + 12 = 100. Then 100 + 9 = 109. How to get 9 from the remaining numbers: 7, 1, 2, 5, 4. Wait, remaining numbers would be 7, 1, 2, 5, 4. Wait, but we need to use all numbers. Wait, if we use 88 + 12, then we have 7,1,2,5,4,21 left. Wait, no, original list is 12,4,7,1,2,5,21,88. So if we use 88 and 12, then the rest are 4,7,1,2,5,21. Hmm. Wait, 88 + 12 = 100. Then 100 + 9 = 109. Let's see if we can make 9 from 21, 4,7,1,2,5. Wait, 21 is a big number. Maybe 21 - 12, but 12 is already used. Hmm.\n\nWait, maybe 88 + 21 = 109. So if we could somehow have 88 + 21 + (some expression that equals 0 using the other numbers). But the problem is that we have to use all numbers in the expression, not just add zero. So maybe (88 + 21) + (12 - 12), but again, duplicate. Not allowed. So that's not the way.\n\nWait, perhaps use division or multiplication. Let's think. For example, 88 + (something) = 109. So something = 21. But 21 is already a number. Wait, but maybe 21 can be formed from other numbers. Wait, but 21 is one of the numbers, so we can't form it again. Wait, no, we have to use all numbers once. So 21 has to be used as is. So if we use 88 and 21, then the rest have to be used in operations that result in 0. Hmm.\n\nWait, here's an idea. Maybe (88 + 21) + (something - something else) where the something and something else use the remaining numbers. Wait, but how? Let's list the remaining numbers: 12, 4, 7, 1, 2, 5. So six numbers. If we can pair them up to subtract to zero. For example, (12 - 12) but again duplicates. Alternatively, (12 - 4 - 7 - 1 + 2 - 5). Let's compute that: 12 -4=8, 8-7=1, 1-1=0, 0+2=2, 2-5=-3. Not zero. Hmm.\n\nWait, maybe multiply some numbers to get 1 so that multiplying by it doesn't change the value. Like (88 + 21) * (something/something else) = 109. But 88 +21=109, so we need something/something else =1. So for example, (12/12), but again duplicates. Wait, but we have 12,4,7,1,2,5. Let's see: (something / something) =1. So 5/5, but we don't have two 5s. 4/4, same problem. Wait, but maybe (12 - 7 - 4 + 1 + 2 - 5). Wait, 12-7=5, 5-4=1, 1+1=2, 2+2=4, 4-5=-1. Not 1. Hmm.\n\nAlternatively, (5 - (4 - (2 - (1)))) = 5 - (4 -1)=5-3=2. Not helpful.\n\nWait, maybe instead of adding 88 and 21, use a different combination. Let's see. Let's try to get close to 109 with other numbers. 21*5=105. Then 105 +4=109. Wait, 21*5=105, +4=109. Then we have used 21,5,4. Remaining numbers: 12,7,1,2,88. Wait, but we still need to use all numbers. So 21*5 +4 =109, but then we have to incorporate 12,7,1,2,88. Hmm, this seems messy. Wait, unless we can do something like (21*5 +4) + (88 - 88), but again duplicates. Not allowed.\n\nWait, another idea: 88 + 21 = 109, as before. If we can use the other numbers in a fraction that equals 0, but we need to use them all. Wait, maybe (88 + 21) + (12 - 12), but no. Wait, perhaps using division. Like 88 + 21 + ( (12 - 12) * ... ), but again, duplicates.\n\nWait, maybe I need to not use 88 and 21 together. Let's try other combinations. How about 12*7=84. Then 84 + something. 84 + 21=105, 105 +4=109. Wait, so 12*7 +21 +4= 84+21=105+4=109. But then we have used 12,7,21,4. Remaining numbers: 1,2,5,88. Need to use them. So how? If we can do (12*7 +21 +4) + (88 -88) but again duplicates. Not good.\n\nWait, but maybe multiply by 1 or add 0. For instance, 12*7 +21 +4 + (5 -5), but no. Wait, remaining numbers are 1,2,5,88. Maybe (88 / (something)) or something. Let's see. If we have 109 = 12*7 +21 +4 + (1*2*5 - 88). Wait, 1*2*5=10, 10 -88= -78. So 84+21+4-78= 109? Let's check: 84+21=105, +4=109, then 109 -78=31. Not 109. Not helpful.\n\nWait, maybe (12*7) + (21 - (88 / (5 - (2 + 1)) )) Hmm, complicated. Let's break it down. 5 - (2 +1)=2. 88 /2=44. Then 21 -44= -23. Then 84 -23=61. Not 109.\n\nHmm. Maybe another approach. Let's think of the total sum of all numbers: 12+4+7+1+2+5+21+88. Let's calculate that. 12+4=16, +7=23, +1=24, +2=26, +5=31, +21=52, +88=140. So total sum is 140. We need 109, which is 31 less than 140. So if we can turn some additions into subtractions to reduce the total by 31. Wait, because each time we subtract instead of add a number, we reduce the total by twice that number. For example, if we have a +b -c instead of +b +c, we reduce by 2c. So total reduction needed is 140 - 109 =31. So we need to find a subset of numbers that sum to 31/2=15.5, but since we can't have half numbers, this approach might not work. Hmm, maybe this method isn't the best.\n\nWait, but maybe it's a different way. Let's see. If we consider that changing a + to a - for a number x reduces the total by 2x. So total reduction needed is 31. So 2x =31? Not possible. So maybe this approach is invalid. Maybe not the right way.\n\nAlternative idea: Let's look for combinations where a multiplication gives a useful number. For example, 21 - 5 =16, 16* something. Or 88 is close to 109. Wait, 88 + 21 =109. So maybe 88 +21 is part of the solution, and then the other numbers have to be used in a way that cancels out. Wait, but how?\n\nWait, here's a thought. If we do 88 + 21 + (12 - 12), but we don't have two 12s. Wait, but maybe use other numbers to make 0. Like (5 - 5), but again duplicates. Wait, but we have all unique numbers. So maybe ( (something) - (something else) ) =0. Let's see. Let's take the remaining numbers: 12,4,7,1,2,5. Let's see if we can split them into two groups with equal sum. The total of these is 12+4+7+1+2+5=31. So 31 is odd, so it's impossible to split into two equal integer sums. So we can't have two groups adding to 15.5 each. So that approach won't work.\n\nHmm. Maybe use multiplication and division. Let's think. Suppose we have 88 + (21 * something). Wait, 21*5=105, 88+105=193, too big. 21* (something smaller). Maybe 88 + (21 - (something)) =109. So 21 - something =21, so something=0. Not helpful.\n\nWait, 88 + (something) =109, so something=21. So if we can make 21 from the other numbers, but 21 is already one of the numbers. Wait, but we have to use 21 as a separate number. So maybe this is a dead end.\n\nWait, let's try different combinations. Let's see, 5*21=105. Then 105 +4=109. So 5*21 +4=109. Now, we need to use the remaining numbers: 12,7,1,2,88. Wait, but we need to include them in the expression without changing the value. So maybe multiply by 1 or add 0. For example, 5*21 +4 + (12 -12), but again duplicates. Wait, but we have 88, which is a big number. Maybe 88 -88=0, but again duplicate. Hmm.\n\nWait, unless we do something like (5*21 +4) + (88 - 88), but we don't have two 88s. So that's not possible. Alternatively, use 88 in a division. Like (5*21 +4) * (something/something) =109. But we need to use all numbers. Let's see. If we have 5*21 +4 =109, then to incorporate the rest: 12,7,1,2,88. Maybe (5*21 +4) + (88 - 88), but no. Wait, 88 divided by something. Wait, 88 / (12 - (7 + 1 + 2)) = 88 / (12 -10)=88/2=44. Not sure.\n\nWait, maybe (5*21) + (88 / (12 / (7 - (1 + 2)))) Hmm, this is getting too convoluted. Let's try to break it down.\n\nFirst, innermost parentheses: 1 + 2 =3. 7 -3=4. 12 /4=3. Then 88 /3≈29.333. Then 5*21=105 +29.333≈134.333. Not 109.\n\nAnother idea: 88 + 12 =100. Then 100 + 7 + 2 =109. Wait, 88+12+7+2=109. Then we have used 88,12,7,2. Remaining numbers: 4,1,5,21. Need to use them. So how? If we can do 88+12+7+2 + (something - something) where something uses 4,1,5,21. But 88+12+7+2=109 already, so we need to add zero. So maybe (4 -4), but no. Wait, 21 - 5 - (4 +1)=21-5-5=11. Not zero. Hmm.\n\nWait, maybe multiply by (21/21)=1. So (88 +12 +7 +2) * (21 /21) =109*1=109. But we still have to use 4,1,5. Wait, no, we still have 4,1,5 left. So this approach doesn't work.\n\nWait, perhaps 88 + 21 - (something) =109. Wait, 88+21=109, so 109 - something =109 implies something=0. Again, need to make zero from the rest.\n\nWait, let's try to use division. For example, 88 + (21 * (something)). Wait, 21*(5 - (4/ something)). Not sure.\n\nWait, another angle: 109 is a prime, so it's likely a sum or difference of products. Let's see. Let's try 88 + 21 =109. If only I can use the other numbers in a way that they cancel out. Wait, what if we do 88 + 21 + ( (12 - 12) * ... ), but we don't have two 12s. Wait, but we have all numbers once. Wait, maybe ( (5 - (1 + 2 + 4)) * (12 - 7) ). Let's compute that: 5 -7= -2, 12-7=5, so -2*5=-10. Then 88 +21 + (-10)=109-10=99. Not good.\n\nWait, ( (5 * 4) - (1 + 2) ) =20 -3=17. 17 * something. 17*6=102. Not sure.\n\nWait, 12*8=96, but we don't have 8. Wait, 12* (7 + something). 12*9=108. Close to 109. 108 +1=109. So 12*(7 + (something)) +1. Let's see. 12*(7 + x) +1=109. So 12*(7 +x)=108 => 7 +x=9 =>x=2. So x=2. So 12*(7 +2) +1=12*9 +1=108+1=109. Now, check which numbers we've used: 12,7,2,1. Remaining numbers:4,5,21,88. Need to use them. Hmm. So if we can make the rest of the numbers somehow cancel out or be part of the expression. Wait, but the expression so far is 12*(7 + 2) +1 =109. We need to include 4,5,21,88. Maybe multiply by (88/88) or add (21-21), but again duplicates. Not allowed.\n\nWait, unless we can integrate them into the expression. For example, 12*(7 + 2 + (88 - 88)) +1, but again duplicates. Not helpful.\n\nWait, another idea. Let's use 88 and 21 as part of a fraction. Like 88 + (21 * (5 - (4 + 1)/2)). Wait, let's compute that. (4 +1)=5, 5/2=2.5, 5 -2.5=2.5, 21*2.5=52.5, 88 +52.5=140.5. Not 109.\n\nHmm. Maybe 21 * 5 =105, as before. 105 + 4 =109. Then use 88 in a division. Like (21 *5 +4) + (88 - 88), but no. Wait, what if (21 *5) + (88 / (12 - (7 + (2 -1)))) Let's compute denominator: 2 -1=1, 7 +1=8, 12 -8=4. 88 /4=22. Then 105 +22=127. Not 109.\n\nWait, 88 / (something). If I do 88 / (something) = x, then 21*5 + x =109. So x=4. So 88 / (something)=4 => something=22. Can we make 22 from remaining numbers? Remaining numbers after using 21,5,4: 12,7,1,2. Wait, 12 +7 + (2 -1)=12+7+1=20. Not 22. 12 +7 +2 -1=20. 12*2=24, 24 - (7 -1)=24-6=18. Not 22. 12 + (7*2) -1=12+14-1=25. Close. Not 22.\n\nHmm. Let's try another way. Let's consider 109 - 88 =21. So 88 +21=109. If we can write 21 as a combination of the other numbers, but we already have 21 as a number. Wait, no, we need to use 21 as a separate number. So maybe this is the key: we have to use 88 and 21 as separate terms, and the rest of the numbers must somehow not affect the total. But since we have to use all numbers in the expression, we need to include them in a way that their contribution is zero. The only way to do that with basic operations is using multiplication by 1 or addition of 0.\n\nSo, for example, (88 + 21) * (something/something) where something/something =1, using the other numbers. Let's try that.\n\nWe have numbers 12,4,7,1,2,5. Need to make 1 with these. For example, (12 - 7 - (5 - (4 - 2))) /1. Wait, compute inside: 4-2=2, 5-2=3, 12-7=5, 5-3=2. Then 2 /1=2. Not 1.\n\nHow about (5 - (4 + 2 - 1)) / (12 - 7). Let's see: numerator: 5 - (4+2-1)=5 -5=0. Denominator:5. So 0/5=0. Not helpful.\n\nWait, ( (12 / (4 + 2)) * (7 - 5) ) /1. 4+2=6, 12/6=2, 7-5=2, 2*2=4, /1=4. Not 1.\n\nHmm. ( (5 - (7 - (4 + 2))) ) / (12 / something). Wait, 4+2=6, 7-6=1, 5-1=4. Not sure.\n\nWait, maybe ( ( (12 - 7) - (5 - 4) ) / (2 - 1) ). Let's compute: 12-7=5, 5-4=1, 5-1=4. Denominator:2-1=1. So 4/1=4.\n\nNot 1. How about ( ( (12 / 4) - (5 - 2) ) / (7 - 1) ). 12/4=3, 5-2=3, 3-3=0. 0 /6=0.\n\nNot good. Maybe this is too hard. Let's think differently.\n\nWait, what if we do 88 + 21 + ( (5 - 5) * ... ), but we don't have two 5s. Wait, we have one 5. Hmm.\n\nWait, another idea: Use 1 as a multiplier. For example, 88 +21 + (12 * 4 * 7 * 1 * 2 * 5) / (something). But that would be huge. Not helpful.\n\nWait, maybe subtraction. 88 + 21 =109. If we do 88 +21 + 5 -5, but only one 5. Not possible.\n\nWait, let's list all numbers and see possible combinations.\n\nNumbers: 1,2,4,5,7,12,21,88.\n\nWait, 88 + 21 =109. So if we can write the entire expression as 88 + 21 + (1 -1), but we don't have two 1s. Wait, we have a 1. So maybe 88 +21 + (12 - 12), but again duplicates.\n\nWait, unless we use other numbers to make 0. For example, ( (5 + 2) - (4 + 3) ), but we don't have a 3. Wait, remaining numbers:12,4,7,1,2,5. Let's see: 12 - 7 - (5 - (4 - (2 -1))). Let's compute innermost: 2-1=1, 4 -1=3, 5 -3=2, 12 -7=5, 5 -2=3. Not zero.\n\nThis trial and error is taking too long. Maybe I need a better strategy.\n\nLet's consider that we have to use all numbers, so likely there will be multiple operations. Maybe a combination of multiplication and addition.\n\nLet me think of 88 + something =109, so something=21. But 21 is a number, so if we do 88 +21, then we need the rest to cancel. But maybe instead, use division to get a fraction that adds up.\n\nWait, another idea: 88 + (21 * ( (5 - (4 / 2)) / (12 - 7 - 1) )). Let's parse this.\n\nFirst, innermost: 4 /2=2. 5 -2=3.\n\nDenominator: 12 -7 -1=4.\n\nSo 3 /4=0.75.\n\nThen 21 *0.75=15.75.\n\n88 +15.75=103.75. Not 109.\n\nClose, but no.\n\nWait, adjust the denominator. If denominator was 3, then 3/3=1, 21*1=21, 88+21=109. So how to get denominator 3. Let's see: 12 -7 - (something)=3. 12-7=5, so 5 - x=3 =>x=2. So if we have 12 -7 -2=3. Then:\n\n(5 - (4 / (1 + something))) / (12 -7 -2). Wait, let's see.\n\nWait, let's try:\n\n88 + [21 * ( (5 - (4 / (1 + 2))) / (12 - 7) ) ]\n\nCompute innermost: 1 +2=3, 4 /3≈1.333, 5 -1.333≈3.666. Denominator:12-7=5. So 3.666 /5≈0.733. 21*0.733≈15.4. 88+15.4≈103.4. Not good.\n\nWait, what if denominator is 3. Let's get denominator=3. 12 -7 -2=3. So:\n\n(5 - (4 / 1)) / (12 -7 -2) = (5 -4)/3=1/3. 21*(1/3)=7. 88 +7=95. Not enough.\n\nHmm.\n\nWait, 88 + (21 - (something)) =109 => something=21 +88 -109=0. So need to make 0 from other numbers. Let's try:\n\n88 + 21 - (12 - 12), but duplicates. Not allowed.\n\nWait, how about 88 + (21 * (something)) where something=1. So 21*1=21. So 88+21=109. So make something=1 from the rest: 12,4,7,1,2,5.\n\nHow to make 1 with 12,4,7,1,2,5.\n\nFor example: (12 - 7 - (5 - (4 - 2))) /1. Compute: 4-2=2, 5-2=3, 12-7=5, 5-3=2. 2 /1=2. Not 1.\n\n( (5 - 4) + (2 - 1) ) / (12 -7 ). (1 +1)/5=2/5. No.\n\n( (12 / (7 - (5 - 2)) ) - (4 -1) ). 5-2=3, 7-3=4, 12/4=3. 4-1=3. 3 -3=0. Not helpful.\n\nWait, ( (12 - 7 - 5) * (4 - 2 -1) ). 0 *1=0.\n\nNot helpful. Hmm.\n\nWait, ( ( (12 - 7) - 5 ) / (4 - 2 -1) ). (5-5)/1=0/1=0.\n\nStill zero. Not 1.\n\nWait, 5 - 4 =1. Then we have 1. So 5 -4=1. Then we still have 12,7,2,1 left. Wait, but we need to use all numbers. So if we do (5 -4) =1, then we have to use 12,7,2,1. But we already have a 1. Wait, the numbers are 12,4,7,1,2,5. So using 5-4=1, then we have 12,7,2,1 left. But we need to make the entire expression equal to 1 using all of them. Wait, this might be a way.\n\nSo, (5 -4) =1. Then we have 12,7,2,1. Need to make 1 from those. Like (12 -7 -2 -1)=2. Not 1. (12 / (7 +2 +1))=12/10=1.2. Not 1. ( (12 -7) / (2 +1) )=5/3≈1.666. Not 1.\n\nHmm. Alternatively, ( (12 / (7 - (2 +1)) ) -5 +4 ). Wait, getting confused.\n\nWait, let's step back. If I use 5 -4 =1, then to get a total multiplier of 1, maybe:\n\n(5 -4) * (something) =1, where something uses 12,7,2,1. But (5-4)=1, so we need something=1. So same problem.\n\nThis isn't working. Let's try a different combination.\n\nWhat if we do 12*7=84. 84 + 21=105. 105 +4=109. So 12*7 +21 +4=109. Now, remaining numbers: 1,2,5,88. Need to include them. If we can do (12*7 +21 +4) + (88 -88) but no. Wait, but what if we multiply by ( (5 - (2 + 1)) / something ). Wait, 5 - (2 +1)=2. If we do 109 * (2 /2)=109, but we don't have another 2.\n\nWait, here's an idea: Use 88 in a division that results in 1 when combined with other numbers. Like (88 / (88)), but we only have one 88. Not helpful.\n\nWait, what if we take 12*7 +21 +4 + (5 -5), but again duplicate.\n\nWait, maybe use 88 as part of a subtraction. For example, 88 + something =109, so something=21. But we already used 21. Wait, no.\n\nWait, another angle: Let's consider that 109 = 9*12 + 1. 9*12=108 +1=109. So 9*12 +1. How to get 9 from other numbers: 7, 21, 4,5,2,88. Wait, 21 - 12=9, but 12 is used. Wait, 21 - (something)=9. 21 -12=9, but 12 is already used in the 9*12. Hmm.\n\nWait, 9 could be (5 + 4), so 5 +4=9. Then 9*12 +1=108 +1=109. So expression: (5 +4)*12 +1. Now, used numbers:5,4,12,1. Remaining:7,2,21,88. Need to include them.\n\nSo, similar to before, need to make the rest cancel. Maybe ((5 +4)*12 +1) + (21 -21), but duplicate. Or multiply by (88/88).\n\nWait, ((5 +4)*12 +1) * (88 /88) =109*1=109. But we still have 7 and 2 unused. So not good.\n\nWait, unless we do ((5 +4)*12 +1) + (21 - 21), but still missing 7 and 2.\n\nWait, another way: ((5 +4)*12 +1) + (88 - 88 -7 +7 +2 -2), but that's using numbers multiple times. Not allowed.\n\nThis is frustrating. Let's try to find another combination.\n\nHow about 21*5=105. 105 + (88 / (12 / (7 - (4 - 2)))) +1. Wait, let's parse this.\n\nFirst, innermost: 4 -2=2. 7 -2=5. 12 /5=2.4. 88 /2.4≈36.666. 105 +36.666≈141.666 +1≈142.666. Not 109.\n\nNope.\n\nWait, 88 - 21 =67. 67 + something=109. Something=42. Can we make 42 from the rest:12,4,7,1,2,5. 12*4=48, 48 - (7 - (5 - (2 -1)))=48 - (7 - (5 -1))=48 - (7 -4)=48-3=45. Not 42. 7*5=35, 35 + (12 -4 -2 -1)=35+5=40. Close. 7*6=42, but no 6.\n\nWait, 12 + 7 + 5 + 4 + 2 +1=31. Not 42.\n\nHmm.\n\nWait, 88 - (21 - something)=109. So 88 -21 + something=109 => something=42. Again, need 42 from other numbers.\n\nSame problem.\n\nAnother idea: 88 + (12 * something)=109. 12* something=21. So something=1.75. Can we make 1.75 from remaining numbers:4,7,1,2,5,21. 7/4=1.75. So 88 +12*(7/4)=88 +21=109. Wait, this uses 88,12,7,4. Then remaining numbers:1,2,5,21. But wait, we still have to use all numbers. So how?\n\nWait, let's write it out: 88 + 12*(7/4) = 88 + 21 =109. Now, we've used 88,12,7,4. Remaining numbers:1,2,5,21. Need to incorporate them. If we can do something like [88 + 12*(7/4)] * (21/21) * (5/5) * (2/2) *1, but that uses numbers multiple times. Not allowed.\n\nBut wait, we have to use each number exactly once. So if we do 88 + 12*(7/4) + (21 -21) + (5 -5) + (2 -2) + (1 -1), but again duplicates and not using each once.\n\nWait a second. Wait, the expression 88 + (12 * 7 / 4) = 88 + 21 = 109. This uses 88,12,7,4. Now, what if we multiply by ( (5 - (2 + 1)) / (21 - 21) )? No, division by zero. Bad.\n\nWait, but we still have 1,2,5,21 left. Maybe add zero: 88 + (12 * 7 / 4) + (21 -21) + (5 -5) + (2 -2) + (1 -1). But again, duplicates.\n\nWait, no. Wait, the key insight here is that 12*7/4=21, so if we write it as 88 + (12 * 7 / 4), that uses 88,12,7,4. Then we have 1,2,5,21 left. If we can make the rest of the expression evaluate to 0 using those numbers. For example, 21 - 21 is zero, but we don't have two 21s. Wait, we have one 21. Hmm.\n\nWait, but what if we do 88 + (12 * 7 / 4) + (21 - 21), but we don't have two 21s. Not possible.\n\nWait, but we have a 21 left. So maybe (88 + (12 * 7 / 4)) + ( (5 - 2 - 1) - (21 / 21) ). Wait, 5-2-1=2, 21/21=1, so 2 -1=1. Then total is 109 +1=110. Close, but no.\n\nWait, ((5 - (2 + 1)) * 21) = (2)*21=42. If we subtract that: 109 -42=67. Not helpful.\n\nWait, another idea: Use the remaining numbers to make 1 and multiply. So [88 + (12 * 7 /4)] * ( (5 - (2 + 1)) / 21 ). Compute: 5-3=2, 2/21≈0.095. 109 *0.095≈10.35. Not good.\n\nHmm. Wait, but what if we do 88 + (12 * 7 / 4) + (21 - 21), but we can't. Wait, unless we use 21 in the denominator or something.\n\nWait, here's a thought. If we have to use all numbers, perhaps the expression is:\n\n88 + (12 * 7 / 4) + (21 - 21), but no. Wait, no. Wait, let's count the numbers used:\n\n- 88: used\n\n- 12: used\n\n- 7: used\n\n- 4: used\n\n- 21: used in (21 -21), but we only have one 21. So invalid.\n\nWait, but we have to use each number exactly once. So we can't use 21 twice. So scratch that.\n\nWait, going back to the expression 88 + (12 * 7 / 4) =109. This uses four numbers. We need to use all eight. So we need to involve the other four numbers in a way that doesn't change the value. The only way is to add 0 or multiply by 1.\n\nSo, for example, + (5 -5), but we don't have two 5s. Or * ( (2 + 1) / (2 + 1) ), but we have to use each number once. Wait, we have 1,2,5,21 left. So if we do:\n\n[88 + (12 * 7 / 4)] + ( (5 - 5) * 21 * 1 * 2 ), but again duplicate 5.\n\nWait, no. Let's think: To make 0, we need something like (a - b), where a and b are made from the remaining numbers. But we have four numbers:1,2,5,21. Can we make two equal numbers from them? 21 - (5 + 2 + 1)=13. Not zero. 5*2=10, 21 - (10 +1)=10. Not equal.\n\nWait, (21 - (5*2 +1))=21 -11=10. Not zero.\n\n( (21 / (5 - (2 -1))) ) =21 / (5 -1)=21/4=5.25. Not helpful.\n\nWait, this is really challenging. Maybe the initial idea of 88 +21 is the way to go, and the rest of the numbers need to be used in a fraction that equals 0, but I'm not seeing it.\n\nWait, let's try using all numbers in a long expression. For example:\n\n88 + 21 + 12 - 12 + 7 -7 + 4 -4 +5 -5 +2 -2 +1 -1. But this uses each number twice, which isn't allowed.\n\nWait, but we have to use each once. So maybe:\n\n88 + 21 + (12 - 4 -7 -1 -2 -5). Let's compute the parentheses:12 -4=8, -7=1, -1=0, -2=-2, -5=-7. So total expression:88+21-7=102. Not 109.\n\nClose. 102 vs 109. Off by 7.\n\nWait, 88 +21 + (12 - (4 +7 +1 +2 +5)). Compute inside:4+7+1+2+5=19. 12-19=-7. 88+21-7=102. Same as above.\n\nHmm. What if we do 88 +21 + (something else). Wait, 88 +21 =109. If we can have the rest of the numbers subtract to zero. Wait, 88 +21 + (expression)=109 => expression=0. So need expression=0 using 12,4,7,1,2,5.\n\nWe need to arrange these six numbers with + and - to get zero. Let's see:\n\nLet's try 12 - 4 -7 -1 +2 +5= (12) -4=8-7=1-1=0+2=2+5=7. Not zero.\n\n12 +4 -7 -1 -2 -5= (16) -7=9-1=8-2=6-5=1.\n\n12 - (4 +7 +1 +2 +5)=12 -19=-7.\n\nHow about (12 +5) - (4 +7 +1 +2)=17 -14=3.\n\n(12 +4 +5) - (7 +1 +2)=21 -10=11.\n\n(12 +7 +5) - (4 +1 +2)=24 -7=17.\n\nNot zero. Maybe multiplication/division.\n\n(12 * (5 - (4 + 2))) / (7 -1). Compute: 4+2=6, 5-6=-1, 12*-1=-12. Denominator:6. -12 /6=-2.\n\nNot zero.\n\n( (12 - 7) * (5 - 4) ) - (2 +1)= (5*1) -3=2.\n\nHmm.\n\nWait, what if ( (12 / (4)) * (5 - (2 +1)) ) -7. 12/4=3, 2+1=3, 5-3=2, 3*2=6, 6-7=-1.\n\nClose to zero but not quite.\n\nThis is really tough. Maybe the solution doesn't involve 88 +21 directly.\n\nLet's try a different combination. How about 21*5=105, then 105 + (88 / (12 - (7 + (4 / 2)) )) +1. Wait, let's compute denominator:\n\n4 /2=2. 7 +2=9. 12 -9=3. 88 /3≈29.333. 105 +29.333≈134.333 +1≈135.333. No.\n\nWait, 88 / (12 -7 - (4 /2)) =88 / (5 -2)=88/3≈29.333. Same as above.\n\nAnother idea: 5* (21 - (12 / (4 - (2 / (7 - 1)) ))). Let's parse this.\n\nInnermost:7 -1=6. 2 /6=1/3. 4 -1/3=11/3. 12 / (11/3)=36/11≈3.27. 21 -3.27≈17.73. 5*17.73≈88.65. Not 109.\n\nNot good.\n\nWait, let's think of 109 as 100 +9. We know 88 +12=100. Then need 9 from 7,1,2,5,21,4. Wait, 21 - 12=9, but 12 is used. Hmm. 7 + (5 - (4 - (2 -1)))=7 + (5 - (4 -1))=7 + (5-3)=7+2=9. Yes!\n\nLet's check:\n\nStart with 88 +12 =100.\n\nThen 7 + (5 - (4 - (2 -1)))=7 + (5 - (4 -1))=7 + (5 -3)=7 +2=9.\n\nSo total expression: (88 +12) + (7 + (5 - (4 - (2 -1)))).\n\nLet's verify all numbers used: 88,12,7,5,4,2,1. Wait, what about 21? Oh no, we haven't used 21. Oops, forgot 21.\n\nSo close! So we have to include 21. Hmm. So this uses all except 21. So need to involve 21.\n\nWait, maybe instead of 7 + ..., use 21 - something. Let's see.\n\nWe need total 9. If we do 21 - 12=9, but 12 is already used. Not helpful.\n\nWait, (21 / something). 21 / (7/3)=9, but not sure.\n\nWait, let's recast. We need to use 21. So maybe:\n\n(88 +12) + (21 - 12) =100 +9=109, but duplicate 12.\n\nNot allowed.\n\nWait, another try: 88 + (21 - (12 / ( (7 -5) + (4 / (2 +1)) ))). Let's compute denominator:\n\nFirst, 2 +1=3. 4 /3≈1.333. 7 -5=2. So denominator=2 +1.333≈3.333. 12 /3.333≈3.6. 21 -3.6≈17.4. 88 +17.4≈105.4. Not 109.\n\nNope.\n\nWait, going back to the earlier almost-solution that used all numbers except 21: (88 +12) + (7 + (5 - (4 - (2 -1)))) =100 +9=109. The missing number is 21. So if we can replace the 9 with something that includes 21. Like instead of getting 9 from the other numbers, get 9 +21 -21, but again duplicates.\n\nWait, what if we do (88 +12) + (7 + (5 - (4 - (2 -1)))) + (21 -21). But duplicates.\n\nWait, unless we can integrate 21 into the expression. For example, change the 7 to 21 -14, but we don't have 14.\n\nWait, let's see. The part that made 9 was:7 + (5 - (4 - (2 -1))). If we replace the 7 with 21 - something. Let's say 21 - x, so that 21 -x + (5 - (4 - (2 -1)))=9. Then x=21 + [5 - (4 - (2 -1))] -9=21 + [5 -3] -9=21 +2 -9=14. So x=14. Can we make 14 from remaining numbers? Wait, but we're trying to use all numbers. This might not help.\n\nWait, this is getting too convoluted. Let's try to see if the expression I had before can be adjusted to include 21.\n\nOriginal almost-solution: 88 +12 +7 +5 -4 + (2 -1). Wait, let's compute:\n\n88+12=100, +7=107, +5=112, -4=108, +2=110, -1=109. Hey, that works!\n\nWait, let's verify step by step:\n\nStart with 88.\n\n+12: 100\n\n+7: 107\n\n+5: 112\n\n-4: 108\n\n+2: 110\n\n-1: 109.\n\nYes! And what numbers have we used? 88,12,7,5,4,2,1. Missing number is 21. Oh no! Still missing 21.\n\nAh, so close. We used all numbers except 21. So need to include 21 somehow.\n\nWait, but maybe we can adjust the operations to include 21. For example, instead of +5, do + (21 -16), but we don't have 16.\n\nWait, let's see. The current total without 21 is 109. We need to use 21. So we need to have an expression where 21 is used in a way that doesn't change the total, like multiplying by 21/21 or adding 21-21.\n\nBut we have to use each number once. So:\n\n(88 +12 +7 +5 -4 +2 -1) * (21 /21) =109*1=109. But this uses 21 twice. Not allowed.\n\nAlternatively, (88 +12 +7 + (21 - 16) -4 +2 -1), but we don't have 16.\n\nWait, another idea: Replace one of the numbers with an expression involving 21. For example, instead of +5, do + (21 - 16), but where to get 16. Or maybe:\n\n88 +12 +7 + (21 - 16) -4 +2 -1. Still need 16.\n\nWait, 21 - (4 + 2 + 1 + something)=21 - (7)=14. Not helpful.\n\nWait, let's think differently. What if we do 88 + 21 =109, and then use the other numbers as (12 - 12) etc., but we need to use them all. Wait, but we have to use each number once, so maybe:\n\n88 + 21 + ( (12 - 7 - 5) * (4 - 2 - 1) )\n\nCompute: 12 -7 -5=0. 4 -2 -1=1. 0*1=0. So total=109 +0=109.\n\nHey, this might work!\n\nLet's verify:\n\nNumbers used: 88,21,12,7,5,4,2,1. All exactly once.\n\nExpression: 88 + 21 + ((12 - 7 - 5) * (4 - 2 - 1))\n\nCompute step by step:\n\nFirst, compute (12 -7 -5)=0.\n\nThen (4 -2 -1)=1.\n\nMultiply them:0 *1=0.\n\nAdd to 88 +21:109 +0=109.\n\nYes! This uses all numbers exactly once.\n\nLet me double-check:\n\n- 88: used\n\n- 21: used\n\n- 12: used\n\n- 7: used\n\n- 5: used\n\n- 4: used\n\n- 2: used\n\n- 1: used\n\nAll numbers accounted for. Operations are +, -, *.\n\nPerfect!\n\nSo the expression is 88 + 21 + (12 - 7 - 5) * (4 - 2 - 1).\n\nSimplify the parentheses:\n\n(12 -7 -5) = 0\n\n(4 -2 -1) =1\n\n0 *1 =0\n\n88 +21 +0=109.\n\nYes! This works.\n</think>\n\nTo solve the problem of creating an expression that equals **109** using **all** the numbers **12, 4, 7, 1, 2, 5, 21, 88** exactly once with the operations **+**, **-**, **\\***, and **/**, we proceed by identifying a structure that allows us to use all numbers while keeping the total at 109.\n\n---\n\n### Step-by-Step Reasoning:\n\nWe observe that:\n\n$$\n88 + 21 = 109\n$$\n\nThis gives us a base expression. However, we must also use the remaining numbers: **12, 4, 7, 1, 2, 5**. To include them without changing the value of the expression, we need to construct a **zero** using these numbers.\n\nLet’s define two sub-expressions:\n\n- $ (12 - 7 - 5) = 0 $\n- $ (4 - 2 - 1) = 1 $\n\nThen:\n\n$$\n(12 - 7 - 5) \\times (4 - 2 - 1) = 0 \\times 1 = 0\n$$\n\nAdding this to the original sum:\n\n$$\n88 + 21 + [(12 - 7 - 5) \\times (4 - 2 - 1)] = 109 + 0 = 109\n$$\n\nAll numbers are used exactly once:\n- **88**, **21** used in the main sum\n- **12**, **7**, **5** used in the first parenthesis\n- **4**, **2**, **1** used in the second parenthesis\n\n---\n\n### Final Expression:\n\n$$\n88 + 21 + (12 - 7 - 5) \\times (4 - 2 - 1)\n$$\n\n---\n\n### Verification:\n\n- $ 12 - 7 - 5 = 0 $\n- $ 4 - 2 - 1 = 1 $\n- $ 0 \\times 1 = 0 $\n- $ 88 + 21 + 0 = 109 $\n\nAll numbers are used **exactly once**, and the expression evaluates to **109**.\n\n---\n\n<answer>88 + 21 + (12 - 7 - 5) * (4 - 2 - 1)</answer>",
"Okay, let's see. The user wants me to continue exploring alternative solution strategies for the same problem. The original problem was to use all numbers 12, 4, 7, 1, 2, 5, 21, 88 exactly once with +, -, *, / to make 109. The first solution used 88 + 21 + (12-7-5)*(4-2-1). Now I need to find another way.\n\nHmm, maybe instead of making zero, I can use multiplication or division to adjust the numbers. Let's list all the numbers again: 12, 4, 7, 1, 2, 5, 21, 88. Total eight numbers. Let's think of other combinations.\n\nAnother idea: 88 is a big number. 109 - 88 = 21. Wait, but 21 is already one of the numbers. So 88 + 21 = 109, but we need to use all numbers. So maybe 88 + 21 + something that cancels out. Wait, the first solution did that. But maybe there's a different way to cancel.\n\nAlternatively, maybe use 88 + something else. Let's see: 109 - 88 = 21. So if I can make 21 from the other numbers, but 21 is already a number, so that might not help. Wait, but we need to use all numbers. So perhaps 88 + (some expression using the rest) = 109. So the expression using the rest should equal 21. Let's check: 12,4,7,1,2,5,21. Wait, but 21 is part of the numbers. Wait, the numbers are 12,4,7,1,2,5,21,88. So if we use 88, then the other seven numbers need to combine to 21. But 21 is one of them. So maybe 21 is part of the expression. Wait, the first solution used 21 as part of the sum. Let's see.\n\nAlternatively, maybe 88 + 21 = 109, but we need to use all the other numbers (12,4,7,1,2,5) in a way that doesn't change the sum. So if we can make 0 with those numbers, as before. The first solution used (12-7-5) and (4-2-1), multiplied to get 0. Are there other ways to make 0 with those numbers?\n\nLet's see: 12 - 4 - 7 -1 = 0. Wait, 12 -4=8, 8-7=1, 1-1=0. So (12 -4 -7 -1) = 0. Then we still have 2 and 5 left. So 0 * (something with 2 and 5) = 0. So maybe (12 -4 -7 -1) * (5 - 2) = 0 * 3 = 0. Then 88 +21 + 0 = 109. Let's check all numbers: 88,21,12,4,7,1,5,2. Yes, all used exactly once. So that's another expression.\n\nWait, let's verify:\n\n(12 - 4 -7 -1) = 0\n\n(5 - 2) = 3\n\n0 * 3 = 0\n\n88 +21 +0 = 109.\n\nYes, that works. So the expression would be 88 + 21 + (12 -4 -7 -1) * (5 - 2).\n\nLet's list all numbers used: 88,21,12,4,7,1,5,2. All exactly once. Perfect.\n\nIs this a valid alternative? Let's check.\n\nAnother way: Maybe using division. For example, 88 + (something) = 109. So something = 21. But we need to use all numbers. Wait, 21 is a number, but maybe combine others to make 21. Wait, but we need to use all numbers, so perhaps 88 + (21) + ... but we need to use the others. Hmm.\n\nWait, maybe 88 + 21 is 109, so the rest must sum to zero. So any expression with the other numbers that equals zero. Let's see.\n\nAnother way to get zero: 5 - 2 - 3, but we don't have 3. Wait, 7 - (4 + 1 + 2) = 0? 7 - (4+1+2)=7-7=0. So (7 -4 -1 -2) =0. Then 12 and 5 left. So (7 -4 -1 -2) * (12 -5) =0*7=0. So then 88 +21 +0=109.\n\nNumbers used: 88,21,7,4,1,2,12,5. All used once. That's another way.\n\nSo expression: 88 +21 + (7 -4 -1 -2) * (12 -5).\n\nCheck:\n\n7-4-1-2=0\n\n12-5=7\n\n0*7=0\n\n88+21=109.\n\nYes, that works too.\n\nSo that's a third alternative.\n\nWait, but the user asked for alternative strategies, so maybe these are valid. Let's check if these are different from the first solution.\n\nFirst solution used (12-7-5) * (4-2-1).\n\nThis new one uses (7-4-1-2) * (12-5).\n\nYes, different grouping.\n\nAnother idea: Maybe using multiplication or division to get a non-zero contribution. For example, 88 + something = 109, but the something is not 21. Wait, 109 -88=21, so the something must be 21, but if we can't use 21 directly, but need to make 21 from other numbers. Wait, but 21 is already one of the numbers, so maybe we can use 21 as part of a different operation.\n\nWait, for example, 88 + (21 * something) where something is 1, but that would be 88 +21=109. But then we still need to use the other numbers. So again, the other numbers need to form 1. Wait, but 21*1=21, but then 88 +21*1=109. But then the other numbers need to equal 1. Let's see: can we make 1 from 12,4,7,1,2,5? Wait, but 1 is already a number. So maybe (12 -7 -5) * (4 -2) +1. Wait, but this is getting complicated.\n\nWait, let's think: 88 + 21 * (some expression that equals 1). So 21 *1 =21, so 88 +21=109. Then the expression for 1 should use the remaining numbers: 12,4,7,1,2,5. Wait, but 1 is already a number. So perhaps ( (12 -7 -5) + (4 -2 -1) ) but that's 0 +1=1. Wait, but that's similar to before. Wait, but if we do 21 * [ (12 -7 -5) + (4 -2 -1) ] =21*(0 +1)=21*1=21. Then 88 +21=109. So the full expression would be 88 +21*( (12 -7 -5) + (4 -2 -1) ). Let's check numbers:\n\n88,21,12,7,5,4,2,1. All used once. Let's compute:\n\n12-7-5=0\n\n4-2-1=1\n\n0 +1=1\n\n21*1=21\n\n88+21=109.\n\nYes, that's another valid expression.\n\nSo this is a different structure: multiplication by 21 instead of adding 21. So this is another alternative.\n\nLet's verify all numbers are used: 88,21,12,7,5,4,2,1. Yes, all exactly once.\n\nSo this is a third alternative.\n\nAnother approach: Maybe using division. Let's see. For example, 88 + (something) =109, so something=21. But maybe 21 can be formed via division. Like 42/2=21, but 42 is not a number here. Wait, numbers are 12,4,7,1,2,5,21,88. Let's see: 21 is already there, so maybe 21* (some fraction). Wait, but we need to use all numbers.\n\nWait, another idea: 88 + (21 * (5 - (12 / (7 - (4 - 1)) / 2)))... Hmm, this might get too complicated. Let's check if it's possible.\n\nWait, maybe 12 / something. Let's try to find another way.\n\nWait, let's consider 88 + 21 = 109. So we need to use the other numbers to make 0. So any way to make 0 with 12,4,7,1,2,5. Let's list all possible combinations.\n\nPossible zero expressions:\n\n- 12 - 7 -5 =0, then 4 -2 -1=1, multiply to get 0. (First solution)\n- 12 -4 -7 -1=0, then 5-2=3, multiply to get 0. (Second solution)\n- 7 -4 -1 -2=0, then 12-5=7, multiply to get 0. (Third solution)\n- 5 - (4 + 1) =0, then 12 -7 -2=3, multiply 0*3=0. So (5 -4 -1) * (12 -7 -2) =0*3=0. Then 88+21+0=109. Let's check numbers: 88,21,5,4,1,12,7,2. All used once. Yes.\n\nSo (5 -4 -1) * (12 -7 -2) =0*3=0. So expression: 88 +21 + (5 -4 -1)*(12 -7 -2).\n\nThat's another valid expression.\n\nSo this is a fourth alternative.\n\nLet's verify:\n\n5-4-1=0\n\n12-7-2=3\n\n0*3=0\n\n88+21=109.\n\nYes, correct.\n\nSo there are multiple ways to make the zero using different groupings of the numbers. All of these are valid and use all numbers exactly once.\n\nAnother way: 2*1=2, 4-2=2, but not sure. Wait, maybe (2*1) - (4 - (12 -7 -5)). Let's see:\n\nWait, perhaps not helpful. Let's stick to the zero method.\n\nAnother zero expression: 12 - (7 + 5) =0, and 4 - (2 +1)=1. So same as first solution.\n\nAlternatively, 12 - (5 +7) =0, and (4 -2) -1=1. Same as before.\n\nSo it seems all these variations are based on grouping the numbers to make zero. Since the problem requires using all numbers exactly once, and we need to get 109, which is 88+21, the key is to use the remaining numbers to create a zero.\n\nAnother way to make zero: (12 / (4 + 2)) - (7 -5 -1). Let's compute:\n\n4+2=6, 12/6=2\n\n7-5-1=1\n\n2-1=1. Not zero.\n\nHmm. Not helpful.\n\nHow about (12 - (7 + 5)) * (4 - (2 + 1)) =0*1=0. Which is the same as the first solution.\n\nSo that's the same as before.\n\nAlternatively, ( (12 -7) -5 ) * ( (4 -2) -1 ) = (5-5)*(2-1)=0*1=0. Same thing.\n\nSo all these are variations of the same structure.\n\nAnother possible structure: Maybe not using 88 +21, but using a different combination. Let's see.\n\nSuppose we don't use 88 and 21 as separate numbers. Let's say we use 88 + something else.\n\nWhat's 109 -88=21. So we need the rest to add up to 21. Wait, but 21 is a number, so maybe 88 +21=109. If we use 21 as part of the expression, but perhaps in a different way. Wait, but the numbers must be used once, so 21 is either added, subtracted, multiplied, etc.\n\nWait, what if we do 88 + (21 * (something)) where something is 1. But as before, something would need to be made from other numbers.\n\nWait, 21 * 1 =21, so 88 +21*1=109. Then the 1 can be made from other numbers. But 1 is already a number, so perhaps (21 * 1) +88. But then we still need to use 12,4,7,2,5. So to make the other numbers cancel out. For example, 12 -7 -5=0, 4 -2=2, so 0*2=0. So 88 +21*1 + (12-7-5)*(4-2)=109+0=109.\n\nWait, let's check:\n\nNumbers used: 88,21,1,12,7,5,4,2. All present.\n\nExpression: 88 + 21 * 1 + (12 -7 -5) * (4 -2)\n\nCompute:\n\n12-7-5=0\n\n4-2=2\n\n0*2=0\n\n21*1=21\n\n88+21+0=109.\n\nYes, this works. This is similar to the earlier solution but structured differently. Here, the multiplication by 1 is explicit, and the zero term is multiplied by (4-2).\n\nSo this is another alternative expression.\n\nAnother possibility: Maybe using division. For example, 5 / (1) =5, but not sure. Let's see.\n\nWait, let's think of 88 + 21 = 109. So if we can use the other numbers to form 0, but perhaps using division. For example, (12 / 12) but we don't have 12 twice. Wait, no.\n\nWait, 4 / 2 =2, 7 -5=2, then 2 -2=0. So (4/2) - (7-5)=2-2=0. Then multiply by something. Wait, so ( (4/2) - (7-5) ) * (12 -1) =0*11=0. Then 88 +21 +0=109.\n\nCheck numbers: 88,21,4,2,7,5,12,1. All used once.\n\nYes, that's another valid expression.\n\nLet's verify:\n\n4/2 =2\n\n7-5=2\n\n2-2=0\n\n12-1=11\n\n0*11=0\n\n88+21=109.\n\nPerfect. So expression: 88 + 21 + ((4 / 2) - (7 - 5)) * (12 - 1)\n\nThis uses all numbers exactly once.\n\nSo this is a fifth alternative.\n\nThis uses division and subtraction to create the zero.\n\nAnother way: ((12 - 4) / 2) - (7 - 5) = (8/2) -2=4-2=2. Not zero. Hmm.\n\nWait, let's try ( (12 - 5) -7 ) * (4 -2 -1). 12-5=7, 7-7=0. 4-2-1=1. 0*1=0. So same as first solution.\n\nSo, it seems there are multiple ways to structure the zero term. The key is to find different groupings of the numbers that result in zero when combined with multiplication or addition.\n\nLet's try to see if there's a way that doesn't rely on making zero. For example, maybe 88 + 21 =109, but instead of adding zero, perhaps using the other numbers in a way that contributes to the sum. Wait, but 88 +21 is exactly 109, so any other numbers must cancel out. So the other numbers must sum to zero, which is why the zero approach is necessary.\n\nAlternatively, maybe a different combination. Let's see: 109 is the target. Let's think of other combinations.\n\nWhat's 21 * 5 =105. Then 105 +4=109. So 21*5 +4=109. Then we need to use the remaining numbers:12,7,1,2,88. Wait, but 88 is still there. 88 is a big number. 105+4=109, but 88 is left. So that doesn't work. Unless we do 21*5 +4 + (88 -88), but we can't use 88 twice.\n\nWait, maybe 21*5 =105, 105 + (88 / something) =109. 109-105=4. So 88 / x =4 → x=22. Can we make 22 from the remaining numbers:12,7,1,2. 12+7+2+1=22. Yes. So 21*5 + (88 / (12+7+2+1)) =105 + (88/22)=105+4=109.\n\nLet's check:\n\nNumbers used: 21,5,88,12,7,2,1. Wait, missing the number 4. Oh, we have to use 4 as well. The numbers are 12,4,7,1,2,5,21,88. So in this case, we're using 21,5,88,12,7,2,1, but missing 4. So we need to include 4. Hmm.\n\nWait, 88 / (12 +7 +2 +1 -4) =88/(22-4)=88/18≈4.888, which is not 4. Not helpful.\n\nAlternatively, adjust the denominator to include 4. Let's see: 12+7+2+1+4=26. 88/26≈3.38, not helpful.\n\nWait, maybe 88 / (something) =4, so something=22. To get 22 from 12,7,1,2,4. Let's see: 12+7+2+1=22, but 4 is left. So 12+7+2+1=22, then 4 is unused. So we need to include 4. So maybe (12+7+2+1) -4=18. 88/18 is not 4. Not helpful.\n\nAlternatively, (12+7+2) + (4-1)=21+3=24. 88/24≈3.666. No.\n\nHmm. Maybe this approach isn't working. Let's try another.\n\nWhat about 12 * 9 =108, close to 109. But we don't have 9. 12* (8 +1)=108. Wait, but let's see. 12*8=96, 96+13=109. Not sure.\n\nAlternatively, 88 + 12 + 7 + 2 =109. Let's compute: 88+12=100, +7=107, +2=109. Then we have used 88,12,7,2. Remaining numbers:4,1,5,21. Need to use them. So 109 + (4-4) etc. But we can't add zero unless we make it from remaining numbers. Wait, 4,1,5,21. To make zero: 21 -5 -4 -1=11. Not zero. 21 - (5+4+1)=11. Not helpful.\n\nAlternatively, 88 +12 +7 +2 + (21 -21)=109, but we can't use 21 twice.\n\nHmm. This path doesn't seem to work.\n\nAnother idea: 21 * 5 =105. 105 + 4 =109. Then we need to use 88,12,7,1,2. Let's see: 88 is large. Maybe 88 - (12 +7 +1 +2)=88-22=66. Then 105+4+66=175. Too big. Not helpful.\n\nWait, if we do 21*5 +4 + (88 -88), but again, can't use 88 twice.\n\nAlternatively, 21*5 + (88 / (12 - (7 + 1 + 2))) =105 + (88 / (12 -10))=105 + (88/2)=105+44=149. Too big.\n\nNot helpful.\n\nLet's go back to the zero approach, as it seems the most viable.\n\nAnother way to make zero: (7 - (4 + 2 + 1)) * (12 -5) = (7-7)*(7)=0*7=0. Which is the third alternative I thought of earlier.\n\nYes, that's the same as before.\n\nSo, given that multiple solutions exist based on creating a zero with the remaining numbers, and the user asked for alternative strategies, I can list several of these.\n\nThe key is to find different groupings of the numbers 12,4,7,1,2,5 to form zero via multiplication or addition/subtraction.\n\nLet's formalize some of the alternatives:\n\n1. **First Solution (Given):** \n $ 88 + 21 + (12 - 7 - 5) \\times (4 - 2 - 1) $\n\n2. **Alternative 1:** \n $ 88 + 21 + (12 - 4 - 7 - 1) \\times (5 - 2) $\n\n3. **Alternative 2:** \n $ 88 + 21 + (7 - 4 - 1 - 2) \\times (12 - 5) $\n\n4. **Alternative 3:** \n $ 88 + 21 + (5 - 4 - 1) \\times (12 - 7 - 2) $\n\n5. **Alternative 4:** \n $ 88 + 21 \\times 1 + (12 - 7 - 5) \\times (4 - 2) $\n\n6. **Alternative 5:** \n $ 88 + 21 + \\left( \\frac{4}{2} - (7 - 5) \\right) \\times (12 - 1) $\n\nEach of these uses all numbers exactly once and evaluates to 109.\n\nLet's verify one of the new ones, say Alternative 5:\n\n$ \\frac{4}{2} = 2 $, $ 7 - 5 = 2 $, so $ 2 - 2 = 0 $. Then $ 12 - 1 = 11 $. $ 0 \\times 11 = 0 $. $ 88 + 21 + 0 = 109 $. All numbers used: 88,21,4,2,7,5,12,1. Correct.\n\nAnother check for Alternative 4:\n\n$ 21 \\times 1 =21 $, $ 12-7-5=0 $, $ 4-2=2 $, $ 0 \\times 2=0 $. So $ 88 +21 +0=109 $. Numbers used: 88,21,1,12,7,5,4,2. Correct.\n\nSo all these alternatives are valid.\n\nThe user asked to \"continue exploring alternative solution strategies,\" so providing a few more of these would be appropriate.\n\nAnother possible alternative: Using division in the zero term.\n\nFor example, $ (12 / (7 - 5)) - (4 + 2) = (12/2) -6=6-6=0 $. Then multiply by 1 to keep it zero. So:\n\n$ 88 + 21 + \\left( \\frac{12}{7 - 5} - (4 + 2) \\right) \\times 1 $\n\nCheck:\n\n7-5=2, 12/2=6, 4+2=6, 6-6=0. 0*1=0. 88+21=109.\n\nNumbers used: 88,21,12,7,5,4,2,1. All present. Perfect.\n\nSo this is another valid expression.\n\nExpression: $ 88 + 21 + \\left( \\frac{12}{7 - 5} - 4 - 2 \\right) \\times 1 $\n\nThis uses division in the zero term, which is a different strategy.\n\nYes, this works. So now we have a sixth alternative.\n\nLet's confirm the numbers:\n\n- 88, 21, 12, 7, 5, 4, 2, 1. All used exactly once.\n\nComputation:\n\n7-5=2\n\n12/2=6\n\n4+2=6\n\n6-6=0\n\n0*1=0\n\n88+21+0=109.\n\nPerfect.\n\nSo this is a valid alternative that uses division in the zero expression.\n\nTherefore, there are multiple valid expressions, all based on making zero from the remaining numbers using different arithmetic operations.\n</think>\n\nTo solve the problem of forming an expression equal to **109** using **all** the numbers **12, 4, 7, 1, 2, 5, 21, 88** exactly once with the operations **+**, **-**, **\\***, and **/**, we can explore multiple valid strategies that all rely on the core idea of **constructing a zero** using the remaining numbers after identifying the base sum (88 + 21 = 109). This ensures the total remains unchanged while incorporating all numbers.\n\n---\n\n### ✅ **Alternative Strategy 1: Using Division in Zero Construction**\n\nWe construct a zero using division and subtraction:\n\n$$\n\\left( \\frac{12}{7 - 5} - (4 + 2) \\right) \\times 1\n$$\n\n- $ 7 - 5 = 2 $\n- $ \\frac{12}{2} = 6 $\n- $ 4 + 2 = 6 $\n- $ 6 - 6 = 0 $\n- $ 0 \\times 1 = 0 $\n\nNow add this to the base sum:\n\n$$\n88 + 21 + \\left( \\frac{12}{7 - 5} - (4 + 2) \\right) \\times 1 = 88 + 21 + 0 = 109\n$$\n\nAll numbers used exactly once:\n- **88**, **21**, **12**, **7**, **5**, **4**, **2**, **1**\n\n---\n\n### ✅ **Alternative Strategy 2: Grouping Numbers to Form Zero**\n\nUse a different grouping of the remaining numbers:\n\n$$\n(12 - 4 - 7 - 1) \\times (5 - 2)\n$$\n\n- $ 12 - 4 - 7 - 1 = 0 $\n- $ 5 - 2 = 3 $\n- $ 0 \\times 3 = 0 $\n\nAdd to the base sum:\n\n$$\n88 + 21 + (12 - 4 - 7 - 1) \\times (5 - 2) = 88 + 21 + 0 = 109\n$$\n\nAll numbers used exactly once:\n- **88**, **21**, **12**, **4**, **7**, **1**, **5**, **2**\n\n---\n\n### ✅ **Alternative Strategy 3: Using Multiplication of Two Zeros**\n\n$$\n(7 - 4 - 1 - 2) \\times (12 - 5)\n$$\n\n- $ 7 - 4 - 1 - 2 = 0 $\n- $ 12 - 5 = 7 $\n- $ 0 \\times 7 = 0 $\n\nAdd to the base sum:\n\n$$\n88 + 21 + (7 - 4 - 1 - 2) \\times (12 - 5) = 88 + 21 + 0 = 109\n$$\n\nAll numbers used exactly once:\n- **88**, **21**, **7**, **4**, **1**, **2**, **12**, **5**\n\n---\n\n### ✅ **Alternative Strategy 4: Multiplying by 1**\n\n$$\n88 + 21 \\times 1 + (12 - 7 - 5) \\times (4 - 2)\n$$\n\n- $ 12 - 7 - 5 = 0 $\n- $ 4 - 2 = 2 $\n- $ 0 \\times 2 = 0 $\n- $ 21 \\times 1 = 21 $\n\nAdd to the base:\n\n$$\n88 + 21 + 0 = 109\n$$\n\nAll numbers used exactly once:\n- **88**, **21**, **1**, **12**, **7**, **5**, **4**, **2**\n\n---\n\n### ✅ **Alternative Strategy 5: Using Parentheses and Subtraction**\n\n$$\n88 + 21 + \\left( \\frac{4}{2} - (7 - 5) \\right) \\times (12 - 1)\n$$\n\n- $ \\frac{4}{2} = 2 $\n- $ 7 - 5 = 2 $\n- $ 2 - 2 = 0 $\n- $ 12 - 1 = 11 $\n- $ 0 \\times 11 = 0 $\n\nAdd to the base:\n\n$$\n88 + 21 + 0 = 109\n$$\n\nAll numbers used exactly once:\n- **88**, **21**, **4**, **2**, **7**, **5**, **12**, **1**\n\n---\n\n### ✅ Final Answer (One of the Valid Alternatives)\n\n<answer>88 + 21 + (12 - 4 - 7 - 1) * (5 - 2)</answer>",
"Okay, let's tackle this problem again to find more alternative expressions that equal 109 using all the numbers 12, 4, 7, 1, 2, 5, 21, 88 exactly once. The previous solutions all used the base 88 + 21 = 109 and added a zero constructed from the remaining numbers. Maybe there's another way to approach this without starting with 88 + 21. Let's see.\n\nFirst, let's list all the numbers: 12, 4, 7, 1, 2, 5, 21, 88. We need to combine them with +, -, *, / to get 109. Let's consider if there's a different base sum or maybe a product that gets us close to 109.\n\nFor example, 88 is a large number, so maybe 88 plus something else. 88 + 21 is 109, which we've used. What if we do 88 + 20 = 108, but we need 109. Not sure. Let's check other combinations.\n\nAnother thought: 21 * 5 = 105. Then 105 + 4 = 109. So 21*5 + 4 = 109. Now we have to use the remaining numbers: 12, 7, 1, 2, 88. Wait, but we need to use all numbers. So if we do 21*5 + 4, that's using 21,5,4. Then we need to incorporate 12,7,1,2,88. But 88 is a big number, so maybe 88 - something? Wait, 88 is already a large number, so maybe subtract a number to get to 109? Wait, 88 is less than 109, so 88 + 21 is the obvious way. Let's stick to that for now.\n\nWait, but the problem is that 88 + 21 = 109, so we need to use the rest of the numbers in a way that doesn't change the value. So the key is to make a term that equals 0 using the other numbers. Let's confirm the remaining numbers after using 88 and 21: 12,4,7,1,2,5. So we need to make 0 with those six numbers.\n\nWe can try different ways to make 0. For example:\n\n- (12 - 7 - 5) = 0, and then (4 - 2 - 1) = 1, so 0 * 1 = 0. That's the first solution.\n\nAnother way: (12 - 4 - 7 - 1) = 0, and (5 - 2) = 3, so 0 * 3 = 0.\n\nAnother way: (7 - 4 - 1 - 2) = 0, and (12 - 5) = 7, so 0 * 7 = 0.\n\nWhat if we use division? Like (12 / (7 - 5)) - (4 + 2) = (12/2) - 6 = 6 - 6 = 0, then multiply by 1. So ( (12/(7-5)) - (4+2) ) * 1 = 0.\n\nAlternatively, (5 - 2 - 1) = 2, (12 - 7 - 4) = 1, but 2 * 1 = 2, which isn't zero. Wait, no, we need zero.\n\nWait, let's try another combination. Maybe (12 + 5 - 7 - 4 - 2 - 1) = 12+5=17, 7+4+2+1=14, 17-14=3. Not zero.\n\n(12 - 5) = 7, (7 - 4 - 2 - 1) = 0, so 7 * 0 = 0. Wait, that's similar to the earlier strategy. Let's see: (12 - 5) * (7 - 4 - 2 - 1) = 7 * 0 = 0. Then add to 88 + 21.\n\nYes, that's another way. So (12 - 5) * (7 - 4 - 2 - 1) = 7 * 0 = 0. So the expression would be 88 + 21 + (12 - 5) * (7 - 4 - 2 - 1).\n\nLet's check numbers used: 88,21,12,5,7,4,2,1. All used exactly once. Perfect.\n\nLet's verify:\n\n12 -5 =7\n\n7 -4 -2 -1 = 0\n\n7 * 0 = 0\n\n88 +21 +0 = 109. Correct.\n\nAnother possibility: (4 * 2) - (12 - 7 - 5 - 1). Let's compute:\n\n4*2=8\n\n12 -7 -5 -1= -1\n\nSo 8 - (-1)=9. Not zero.\n\nHmm. Maybe (12 - 7) =5, (5 - 2)=3, (4 - 1)=3. 5*3*3=45. Not helpful.\n\nWait, let's think of other ways to get zero. For example, (21 - 21), but we can't use 21 twice. We already used 21 in the base sum. Wait, no, the base sum is 88+21, so 21 is already used, so we can't use it again.\n\nWait, all numbers must be used exactly once, so 21 is part of the base sum, so the remaining numbers are the other six. So we can't use 21 again.\n\nAnother idea: using division to create a zero. Like (something / something) - (something). For example, (12 / 6) - 2 = 0, but we don't have 6. Wait, 7 -1 =6. Let's see:\n\n(12 / (7 - 1)) - (5 - (4 - 2)). Let's compute:\n\n7-1=6, 12/6=2\n\n4-2=2, 5-2=3\n\nSo 2 -3 = -1. Not zero.\n\nAlternatively, ( (12 / (7 - 5)) - (4 + 2) ) * 1. As before, 12/(2)=6, 4+2=6, 6-6=0, times 1=0.\n\nThat's the same as Strategy 1 earlier.\n\nWhat if we do (5 * 2) - (12 - 7 - 4 - 1). Let's see:\n\n5*2=10\n\n12-7-4-1=0\n\nSo 10 -0=10. Not zero.\n\nWait, (5*2) - (12 -7 -4 -1) =10 -0=10. So if we have 88 +21 + (5*2 - (12-7-4-1)) -10, but that's not helpful.\n\nWait, no, we need to use all numbers once. So 5*2 is using 5 and 2, 12-7-4-1 uses 12,7,4,1. Then we have 88 and 21 left. So 88 +21 + (5*2 - (12-7-4-1)) = 109 + (10 -0) = 119. Too big.\n\nNot helpful.\n\nLet's try another approach. Maybe using multiplication and division to reach 109 without starting with 88+21.\n\nFor example, 88 + 21 =109, but what if we do 88 + (21 * something). Wait, 21*5=105, 88+105=193, too big. 21*4=84, 88+84=172. No. 21*1=21, 88+21=109, which is the original base.\n\nHow about 12 * 9 = 108, close to 109. But where to get 9? 7 + 2 =9. So 12*(7+2)=108. Then 108 +1=109. Now we have 12,7,2,1 used. Remaining numbers: 4,5,21,88. Need to use all. So 12*(7+2) +1 + (88 -21 -5 -4). Let's compute:\n\n88-21=67, 67-5=62, 62-4=58. So 108 +1 +58=167. Not 109.\n\nAlternatively, 12*(7+2) +1 = 109. So we need the rest (4,5,21,88) to cancel out. So 12*(7+2) +1 + (something that equals zero using 4,5,21,88). But 4,5,21,88 are all positive and large. How to make zero? Maybe 88 -21 -5 -4=58, which is not zero. So that approach doesn't work.\n\nAnother idea: 21 * 5 = 105. 105 + 4 = 109. So 21*5 +4. Then need to use 12,7,1,2,88. So 21*5 +4 + (88 - 88) + ... but we can't repeat 88. Wait, we have to use all numbers once. So 21*5 +4 uses 21,5,4. Then we have 12,7,1,2,88 left. So we need to make 0 with those. For example, 88 - (12 +7 +1 +2) =88 -22=66. Not zero. 88 - 12*7 +1 +2=88-84+3=7. Not zero.\n\nAlternatively, 88 - (12*7) =88-84=4. Then 4 +1 +2=7. So 21*5 +4 + (88 -12*7 +1 +2) =105+4+7=116. Not 109.\n\nHmm. Maybe 88 is a key number. Let's consider 88 as part of a product. For example, 88 + (something) =109. So something=21, which is the original base.\n\nAnother angle: Maybe use subtraction. Like 88 + 50 =138, too big. 88 + 21=109, as before.\n\nWait, let's think of fractions. Suppose we do 88 + (21 * (something)) but that might not help. Wait, 21 * (5 - (12/4)) =21*(5-3)=21*2=42. Then 88 +42=130. Not helpful.\n\nWait, 12/4=3. Then 7-3=4. 5-1=4. So 4*4=16. Not sure.\n\nWait, let's try a different base. What if we take 21 * 5 =105, then 105 + 4=109. Then we need to use 12,7,1,2,88 in a way that adds zero. So 105 +4 + (88 - 88) + ... but can't repeat. Wait, we have to use 12,7,1,2. So maybe (88 - 88) but no. Wait, 88 is already used in the expression? Wait, no, if we use 21*5 +4, we haven't used 88 yet. So the full expression would be 21*5 +4 + (88 - something). Wait, 21*5=105, 105+4=109. So we need to add zero using 88 and the rest. But 88 is a large number. So 109 + (88 -88) but we can't use 88 twice. So maybe 21*5 +4 + (88 - (12 +7 +1 +2)). Let's compute:\n\n12+7+1+2=22. So 88-22=66. Then 105+4+66=175. Not 109.\n\nAlternatively, 21*5 +4 + (12 -7 -1 -2) -88. That would be 105+4+2 -88=23. Not 109.\n\nNot helpful.\n\nLet's go back to the original idea. The safest way is to have 88 +21 =109, and then make a zero with the other numbers. Let's find all possible ways to make zero with 12,4,7,1,2,5.\n\nPossible combinations for zero:\n\n1. (12 -7 -5) * (4 -2 -1) =0*1=0\n\n2. (12 -4 -7 -1) * (5 -2)=0*3=0\n\n3. (7 -4 -1 -2) * (12 -5)=0*7=0\n\n4. (12 / (7 -5)) - (4 +2) =6-6=0, then *1=0\n\n5. (12 -5) * (7 -4 -2 -1)=7*0=0\n\n6. (5 -2 -1) * (12 -7 -4)=2*1=2 (not zero)\n\n7. (12 -7) - (5 - (4 -2 -1))=5 - (5 - (1))=5-4=1 (not zero)\n\n8. (4*2) - (12 -7 -5 +1)=8 - (12-7=5; 5-5=0; 0+1=1; 8-1=7) Not zero.\n\nSo the valid ones are 1,2,3,4,5.\n\nWait, let's check if there's another way. For example, (5*2) - (12 -7 -4 -1)=10 -0=10, which is not zero, but if we do (5*2) - (12 -7 -4 -1) -10=0, but we can't introduce 10.\n\nAnother way: ((12 - 5) - (7 - 4)) * (2 -1). Let's compute:\n\n12-5=7, 7-4=3, 7-3=4. 2-1=1. 4*1=4. Not zero.\n\nHmm. Let's confirm the fifth way: (12 -5) * (7 -4 -2 -1). 12-5=7, 7-4=3, 3-2=1, 1-1=0. So 7*0=0. Yes, that's valid.\n\nSo that's another expression: 88 + 21 + (12 -5) * (7 -4 -2 -1)\n\nLet's write it out: 88 + 21 + (12 - 5) * (7 - 4 - 2 - 1)\n\nNumbers used: 88,21,12,5,7,4,2,1. All exactly once.\n\nAnother possibility: (21 - (12 - 7 - 5 - 4 + 1)) * something. Wait, let's compute inside: 12-7=5, 5-5=0, 0-4=-4, -4+1=-3. So 21 - (-3)=24. Not helpful.\n\nWait, maybe using division in the zero. For example, ( (12 / (5 - 1)) - (7 - 4) ) * 2. Let's see:\n\n5-1=4, 12/4=3. 7-4=3. 3-3=0. 0*2=0. So that's a way to make zero: (12/(5-1) - (7-4)) *2 =0.\n\nLet's verify:\n\n5-1=4\n\n12/4=3\n\n7-4=3\n\n3-3=0\n\n0*2=0\n\nSo the expression would be 88 +21 + (12/(5-1) - (7-4)) *2\n\nCheck numbers used: 88,21,12,5,1,7,4,2. All exactly once.\n\nYes! This is another valid solution.\n\nLet's verify step by step:\n\n- 5 - 1 = 4\n\n- 12 / 4 = 3\n\n- 7 - 4 = 3\n\n- 3 - 3 = 0\n\n- 0 * 2 = 0\n\n- 88 + 21 + 0 = 109\n\nPerfect. All numbers used exactly once.\n\nThis is a new alternative strategy. Let's check if this uses all numbers:\n\n- 88: yes\n\n- 21: yes\n\n- 12: yes\n\n- 5: yes\n\n- 1: yes\n\n- 7: yes\n\n- 4: yes\n\n- 2: yes\n\nAll accounted for.\n\nSo this is a valid alternative.\n\nAnother way: ( (7 * 2) - 12 ) * (5 - (4 + 1)) \n\nCompute:\n\n7*2=14, 14-12=2\n\n4+1=5, 5-5=0\n\n2*0=0\n\nThen 88 +21 +0=109.\n\nNumbers used: 7,2,12,5,4,1. Wait, 5 - (4+1) uses 5,4,1. So all numbers: 88,21,7,2,12,5,4,1. All used once.\n\nYes! Let's verify:\n\n- 7*2 =14\n\n- 14 -12=2\n\n- 4+1=5\n\n- 5-5=0 (wait, 5 - (4+1)=5-5=0)\n\n- 2*0=0\n\n- 88+21+0=109\n\nYes, this works.\n\nSo the expression is 88 + 21 + ( (7 * 2) - 12 ) * (5 - (4 + 1))\n\nLet's check numbers: 88,21,7,2,12,5,4,1. All present exactly once.\n\nAnother valid solution.\n\nLet's count how many we have now:\n\n1. 88 + 21 + (12 - 7 - 5) * (4 - 2 - 1)\n\n2. 88 + 21 + (12 - 4 - 7 - 1) * (5 - 2)\n\n3. 88 + 21 + (7 - 4 - 1 - 2) * (12 - 5)\n\n4. 88 + 21 + (12 / (7 - 5) - (4 + 2)) * 1\n\n5. 88 + 21 + (12 - 5) * (7 - 4 - 2 - 1)\n\n6. 88 + 21 + (12 / (5 - 1) - (7 - 4)) * 2\n\n7. 88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1))\n\nLet's verify the seventh one:\n\n(7*2 -12) =14-12=2\n\n(5 - (4+1))=5-5=0\n\n2*0=0\n\nYes, that's correct.\n\nIs there a way to use subtraction in the base sum instead? Like 88 + something =109, so something=21, which is already covered.\n\nAnother idea: 88 + 21 + 0 =109, and 0 can be formed in multiple ways. Let's see if there's a way to use division in a different manner.\n\nFor example, ( (12 + 5) - (7 + 4 + 2 + 1) ) =17 -14=3. Not zero.\n\n( (12 + 7) - (5 + 4 + 2 + 1) )=19-12=7. Not zero.\n\n( (5 + 4 + 2) - (12 - 7 + 1) )=11 - (6)=5. Not zero.\n\nHmm. So the main ways are using products of zero with the remaining numbers.\n\nLet's confirm the sixth solution:\n\n88 + 21 + (12 / (5 - 1) - (7 - 4)) * 2\n\nCompute inside the parentheses:\n\n5-1=4\n\n12/4=3\n\n7-4=3\n\n3-3=0\n\n0*2=0\n\nSo total is 88+21+0=109. Correct.\n\nAnother possible variation: 88 + 21 + ( (4 * 2) - (12 - 7 - 5) ) * 1\n\nCompute:\n\n4*2=8\n\n12-7-5=0\n\n8-0=8\n\n8*1=8\n\nSo 88+21+8=117. Not 109. So that's not good.\n\nWait, but if we do ( (12 - 7 - 5) - (4 - 2) ) *1 = (0 -2)*1=-2. Then 88+21-2=107. Not 109.\n\nSo that's bad.\n\nAnother try: ( (5 * 2) - (12 - 7 - 4 - 1) ) =10 -0=10. So 88+21+10=119. Not good.\n\nWait, but if we do 88 + (21 - 10) = 88+11=99, no.\n\nHmm. Let's stick to the valid ones we found.\n\nSo the seventh solution is valid: 88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1))\n\nLet's write it properly with parentheses:\n\n88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1))\n\nYes.\n\nLet's check the numbers again:\n\n- 7, 2, 12 in the first part.\n\n- 5, 4, 1 in the second part.\n\n- 88 and 21.\n\nAll numbers used once.\n\nYes.\n\nAnother possible way: ( (12 - 4) * (7 - 5) ) - (2 + 1) = (8*2) -3=16-3=13. Not zero.\n\nNot helpful.\n\nWait, let's think of another zero. (21 - 21) but can't reuse 21.\n\nNo.\n\nOkay, so the main alternative strategies are the ones we've found, each using a different way to form zero with the six remaining numbers.\n\nLet's list all the valid expressions we have:\n\n1. 88 + 21 + (12 - 7 - 5) * (4 - 2 - 1)\n\n2. 88 + 21 + (12 - 4 - 7 - 1) * (5 - 2)\n\n3. 88 + 21 + (7 - 4 - 1 - 2) * (12 - 5)\n\n4. 88 + 21 + (12 / (7 - 5) - (4 + 2)) * 1\n\n5. 88 + 21 + (12 - 5) * (7 - 4 - 2 - 1)\n\n6. 88 + 21 + (12 / (5 - 1) - (7 - 4)) * 2\n\n7. 88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1))\n\nEach of these uses all numbers exactly once and evaluates to 109.\n\nThe user asked to continue exploring alternative solution strategies, so we can present one more of these as a new alternative.\n\nLet's pick the seventh one as it's a bit different, using multiplication (7*2) and subtraction.\n\nSo the expression is:\n\n88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1))\n\nLet's verify once more:\n\n- 7 * 2 = 14\n\n- 14 - 12 = 2\n\n- 4 + 1 = 5\n\n- 5 - 5 = 0\n\n- 2 * 0 = 0\n\n- 88 + 21 + 0 = 109\n\nAll numbers used: 88, 21, 7, 2, 12, 5, 4, 1. Perfect.\n\nThis is a valid alternative.\n</think>\n\n<answer>88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1))</answer>",
"Okay, let's see. The user wants me to continue exploring alternative strategies to form 109 using all the numbers 12, 4, 7, 1, 2, 5, 21, 88 exactly once. The previous solutions all used 88 + 21 plus a zero constructed from the other numbers. But maybe there's another approach where we don't start with 88 + 21. Let me think.\n\nFirst, let's list all the numbers again: 12, 4, 7, 1, 2, 5, 21, 88. Total of 8 numbers. We need to use each once with +, -, *, /.\n\nAnother idea: Maybe combine some numbers to get close to 109 and then adjust with the rest. Let's see, 88 is the largest number. 88 + 21 is 109, but maybe if we use other combinations. Wait, 88 + 21 is exactly 109, so that's a good base. But maybe the user wants to see different ways to form zero, not just the same pattern.\n\nWait, the previous answer they provided was 88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1)). Let's check that:\n\nFirst, calculate the parts:\n\n7 * 2 = 14. 14 - 12 = 2.\n\nThen, 4 + 1 = 5. 5 - 5 = 0.\n\nSo 2 * 0 = 0. Then 88 + 21 + 0 = 109. All numbers used: 88,21,7,2,12,5,4,1. Yes, all exactly once.\n\nSo that's another way to make zero. The key is to make a product that equals zero. So either one of the factors is zero, or the whole thing is multiplied by zero.\n\nLet me try to find another way. Maybe using division to create a zero. Wait, division by zero is undefined, so we can't have that. So better to have a subtraction that equals zero.\n\nLet's think of other combinations for the zero part. Let's list the remaining numbers after 88 and 21: 12,4,7,1,2,5.\n\nWe need to make zero using these six numbers. Let's try different groupings.\n\nFor example, (12 - 5 - 7) * (4 - 2 - 1). Wait, 12-5-7=0, 4-2-1=1, so 0*1=0. That's the first solution they had.\n\nAnother way: (5 - (4 + 1)) * (7 - (12 / 2)). Let's check: 4+1=5, so 5-5=0. 12/2=6, 7-6=1. So 0*1=0. So that's similar to the one they provided.\n\nWait, the user's last answer was 88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1)). Let's break that down:\n\n(7*2 -12) = 14-12=2\n\n(5 - (4+1)) =5-5=0\n\n2*0=0. So same as before.\n\nSo the zero comes from the second part being zero. So any way to make the second part zero will work.\n\nAnother possibility: (12 - (7 + 5)) * (4 - 2 - 1). 12-12=0, 4-3=1, so 0*1=0. That's another way.\n\nWait, but maybe using division. Let's see. For example, ( (12 / 4) - 3 ) but 3 isn't a number we have. Wait, numbers are 12,4,7,1,2,5. Let's see:\n\nSuppose we do ( (7 + 5) - 12 ) * ( (4 * 2) - 8 ), but 8 isn't in the numbers. Hmm. Wait, maybe not.\n\nAlternatively, ( (5 * 2) - 10 ) * something. 5*2=10, but 10 isn't a number here. Wait, 12 - 2 =10. So (5*2 - (12 - 2)) but that uses 2 twice. Not allowed.\n\nWait, let's think of another zero. Let's say ( (4 * 1) - 4 ), but 4 is used once. No, we can't use 4 twice.\n\nWait, maybe ( (7 - 1) - 6 ), but 6 isn't a number. Hmm.\n\nAlternatively, ( (12 - 5) - 7 ) * (4 - 2 - 1). 12-5=7, 7-7=0. So 0*1=0. So that's (12 -5 -7) * (4 -2 -1) =0*1=0. Which is the same as the first solution.\n\nAnother way: Let's see if we can get zero using division. For example, ( (7 * 2) / 14 - 1 ), but 14 isn't a number. Wait, but 7*2=14, and 14-14=0. But 14 isn't one of our numbers. Wait, but we have 12. 14-12=2. Not helpful.\n\nWait, maybe ( (5 - 2) - 3 ) * something. But 3 isn't there. Hmm.\n\nAlternatively, ( (4 + 1) - 5 ) * (12 - 7 - 2). Let's check: 4+1=5, 5-5=0. 12-7-2=3. So 0*3=0. Yes! So that's another way.\n\nSo the expression would be 88 + 21 + ( (4 + 1) - 5 ) * (12 - 7 - 2 ). Let's verify:\n\n(4+1)=5, 5-5=0.\n\n12-7=5, 5-2=3.\n\n0*3=0.\n\n88+21+0=109.\n\nNumbers used: 88,21,4,1,5,12,7,2. All exactly once. Perfect.\n\nSo this is another valid solution. Let's write that out:\n\n88 + 21 + ((4 + 1) - 5) * (12 - 7 - 2)\n\nLet me check if all numbers are used once:\n\n- 88: yes\n- 21: yes\n- 4: yes\n- 1: yes\n- 5: yes\n- 12: yes\n- 7: yes\n- 2: yes\n\nAll numbers used. Perfect.\n\nAnother one: ( (2 * 5) - 10 ) * something. Wait, 2*5=10. But 10 isn't a number. Wait, but 12 - 2 =10. So (2*5 - (12 - 2)) but that uses 2 twice. Not allowed.\n\nHow about ( (7 + 5) - (12) ) * ( (4 * 1) - 2 ). Let's compute:\n\n7+5=12, 12-12=0.\n\n4*1=4, 4-2=2.\n\n0*2=0. So 88+21+0=109.\n\nNumbers used: 7,5,12,4,1,2. Plus 88 and 21. All good.\n\nSo expression: 88 + 21 + (7 + 5 - 12) * (4 * 1 - 2)\n\nCheck:\n\n7+5-12=0\n\n4*1-2=2\n\n0*2=0\n\n88+21=109. Correct.\n\nNumbers used: 88,21,7,5,12,4,1,2. All exactly once.\n\nThat's another valid expression.\n\nLet me think of another way. Maybe using division in the zero part. For example:\n\n( (12 / (7 - 5)) - (4 + 2) ) * 1. Let's compute:\n\n7-5=2. 12/2=6. 4+2=6. 6-6=0. 0*1=0.\n\nSo expression: 88 + 21 + (12 / (7 - 5) - (4 + 2)) * 1\n\nNumbers used: 88,21,12,7,5,4,2,1. All good.\n\nThis is the same as one of the earlier alternatives I thought of. So this is valid.\n\nAnother idea: What if we use a different base instead of 88 + 21? Let's see if there's a way to get 109 without using 88 + 21 as the main sum. For example, 88 + something else.\n\nSuppose 88 + 20 +1, but 20 and 1. But 20 would need to be made from other numbers. Let's see.\n\nWait, 21 is a number, so 88 + 21 is the closest. Let's check other combinations. Let's say 88 + 5 * something.\n\n88 + 5 * 4 = 88 + 20 = 108. Close to 109, but need to add 1. But then numbers used: 88,5,4,1. Remaining numbers: 12,7,2,21. Not sure.\n\nWait, 88 + 5 * 4 + 1 = 109, but then we need to use 12,7,2,21. How? If we do 88 + 5*4 +1 + (21 - 12 -7 -2). Let's compute that:\n\n21-12=9, 9-7=2, 2-2=0. So total is 88 +20 +1 +0=109.\n\nSo expression: 88 + 5*4 +1 + (21 -12 -7 -2)\n\nCheck numbers:\n\n88,5,4,1,21,12,7,2. All used once.\n\nYes! Let's verify:\n\n5*4=20\n\n20 +1=21\n\n88 +21=109\n\n21-12-7-2=0\n\nSo total: 109 +0=109.\n\nThis is a different structure where the zero is added at the end, but still uses all numbers.\n\nSo the expression would be 88 + 5 * 4 + 1 + (21 - 12 - 7 - 2).\n\nLet me check the operations: multiplication comes before addition, so it's 88 + (5*4) +1 + (21-12-7-2).\n\nYes, that's correct.\n\nThis is a valid solution that doesn't start with 88 +21 as the main sum. Instead, it's 88 + 20 +1 +0 =109.\n\nThis is a good alternative strategy. Let's confirm all numbers are used:\n\n88, 5, 4, 1, 21, 12, 7, 2. All present once. Perfect.\n\nAnother way: Let's see if we can use division. For example, 88 + (21 * (something)) but 21*5=105, 88+105=193 which is too big. Not helpful.\n\nWait, 88 + 21 =109, so maybe another way to get 21 from other numbers? But 21 is one of the given numbers, so we have to use it as is.\n\nWait, no, we have to use each number once, so 21 is a number we must include. So we can't replace 21 with another expression; it has to be used as 21.\n\nWait, but in the previous solution, 21 is used as part of the zero: (21 -12 -7 -2). So 21 is used in the subtraction.\n\nSo in that solution, the 21 isn't added directly but is part of the zero expression.\n\nSo that's a different approach. So the main sum is 88 +5*4 +1, and then the rest form zero.\n\nThis is a different structure than the previous ones, which is good.\n\nLet's check the arithmetic again:\n\n5*4 =20\n\n88 +20 =108\n\n108 +1 =109\n\n21 -12 =9\n\n9 -7=2\n\n2 -2=0\n\nSo total is 109 +0=109. Correct.\n\nSo this is another valid solution.\n\nAnother possibility: 88 + 21 - (something that equals zero). But 88+21 is already 109, so subtracting zero would still give 109. But same as adding zero.\n\nWait, but the key is to use all numbers. So the zero expression has to use the remaining six numbers.\n\nSo the previous examples all use the remaining numbers to make zero.\n\nLet's think of another zero expression. Let's say ( (12 - 5 - 7) * (4 - 2 - 1) ), which is 0*1=0, as before.\n\nOr ( (5 * 2) - (12 - 2) ) but that uses 2 twice. Not allowed.\n\nWait, how about ( (7 - 5) * (4 - 2) ) - (12 / 6). But 6 isn't a number. Hmm.\n\nAlternatively, ( (7 - 5) * (4 - 2) ) * 1 - (12 / 12). But 12/12 would require using 12 twice. Not allowed.\n\nWait, let's think of using all six numbers in a single expression that equals zero. For example:\n\n(12 - 4 - 7 - 1) * (5 - 2) = (0) * (3) =0. Which we've used before.\n\nAnother one: ( (12 + 5) - (7 + 10) ), but 10 isn't a number. Wait, 12+5=17, 7+ (4*2 +1)=7+9=16. Not zero.\n\nWait, maybe ( (4 * 2) + 1 ) - (12 - 7 + 5). Let's compute:\n\n4*2=8 +1=9.\n\n12-7=5 +5=10.\n\n9 -10= -1. Not zero.\n\nHmm. Not helpful.\n\nWait, let's try ( (5 * 4) - 12 ) * ( (7 - 2) - 1 ). Compute:\n\n5*4=20 -12=8.\n\n7-2=5 -1=4.\n\n8*4=32. Not zero.\n\nNot helpful.\n\nHow about ( (7 * 2) - 14 ) * (12 / (5 + 4 + 1)). 14 isn't a number. 7*2=14. 5+4+1=10. 12/10=1.2. So (14-14)=0. Wait, but 14 isn't a number. Wait, 7*2=14, so (7*2 -14) but 14 isn't a number. So we can't write that. But if we use 12, which is close to 14. 7*2=14, 14-12=2. So (7*2 -12)=2. Then multiply by something to get zero. Like (7*2 -12)*(something that is zero). But that's the same as the user's last answer.\n\nSo maybe we're going in circles here.\n\nLet's go back to the solution where we have 88 + 5*4 +1 + (21 -12 -7 -2). That's a good alternative.\n\nAnother one: 21 * 5 = 105. Then 105 + 4 = 109. So 21*5 +4 =109. Then we need to use the remaining numbers: 12,7,1,2,88. Wait, but 88 is a big number. So 21*5 +4 =109, but then we have to incorporate 88, 12,7,1,2. If we do 21*5 +4 + (88 -88) + (12 -12) etc., but we can't reuse numbers. So we need to use all of them. So perhaps:\n\n21*5 +4 + (88 - 88) + ... but no, we can't use 88 twice.\n\nWait, better to use the remaining numbers to form zero. So 21*5 +4 =109, and then the rest (88,12,7,1,2) need to form zero. But 88 is a large number, so maybe 88 - (12 +7 +1 +2)*something. Wait:\n\n88 - (12 +7 +1 +2) =88 -22=66. Not zero.\n\nBut if we do 88 - (12*7 - (1*2)). Let's compute 12*7=84, 1*2=2, 84-2=82. 88-82=6. Not zero.\n\nHmm. Not helpful.\n\nAlternatively, (88 / (12 - (7 + 1 + 2))) * something. 7+1+2=10. 12-10=2. 88/2=44. Not sure.\n\nThis seems more complicated. The original approach of using 88+21 as the base is probably the most straightforward, as 88+21=109.\n\nBut the user wants to explore other strategies, so let's confirm the solution I came up with earlier:\n\n88 + 5*4 + 1 + (21 - 12 - 7 - 2)\n\nLet's write it out with parentheses to ensure order of operations:\n\n88 + (5 * 4) + 1 + (21 - 12 - 7 - 2)\n\nCalculating step by step:\n\n5 * 4 = 20\n\n21 - 12 = 9\n\n9 - 7 = 2\n\n2 - 2 = 0\n\nSo:\n\n88 + 20 + 1 + 0 = 109\n\nYes, correct.\n\nAll numbers used: 88,5,4,1,21,12,7,2. Perfect.\n\nAnother way: 88 + 21 + ( (12 - 7) - 5 ) * (4 + 2 - 1 )\n\nCompute:\n\n12-7=5, 5-5=0.\n\n4+2=6, 6-1=5.\n\n0*5=0.\n\nSo 88+21+0=109.\n\nNumbers used: 88,21,12,7,5,4,2,1. All present.\n\nYes, this is valid.\n\nSo the expression is 88 + 21 + ((12 - 7) - 5) * (4 + 2 - 1)\n\nLet's verify:\n\n(12-7)=5, 5-5=0\n\n(4+2-1)=5\n\n0*5=0\n\n88+21=109.\n\nCorrect.\n\nSo that's another alternative.\n\nI think the key insight is that as long as we can form a zero with the remaining numbers, we can add it to 88+21 without changing the value. And there are multiple ways to form that zero using different groupings of the six remaining numbers.\n\nSo, to recap, the main strategies are:\n\n1. Use 88 + 21 as the base.\n2. Form a zero using the other six numbers with arithmetic operations.\n3. Add the zero to the base sum.\n\nThe user's last answer was one such example. Now, I need to provide another one.\n\nLet's confirm the one I had: 88 + 5*4 + 1 + (21 - 12 - 7 - 2). This is valid.\n\nAnother one: 88 + 21 + ( (5 - (4 + 1)) * (12 - 7 - 2) )\n\nWait, 4+1=5, 5-5=0. 12-7=5-2=3. 0*3=0. So yes, same as before.\n\nBut let's write it as:\n\n88 + 21 + (5 - (4 + 1)) * (12 - 7 - 2)\n\nNumbers used: 88,21,5,4,1,12,7,2. All good.\n\nThis is another valid expression.\n\nI think this is enough. The user wants to see alternative strategies, so providing another valid expression that uses the zero method but with a different grouping should suffice.\n\nLet me pick one that's different from the previous ones. How about:\n\n88 + 21 + ( (12 + 5) - (7 + 10) ), but wait, 10 isn't a number. No.\n\nWait, let's use the earlier one where we have 88 + 5*4 + 1 + (21 - 12 -7 -2). Let's write that out clearly.\n\nFinal Answer:\n\n<answer>88 + 5 * 4 + 1 + (21 - 12 - 7 - 2)</answer>\n</think>\n\n<answer>88 + 5 * 4 + 1 + (21 - 12 - 7 - 2)</answer>"
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"Okay, let's see. I need to use all the numbers 12, 4, 7, 1, 2, 5, 21, 88 exactly once with +, -, *, / to make 109. Hmm, this might take a while. Let me start by listing out the numbers again to make sure I have them all: 12, 4, 7, 1, 2, 5, 21, 88. Eight numbers total. So, I need to combine them with operations to reach 109.\n\nFirst thought: 88 is a big number, maybe it's part of the main addition. If I take 88 and add some other numbers to get close to 109. Let's see, 109 - 88 = 21. Wait, but 21 is one of the numbers. Wait, but if I do 88 + 21, that's 109 already. But then I still have to use all the other numbers: 12, 4, 7, 1, 2, 5. So that's a problem. So 88 + 21 is 109, but I can't just ignore the rest. So maybe 88 + something else equals 109, and then somehow incorporate the other numbers in a way that cancels out or adds zero? Wait, but we have to use all numbers exactly once, so we can't just have 88 + 21 and then do something like *1 or +0, because we have to use the other numbers. Hmm.\n\nWait, maybe 88 plus some combination that equals 21. Wait, but 88 + (some expression with the rest of the numbers) = 109. So the rest of the numbers need to sum to 21. Let's check: total of the other numbers: 12 + 4 + 7 + 1 + 2 + 5 = 31. So 31. But we need 21. So maybe 31 minus something? Wait, but if we have to use all numbers, maybe we need to combine them with operations, not just add. So maybe 88 + (something) = 109, where \"something\" uses the other numbers. Let's think.\n\nAlternatively, maybe multiply some numbers. Let's see. 88 is the largest number. Let's see if we can get 109 by adding 88 to a smaller number. 109 - 88 = 21. But 21 is already a number. Wait, but if we do 88 + 21 = 109, but then we have to use the other numbers. So maybe 88 + 21 + (some expression with the rest that equals 0). But how? For example, (12 - 12), but we don't have two 12s. Wait, we have to use each number once. So maybe something like (12 - 4 - 7 - 1 - 2 - 5) but that would be 12 - 4=8, 8-7=1, 1-1=0, 0-2=-2, -2-5=-7. Not zero. Hmm.\n\nAlternatively, maybe multiply some numbers to get a larger value. Wait, 88 is big. Let's see. Let's think of other combinations. What if we take 88 + 21 = 109, but then we need to use the other numbers in a way that their total effect is zero. But how? Like multiplying by 1 or adding zero. Wait, for example, if we have (88 + 21) * (something that equals 1), but we need to use all numbers. Wait, but we have to use all numbers in the expression. So maybe 88 + 21 + (12 - 12), but again, duplicates. Not allowed.\n\nWait, maybe I need to not use 88 and 21 directly. Let's think differently. Let's consider that 109 is a prime number, so maybe it's a sum of a few larger numbers. Let's see. Let's list all numbers: 88, 21, 12, 7, 5, 4, 2, 1.\n\nAnother idea: 88 + 12 = 100. Then 100 + 9 = 109. How to get 9 from the remaining numbers: 7, 1, 2, 5, 4. Wait, remaining numbers would be 7, 1, 2, 5, 4. Wait, but we need to use all numbers. Wait, if we use 88 + 12, then we have 7,1,2,5,4,21 left. Wait, no, original list is 12,4,7,1,2,5,21,88. So if we use 88 and 12, then the rest are 4,7,1,2,5,21. Hmm. Wait, 88 + 12 = 100. Then 100 + 9 = 109. Let's see if we can make 9 from 21, 4,7,1,2,5. Wait, 21 is a big number. Maybe 21 - 12, but 12 is already used. Hmm.\n\nWait, maybe 88 + 21 = 109. So if we could somehow have 88 + 21 + (some expression that equals 0 using the other numbers). But the problem is that we have to use all numbers in the expression, not just add zero. So maybe (88 + 21) + (12 - 12), but again, duplicate. Not allowed. So that's not the way.\n\nWait, perhaps use division or multiplication. Let's think. For example, 88 + (something) = 109. So something = 21. But 21 is already a number. Wait, but maybe 21 can be formed from other numbers. Wait, but 21 is one of the numbers, so we can't form it again. Wait, no, we have to use all numbers once. So 21 has to be used as is. So if we use 88 and 21, then the rest have to be used in operations that result in 0. Hmm.\n\nWait, here's an idea. Maybe (88 + 21) + (something - something else) where the something and something else use the remaining numbers. Wait, but how? Let's list the remaining numbers: 12, 4, 7, 1, 2, 5. So six numbers. If we can pair them up to subtract to zero. For example, (12 - 12) but again duplicates. Alternatively, (12 - 4 - 7 - 1 + 2 - 5). Let's compute that: 12 -4=8, 8-7=1, 1-1=0, 0+2=2, 2-5=-3. Not zero. Hmm.\n\nWait, maybe multiply some numbers to get 1 so that multiplying by it doesn't change the value. Like (88 + 21) * (something/something else) = 109. But 88 +21=109, so we need something/something else =1. So for example, (12/12), but again duplicates. Wait, but we have 12,4,7,1,2,5. Let's see: (something / something) =1. So 5/5, but we don't have two 5s. 4/4, same problem. Wait, but maybe (12 - 7 - 4 + 1 + 2 - 5). Wait, 12-7=5, 5-4=1, 1+1=2, 2+2=4, 4-5=-1. Not 1. Hmm.\n\nAlternatively, (5 - (4 - (2 - (1)))) = 5 - (4 -1)=5-3=2. Not helpful.\n\nWait, maybe instead of adding 88 and 21, use a different combination. Let's see. Let's try to get close to 109 with other numbers. 21*5=105. Then 105 +4=109. Wait, 21*5=105, +4=109. Then we have used 21,5,4. Remaining numbers: 12,7,1,2,88. Wait, but we still need to use all numbers. So 21*5 +4 =109, but then we have to incorporate 12,7,1,2,88. Hmm, this seems messy. Wait, unless we can do something like (21*5 +4) + (88 - 88), but again duplicates. Not allowed.\n\nWait, another idea: 88 + 21 = 109, as before. If we can use the other numbers in a fraction that equals 0, but we need to use them all. Wait, maybe (88 + 21) + (12 - 12), but no. Wait, perhaps using division. Like 88 + 21 + ( (12 - 12) * ... ), but again, duplicates.\n\nWait, maybe I need to not use 88 and 21 together. Let's try other combinations. How about 12*7=84. Then 84 + something. 84 + 21=105, 105 +4=109. Wait, so 12*7 +21 +4= 84+21=105+4=109. But then we have used 12,7,21,4. Remaining numbers: 1,2,5,88. Need to use them. So how? If we can do (12*7 +21 +4) + (88 -88) but again duplicates. Not good.\n\nWait, but maybe multiply by 1 or add 0. For instance, 12*7 +21 +4 + (5 -5), but no. Wait, remaining numbers are 1,2,5,88. Maybe (88 / (something)) or something. Let's see. If we have 109 = 12*7 +21 +4 + (1*2*5 - 88). Wait, 1*2*5=10, 10 -88= -78. So 84+21+4-78= 109? Let's check: 84+21=105, +4=109, then 109 -78=31. Not 109. Not helpful.\n\nWait, maybe (12*7) + (21 - (88 / (5 - (2 + 1)) )) Hmm, complicated. Let's break it down. 5 - (2 +1)=2. 88 /2=44. Then 21 -44= -23. Then 84 -23=61. Not 109.\n\nHmm. Maybe another approach. Let's think of the total sum of all numbers: 12+4+7+1+2+5+21+88. Let's calculate that. 12+4=16, +7=23, +1=24, +2=26, +5=31, +21=52, +88=140. So total sum is 140. We need 109, which is 31 less than 140. So if we can turn some additions into subtractions to reduce the total by 31. Wait, because each time we subtract instead of add a number, we reduce the total by twice that number. For example, if we have a +b -c instead of +b +c, we reduce by 2c. So total reduction needed is 140 - 109 =31. So we need to find a subset of numbers that sum to 31/2=15.5, but since we can't have half numbers, this approach might not work. Hmm, maybe this method isn't the best.\n\nWait, but maybe it's a different way. Let's see. If we consider that changing a + to a - for a number x reduces the total by 2x. So total reduction needed is 31. So 2x =31? Not possible. So maybe this approach is invalid. Maybe not the right way.\n\nAlternative idea: Let's look for combinations where a multiplication gives a useful number. For example, 21 - 5 =16, 16* something. Or 88 is close to 109. Wait, 88 + 21 =109. So maybe 88 +21 is part of the solution, and then the other numbers have to be used in a way that cancels out. Wait, but how?\n\nWait, here's a thought. If we do 88 + 21 + (12 - 12), but we don't have two 12s. Wait, but maybe use other numbers to make 0. Like (5 - 5), but again duplicates. Wait, but we have all unique numbers. So maybe ( (something) - (something else) ) =0. Let's see. Let's take the remaining numbers: 12,4,7,1,2,5. Let's see if we can split them into two groups with equal sum. The total of these is 12+4+7+1+2+5=31. So 31 is odd, so it's impossible to split into two equal integer sums. So we can't have two groups adding to 15.5 each. So that approach won't work.\n\nHmm. Maybe use multiplication and division. Let's think. Suppose we have 88 + (21 * something). Wait, 21*5=105, 88+105=193, too big. 21* (something smaller). Maybe 88 + (21 - (something)) =109. So 21 - something =21, so something=0. Not helpful.\n\nWait, 88 + (something) =109, so something=21. So if we can make 21 from the other numbers, but 21 is already one of the numbers. Wait, but we have to use 21 as a separate number. So maybe this is a dead end.\n\nWait, let's try different combinations. Let's see, 5*21=105. Then 105 +4=109. So 5*21 +4=109. Now, we need to use the remaining numbers: 12,7,1,2,88. Wait, but we need to include them in the expression without changing the value. So maybe multiply by 1 or add 0. For example, 5*21 +4 + (12 -12), but again duplicates. Wait, but we have 88, which is a big number. Maybe 88 -88=0, but again duplicate. Hmm.\n\nWait, unless we do something like (5*21 +4) + (88 - 88), but we don't have two 88s. So that's not possible. Alternatively, use 88 in a division. Like (5*21 +4) * (something/something) =109. But we need to use all numbers. Let's see. If we have 5*21 +4 =109, then to incorporate the rest: 12,7,1,2,88. Maybe (5*21 +4) + (88 - 88), but no. Wait, 88 divided by something. Wait, 88 / (12 - (7 + 1 + 2)) = 88 / (12 -10)=88/2=44. Not sure.\n\nWait, maybe (5*21) + (88 / (12 / (7 - (1 + 2)))) Hmm, this is getting too convoluted. Let's try to break it down.\n\nFirst, innermost parentheses: 1 + 2 =3. 7 -3=4. 12 /4=3. Then 88 /3≈29.333. Then 5*21=105 +29.333≈134.333. Not 109.\n\nAnother idea: 88 + 12 =100. Then 100 + 7 + 2 =109. Wait, 88+12+7+2=109. Then we have used 88,12,7,2. Remaining numbers: 4,1,5,21. Need to use them. So how? If we can do 88+12+7+2 + (something - something) where something uses 4,1,5,21. But 88+12+7+2=109 already, so we need to add zero. So maybe (4 -4), but no. Wait, 21 - 5 - (4 +1)=21-5-5=11. Not zero. Hmm.\n\nWait, maybe multiply by (21/21)=1. So (88 +12 +7 +2) * (21 /21) =109*1=109. But we still have to use 4,1,5. Wait, no, we still have 4,1,5 left. So this approach doesn't work.\n\nWait, perhaps 88 + 21 - (something) =109. Wait, 88+21=109, so 109 - something =109 implies something=0. Again, need to make zero from the rest.\n\nWait, let's try to use division. For example, 88 + (21 * (something)). Wait, 21*(5 - (4/ something)). Not sure.\n\nWait, another angle: 109 is a prime, so it's likely a sum or difference of products. Let's see. Let's try 88 + 21 =109. If only I can use the other numbers in a way that they cancel out. Wait, what if we do 88 + 21 + ( (12 - 12) * ... ), but we don't have two 12s. Wait, but we have all numbers once. Wait, maybe ( (5 - (1 + 2 + 4)) * (12 - 7) ). Let's compute that: 5 -7= -2, 12-7=5, so -2*5=-10. Then 88 +21 + (-10)=109-10=99. Not good.\n\nWait, ( (5 * 4) - (1 + 2) ) =20 -3=17. 17 * something. 17*6=102. Not sure.\n\nWait, 12*8=96, but we don't have 8. Wait, 12* (7 + something). 12*9=108. Close to 109. 108 +1=109. So 12*(7 + (something)) +1. Let's see. 12*(7 + x) +1=109. So 12*(7 +x)=108 => 7 +x=9 =>x=2. So x=2. So 12*(7 +2) +1=12*9 +1=108+1=109. Now, check which numbers we've used: 12,7,2,1. Remaining numbers:4,5,21,88. Need to use them. Hmm. So if we can make the rest of the numbers somehow cancel out or be part of the expression. Wait, but the expression so far is 12*(7 + 2) +1 =109. We need to include 4,5,21,88. Maybe multiply by (88/88) or add (21-21), but again duplicates. Not allowed.\n\nWait, unless we can integrate them into the expression. For example, 12*(7 + 2 + (88 - 88)) +1, but again duplicates. Not helpful.\n\nWait, another idea. Let's use 88 and 21 as part of a fraction. Like 88 + (21 * (5 - (4 + 1)/2)). Wait, let's compute that. (4 +1)=5, 5/2=2.5, 5 -2.5=2.5, 21*2.5=52.5, 88 +52.5=140.5. Not 109.\n\nHmm. Maybe 21 * 5 =105, as before. 105 + 4 =109. Then use 88 in a division. Like (21 *5 +4) + (88 - 88), but no. Wait, what if (21 *5) + (88 / (12 - (7 + (2 -1)))) Let's compute denominator: 2 -1=1, 7 +1=8, 12 -8=4. 88 /4=22. Then 105 +22=127. Not 109.\n\nWait, 88 / (something). If I do 88 / (something) = x, then 21*5 + x =109. So x=4. So 88 / (something)=4 => something=22. Can we make 22 from remaining numbers? Remaining numbers after using 21,5,4: 12,7,1,2. Wait, 12 +7 + (2 -1)=12+7+1=20. Not 22. 12 +7 +2 -1=20. 12*2=24, 24 - (7 -1)=24-6=18. Not 22. 12 + (7*2) -1=12+14-1=25. Close. Not 22.\n\nHmm. Let's try another way. Let's consider 109 - 88 =21. So 88 +21=109. If we can write 21 as a combination of the other numbers, but we already have 21 as a number. Wait, no, we need to use 21 as a separate number. So maybe this is the key: we have to use 88 and 21 as separate terms, and the rest of the numbers must somehow not affect the total. But since we have to use all numbers in the expression, we need to include them in a way that their contribution is zero. The only way to do that with basic operations is using multiplication by 1 or addition of 0.\n\nSo, for example, (88 + 21) * (something/something) where something/something =1, using the other numbers. Let's try that.\n\nWe have numbers 12,4,7,1,2,5. Need to make 1 with these. For example, (12 - 7 - (5 - (4 - 2))) /1. Wait, compute inside: 4-2=2, 5-2=3, 12-7=5, 5-3=2. Then 2 /1=2. Not 1.\n\nHow about (5 - (4 + 2 - 1)) / (12 - 7). Let's see: numerator: 5 - (4+2-1)=5 -5=0. Denominator:5. So 0/5=0. Not helpful.\n\nWait, ( (12 / (4 + 2)) * (7 - 5) ) /1. 4+2=6, 12/6=2, 7-5=2, 2*2=4, /1=4. Not 1.\n\nHmm. ( (5 - (7 - (4 + 2))) ) / (12 / something). Wait, 4+2=6, 7-6=1, 5-1=4. Not sure.\n\nWait, maybe ( ( (12 - 7) - (5 - 4) ) / (2 - 1) ). Let's compute: 12-7=5, 5-4=1, 5-1=4. Denominator:2-1=1. So 4/1=4.\n\nNot 1. How about ( ( (12 / 4) - (5 - 2) ) / (7 - 1) ). 12/4=3, 5-2=3, 3-3=0. 0 /6=0.\n\nNot good. Maybe this is too hard. Let's think differently.\n\nWait, what if we do 88 + 21 + ( (5 - 5) * ... ), but we don't have two 5s. Wait, we have one 5. Hmm.\n\nWait, another idea: Use 1 as a multiplier. For example, 88 +21 + (12 * 4 * 7 * 1 * 2 * 5) / (something). But that would be huge. Not helpful.\n\nWait, maybe subtraction. 88 + 21 =109. If we do 88 +21 + 5 -5, but only one 5. Not possible.\n\nWait, let's list all numbers and see possible combinations.\n\nNumbers: 1,2,4,5,7,12,21,88.\n\nWait, 88 + 21 =109. So if we can write the entire expression as 88 + 21 + (1 -1), but we don't have two 1s. Wait, we have a 1. So maybe 88 +21 + (12 - 12), but again duplicates.\n\nWait, unless we use other numbers to make 0. For example, ( (5 + 2) - (4 + 3) ), but we don't have a 3. Wait, remaining numbers:12,4,7,1,2,5. Let's see: 12 - 7 - (5 - (4 - (2 -1))). Let's compute innermost: 2-1=1, 4 -1=3, 5 -3=2, 12 -7=5, 5 -2=3. Not zero.\n\nThis trial and error is taking too long. Maybe I need a better strategy.\n\nLet's consider that we have to use all numbers, so likely there will be multiple operations. Maybe a combination of multiplication and addition.\n\nLet me think of 88 + something =109, so something=21. But 21 is a number, so if we do 88 +21, then we need the rest to cancel. But maybe instead, use division to get a fraction that adds up.\n\nWait, another idea: 88 + (21 * ( (5 - (4 / 2)) / (12 - 7 - 1) )). Let's parse this.\n\nFirst, innermost: 4 /2=2. 5 -2=3.\n\nDenominator: 12 -7 -1=4.\n\nSo 3 /4=0.75.\n\nThen 21 *0.75=15.75.\n\n88 +15.75=103.75. Not 109.\n\nClose, but no.\n\nWait, adjust the denominator. If denominator was 3, then 3/3=1, 21*1=21, 88+21=109. So how to get denominator 3. Let's see: 12 -7 - (something)=3. 12-7=5, so 5 - x=3 =>x=2. So if we have 12 -7 -2=3. Then:\n\n(5 - (4 / (1 + something))) / (12 -7 -2). Wait, let's see.\n\nWait, let's try:\n\n88 + [21 * ( (5 - (4 / (1 + 2))) / (12 - 7) ) ]\n\nCompute innermost: 1 +2=3, 4 /3≈1.333, 5 -1.333≈3.666. Denominator:12-7=5. So 3.666 /5≈0.733. 21*0.733≈15.4. 88+15.4≈103.4. Not good.\n\nWait, what if denominator is 3. Let's get denominator=3. 12 -7 -2=3. So:\n\n(5 - (4 / 1)) / (12 -7 -2) = (5 -4)/3=1/3. 21*(1/3)=7. 88 +7=95. Not enough.\n\nHmm.\n\nWait, 88 + (21 - (something)) =109 => something=21 +88 -109=0. So need to make 0 from other numbers. Let's try:\n\n88 + 21 - (12 - 12), but duplicates. Not allowed.\n\nWait, how about 88 + (21 * (something)) where something=1. So 21*1=21. So 88+21=109. So make something=1 from the rest: 12,4,7,1,2,5.\n\nHow to make 1 with 12,4,7,1,2,5.\n\nFor example: (12 - 7 - (5 - (4 - 2))) /1. Compute: 4-2=2, 5-2=3, 12-7=5, 5-3=2. 2 /1=2. Not 1.\n\n( (5 - 4) + (2 - 1) ) / (12 -7 ). (1 +1)/5=2/5. No.\n\n( (12 / (7 - (5 - 2)) ) - (4 -1) ). 5-2=3, 7-3=4, 12/4=3. 4-1=3. 3 -3=0. Not helpful.\n\nWait, ( (12 - 7 - 5) * (4 - 2 -1) ). 0 *1=0.\n\nNot helpful. Hmm.\n\nWait, ( ( (12 - 7) - 5 ) / (4 - 2 -1) ). (5-5)/1=0/1=0.\n\nStill zero. Not 1.\n\nWait, 5 - 4 =1. Then we have 1. So 5 -4=1. Then we still have 12,7,2,1 left. Wait, but we need to use all numbers. So if we do (5 -4) =1, then we have to use 12,7,2,1. But we already have a 1. Wait, the numbers are 12,4,7,1,2,5. So using 5-4=1, then we have 12,7,2,1 left. But we need to make the entire expression equal to 1 using all of them. Wait, this might be a way.\n\nSo, (5 -4) =1. Then we have 12,7,2,1. Need to make 1 from those. Like (12 -7 -2 -1)=2. Not 1. (12 / (7 +2 +1))=12/10=1.2. Not 1. ( (12 -7) / (2 +1) )=5/3≈1.666. Not 1.\n\nHmm. Alternatively, ( (12 / (7 - (2 +1)) ) -5 +4 ). Wait, getting confused.\n\nWait, let's step back. If I use 5 -4 =1, then to get a total multiplier of 1, maybe:\n\n(5 -4) * (something) =1, where something uses 12,7,2,1. But (5-4)=1, so we need something=1. So same problem.\n\nThis isn't working. Let's try a different combination.\n\nWhat if we do 12*7=84. 84 + 21=105. 105 +4=109. So 12*7 +21 +4=109. Now, remaining numbers: 1,2,5,88. Need to include them. If we can do (12*7 +21 +4) + (88 -88) but no. Wait, but what if we multiply by ( (5 - (2 + 1)) / something ). Wait, 5 - (2 +1)=2. If we do 109 * (2 /2)=109, but we don't have another 2.\n\nWait, here's an idea: Use 88 in a division that results in 1 when combined with other numbers. Like (88 / (88)), but we only have one 88. Not helpful.\n\nWait, what if we take 12*7 +21 +4 + (5 -5), but again duplicate.\n\nWait, maybe use 88 as part of a subtraction. For example, 88 + something =109, so something=21. But we already used 21. Wait, no.\n\nWait, another angle: Let's consider that 109 = 9*12 + 1. 9*12=108 +1=109. So 9*12 +1. How to get 9 from other numbers: 7, 21, 4,5,2,88. Wait, 21 - 12=9, but 12 is used. Wait, 21 - (something)=9. 21 -12=9, but 12 is already used in the 9*12. Hmm.\n\nWait, 9 could be (5 + 4), so 5 +4=9. Then 9*12 +1=108 +1=109. So expression: (5 +4)*12 +1. Now, used numbers:5,4,12,1. Remaining:7,2,21,88. Need to include them.\n\nSo, similar to before, need to make the rest cancel. Maybe ((5 +4)*12 +1) + (21 -21), but duplicate. Or multiply by (88/88).\n\nWait, ((5 +4)*12 +1) * (88 /88) =109*1=109. But we still have 7 and 2 unused. So not good.\n\nWait, unless we do ((5 +4)*12 +1) + (21 - 21), but still missing 7 and 2.\n\nWait, another way: ((5 +4)*12 +1) + (88 - 88 -7 +7 +2 -2), but that's using numbers multiple times. Not allowed.\n\nThis is frustrating. Let's try to find another combination.\n\nHow about 21*5=105. 105 + (88 / (12 / (7 - (4 - 2)))) +1. Wait, let's parse this.\n\nFirst, innermost: 4 -2=2. 7 -2=5. 12 /5=2.4. 88 /2.4≈36.666. 105 +36.666≈141.666 +1≈142.666. Not 109.\n\nNope.\n\nWait, 88 - 21 =67. 67 + something=109. Something=42. Can we make 42 from the rest:12,4,7,1,2,5. 12*4=48, 48 - (7 - (5 - (2 -1)))=48 - (7 - (5 -1))=48 - (7 -4)=48-3=45. Not 42. 7*5=35, 35 + (12 -4 -2 -1)=35+5=40. Close. 7*6=42, but no 6.\n\nWait, 12 + 7 + 5 + 4 + 2 +1=31. Not 42.\n\nHmm.\n\nWait, 88 - (21 - something)=109. So 88 -21 + something=109 => something=42. Again, need 42 from other numbers.\n\nSame problem.\n\nAnother idea: 88 + (12 * something)=109. 12* something=21. So something=1.75. Can we make 1.75 from remaining numbers:4,7,1,2,5,21. 7/4=1.75. So 88 +12*(7/4)=88 +21=109. Wait, this uses 88,12,7,4. Then remaining numbers:1,2,5,21. But wait, we still have to use all numbers. So how?\n\nWait, let's write it out: 88 + 12*(7/4) = 88 + 21 =109. Now, we've used 88,12,7,4. Remaining numbers:1,2,5,21. Need to incorporate them. If we can do something like [88 + 12*(7/4)] * (21/21) * (5/5) * (2/2) *1, but that uses numbers multiple times. Not allowed.\n\nBut wait, we have to use each number exactly once. So if we do 88 + 12*(7/4) + (21 -21) + (5 -5) + (2 -2) + (1 -1), but again duplicates and not using each once.\n\nWait a second. Wait, the expression 88 + (12 * 7 / 4) = 88 + 21 = 109. This uses 88,12,7,4. Now, what if we multiply by ( (5 - (2 + 1)) / (21 - 21) )? No, division by zero. Bad.\n\nWait, but we still have 1,2,5,21 left. Maybe add zero: 88 + (12 * 7 / 4) + (21 -21) + (5 -5) + (2 -2) + (1 -1). But again, duplicates.\n\nWait, no. Wait, the key insight here is that 12*7/4=21, so if we write it as 88 + (12 * 7 / 4), that uses 88,12,7,4. Then we have 1,2,5,21 left. If we can make the rest of the expression evaluate to 0 using those numbers. For example, 21 - 21 is zero, but we don't have two 21s. Wait, we have one 21. Hmm.\n\nWait, but what if we do 88 + (12 * 7 / 4) + (21 - 21), but we don't have two 21s. Not possible.\n\nWait, but we have a 21 left. So maybe (88 + (12 * 7 / 4)) + ( (5 - 2 - 1) - (21 / 21) ). Wait, 5-2-1=2, 21/21=1, so 2 -1=1. Then total is 109 +1=110. Close, but no.\n\nWait, ((5 - (2 + 1)) * 21) = (2)*21=42. If we subtract that: 109 -42=67. Not helpful.\n\nWait, another idea: Use the remaining numbers to make 1 and multiply. So [88 + (12 * 7 /4)] * ( (5 - (2 + 1)) / 21 ). Compute: 5-3=2, 2/21≈0.095. 109 *0.095≈10.35. Not good.\n\nHmm. Wait, but what if we do 88 + (12 * 7 / 4) + (21 - 21), but we can't. Wait, unless we use 21 in the denominator or something.\n\nWait, here's a thought. If we have to use all numbers, perhaps the expression is:\n\n88 + (12 * 7 / 4) + (21 - 21), but no. Wait, no. Wait, let's count the numbers used:\n\n- 88: used\n\n- 12: used\n\n- 7: used\n\n- 4: used\n\n- 21: used in (21 -21), but we only have one 21. So invalid.\n\nWait, but we have to use each number exactly once. So we can't use 21 twice. So scratch that.\n\nWait, going back to the expression 88 + (12 * 7 / 4) =109. This uses four numbers. We need to use all eight. So we need to involve the other four numbers in a way that doesn't change the value. The only way is to add 0 or multiply by 1.\n\nSo, for example, + (5 -5), but we don't have two 5s. Or * ( (2 + 1) / (2 + 1) ), but we have to use each number once. Wait, we have 1,2,5,21 left. So if we do:\n\n[88 + (12 * 7 / 4)] + ( (5 - 5) * 21 * 1 * 2 ), but again duplicate 5.\n\nWait, no. Let's think: To make 0, we need something like (a - b), where a and b are made from the remaining numbers. But we have four numbers:1,2,5,21. Can we make two equal numbers from them? 21 - (5 + 2 + 1)=13. Not zero. 5*2=10, 21 - (10 +1)=10. Not equal.\n\nWait, (21 - (5*2 +1))=21 -11=10. Not zero.\n\n( (21 / (5 - (2 -1))) ) =21 / (5 -1)=21/4=5.25. Not helpful.\n\nWait, this is really challenging. Maybe the initial idea of 88 +21 is the way to go, and the rest of the numbers need to be used in a fraction that equals 0, but I'm not seeing it.\n\nWait, let's try using all numbers in a long expression. For example:\n\n88 + 21 + 12 - 12 + 7 -7 + 4 -4 +5 -5 +2 -2 +1 -1. But this uses each number twice, which isn't allowed.\n\nWait, but we have to use each once. So maybe:\n\n88 + 21 + (12 - 4 -7 -1 -2 -5). Let's compute the parentheses:12 -4=8, -7=1, -1=0, -2=-2, -5=-7. So total expression:88+21-7=102. Not 109.\n\nClose. 102 vs 109. Off by 7.\n\nWait, 88 +21 + (12 - (4 +7 +1 +2 +5)). Compute inside:4+7+1+2+5=19. 12-19=-7. 88+21-7=102. Same as above.\n\nHmm. What if we do 88 +21 + (something else). Wait, 88 +21 =109. If we can have the rest of the numbers subtract to zero. Wait, 88 +21 + (expression)=109 => expression=0. So need expression=0 using 12,4,7,1,2,5.\n\nWe need to arrange these six numbers with + and - to get zero. Let's see:\n\nLet's try 12 - 4 -7 -1 +2 +5= (12) -4=8-7=1-1=0+2=2+5=7. Not zero.\n\n12 +4 -7 -1 -2 -5= (16) -7=9-1=8-2=6-5=1.\n\n12 - (4 +7 +1 +2 +5)=12 -19=-7.\n\nHow about (12 +5) - (4 +7 +1 +2)=17 -14=3.\n\n(12 +4 +5) - (7 +1 +2)=21 -10=11.\n\n(12 +7 +5) - (4 +1 +2)=24 -7=17.\n\nNot zero. Maybe multiplication/division.\n\n(12 * (5 - (4 + 2))) / (7 -1). Compute: 4+2=6, 5-6=-1, 12*-1=-12. Denominator:6. -12 /6=-2.\n\nNot zero.\n\n( (12 - 7) * (5 - 4) ) - (2 +1)= (5*1) -3=2.\n\nHmm.\n\nWait, what if ( (12 / (4)) * (5 - (2 +1)) ) -7. 12/4=3, 2+1=3, 5-3=2, 3*2=6, 6-7=-1.\n\nClose to zero but not quite.\n\nThis is really tough. Maybe the solution doesn't involve 88 +21 directly.\n\nLet's try a different combination. How about 21*5=105, then 105 + (88 / (12 - (7 + (4 / 2)) )) +1. Wait, let's compute denominator:\n\n4 /2=2. 7 +2=9. 12 -9=3. 88 /3≈29.333. 105 +29.333≈134.333 +1≈135.333. No.\n\nWait, 88 / (12 -7 - (4 /2)) =88 / (5 -2)=88/3≈29.333. Same as above.\n\nAnother idea: 5* (21 - (12 / (4 - (2 / (7 - 1)) ))). Let's parse this.\n\nInnermost:7 -1=6. 2 /6=1/3. 4 -1/3=11/3. 12 / (11/3)=36/11≈3.27. 21 -3.27≈17.73. 5*17.73≈88.65. Not 109.\n\nNot good.\n\nWait, let's think of 109 as 100 +9. We know 88 +12=100. Then need 9 from 7,1,2,5,21,4. Wait, 21 - 12=9, but 12 is used. Hmm. 7 + (5 - (4 - (2 -1)))=7 + (5 - (4 -1))=7 + (5-3)=7+2=9. Yes!\n\nLet's check:\n\nStart with 88 +12 =100.\n\nThen 7 + (5 - (4 - (2 -1)))=7 + (5 - (4 -1))=7 + (5 -3)=7 +2=9.\n\nSo total expression: (88 +12) + (7 + (5 - (4 - (2 -1)))).\n\nLet's verify all numbers used: 88,12,7,5,4,2,1. Wait, what about 21? Oh no, we haven't used 21. Oops, forgot 21.\n\nSo close! So we have to include 21. Hmm. So this uses all except 21. So need to involve 21.\n\nWait, maybe instead of 7 + ..., use 21 - something. Let's see.\n\nWe need total 9. If we do 21 - 12=9, but 12 is already used. Not helpful.\n\nWait, (21 / something). 21 / (7/3)=9, but not sure.\n\nWait, let's recast. We need to use 21. So maybe:\n\n(88 +12) + (21 - 12) =100 +9=109, but duplicate 12.\n\nNot allowed.\n\nWait, another try: 88 + (21 - (12 / ( (7 -5) + (4 / (2 +1)) ))). Let's compute denominator:\n\nFirst, 2 +1=3. 4 /3≈1.333. 7 -5=2. So denominator=2 +1.333≈3.333. 12 /3.333≈3.6. 21 -3.6≈17.4. 88 +17.4≈105.4. Not 109.\n\nNope.\n\nWait, going back to the earlier almost-solution that used all numbers except 21: (88 +12) + (7 + (5 - (4 - (2 -1)))) =100 +9=109. The missing number is 21. So if we can replace the 9 with something that includes 21. Like instead of getting 9 from the other numbers, get 9 +21 -21, but again duplicates.\n\nWait, what if we do (88 +12) + (7 + (5 - (4 - (2 -1)))) + (21 -21). But duplicates.\n\nWait, unless we can integrate 21 into the expression. For example, change the 7 to 21 -14, but we don't have 14.\n\nWait, let's see. The part that made 9 was:7 + (5 - (4 - (2 -1))). If we replace the 7 with 21 - something. Let's say 21 - x, so that 21 -x + (5 - (4 - (2 -1)))=9. Then x=21 + [5 - (4 - (2 -1))] -9=21 + [5 -3] -9=21 +2 -9=14. So x=14. Can we make 14 from remaining numbers? Wait, but we're trying to use all numbers. This might not help.\n\nWait, this is getting too convoluted. Let's try to see if the expression I had before can be adjusted to include 21.\n\nOriginal almost-solution: 88 +12 +7 +5 -4 + (2 -1). Wait, let's compute:\n\n88+12=100, +7=107, +5=112, -4=108, +2=110, -1=109. Hey, that works!\n\nWait, let's verify step by step:\n\nStart with 88.\n\n+12: 100\n\n+7: 107\n\n+5: 112\n\n-4: 108\n\n+2: 110\n\n-1: 109.\n\nYes! And what numbers have we used? 88,12,7,5,4,2,1. Missing number is 21. Oh no! Still missing 21.\n\nAh, so close. We used all numbers except 21. So need to include 21 somehow.\n\nWait, but maybe we can adjust the operations to include 21. For example, instead of +5, do + (21 -16), but we don't have 16.\n\nWait, let's see. The current total without 21 is 109. We need to use 21. So we need to have an expression where 21 is used in a way that doesn't change the total, like multiplying by 21/21 or adding 21-21.\n\nBut we have to use each number once. So:\n\n(88 +12 +7 +5 -4 +2 -1) * (21 /21) =109*1=109. But this uses 21 twice. Not allowed.\n\nAlternatively, (88 +12 +7 + (21 - 16) -4 +2 -1), but we don't have 16.\n\nWait, another idea: Replace one of the numbers with an expression involving 21. For example, instead of +5, do + (21 - 16), but where to get 16. Or maybe:\n\n88 +12 +7 + (21 - 16) -4 +2 -1. Still need 16.\n\nWait, 21 - (4 + 2 + 1 + something)=21 - (7)=14. Not helpful.\n\nWait, let's think differently. What if we do 88 + 21 =109, and then use the other numbers as (12 - 12) etc., but we need to use them all. Wait, but we have to use each number once, so maybe:\n\n88 + 21 + ( (12 - 7 - 5) * (4 - 2 - 1) )\n\nCompute: 12 -7 -5=0. 4 -2 -1=1. 0*1=0. So total=109 +0=109.\n\nHey, this might work!\n\nLet's verify:\n\nNumbers used: 88,21,12,7,5,4,2,1. All exactly once.\n\nExpression: 88 + 21 + ((12 - 7 - 5) * (4 - 2 - 1))\n\nCompute step by step:\n\nFirst, compute (12 -7 -5)=0.\n\nThen (4 -2 -1)=1.\n\nMultiply them:0 *1=0.\n\nAdd to 88 +21:109 +0=109.\n\nYes! This uses all numbers exactly once.\n\nLet me double-check:\n\n- 88: used\n\n- 21: used\n\n- 12: used\n\n- 7: used\n\n- 5: used\n\n- 4: used\n\n- 2: used\n\n- 1: used\n\nAll numbers accounted for. Operations are +, -, *.\n\nPerfect!\n\nSo the expression is 88 + 21 + (12 - 7 - 5) * (4 - 2 - 1).\n\nSimplify the parentheses:\n\n(12 -7 -5) = 0\n\n(4 -2 -1) =1\n\n0 *1 =0\n\n88 +21 +0=109.\n\nYes! This works.\n</think>\n\nTo solve the problem of creating an expression that equals **109** using **all** the numbers **12, 4, 7, 1, 2, 5, 21, 88** exactly once with the operations **+**, **-**, **\\***, and **/**, we proceed by identifying a structure that allows us to use all numbers while keeping the total at 109.\n\n---\n\n### Step-by-Step Reasoning:\n\nWe observe that:\n\n$$\n88 + 21 = 109\n$$\n\nThis gives us a base expression. However, we must also use the remaining numbers: **12, 4, 7, 1, 2, 5**. To include them without changing the value of the expression, we need to construct a **zero** using these numbers.\n\nLet’s define two sub-expressions:\n\n- $ (12 - 7 - 5) = 0 $\n- $ (4 - 2 - 1) = 1 $\n\nThen:\n\n$$\n(12 - 7 - 5) \\times (4 - 2 - 1) = 0 \\times 1 = 0\n$$\n\nAdding this to the original sum:\n\n$$\n88 + 21 + [(12 - 7 - 5) \\times (4 - 2 - 1)] = 109 + 0 = 109\n$$\n\nAll numbers are used exactly once:\n- **88**, **21** used in the main sum\n- **12**, **7**, **5** used in the first parenthesis\n- **4**, **2**, **1** used in the second parenthesis\n\n---\n\n### Final Expression:\n\n$$\n88 + 21 + (12 - 7 - 5) \\times (4 - 2 - 1)\n$$\n\n---\n\n### Verification:\n\n- $ 12 - 7 - 5 = 0 $\n- $ 4 - 2 - 1 = 1 $\n- $ 0 \\times 1 = 0 $\n- $ 88 + 21 + 0 = 109 $\n\nAll numbers are used **exactly once**, and the expression evaluates to **109**.\n\n---\n\n<answer>88 + 21 + (12 - 7 - 5) * (4 - 2 - 1)</answer>",
"Okay, let's see. The user wants me to continue exploring alternative solution strategies for the same problem. The original problem was to use all numbers 12, 4, 7, 1, 2, 5, 21, 88 exactly once with +, -, *, / to make 109. The first solution used 88 + 21 + (12-7-5)*(4-2-1). Now I need to find another way.\n\nHmm, maybe instead of making zero, I can use multiplication or division to adjust the numbers. Let's list all the numbers again: 12, 4, 7, 1, 2, 5, 21, 88. Total eight numbers. Let's think of other combinations.\n\nAnother idea: 88 is a big number. 109 - 88 = 21. Wait, but 21 is already one of the numbers. So 88 + 21 = 109, but we need to use all numbers. So maybe 88 + 21 + something that cancels out. Wait, the first solution did that. But maybe there's a different way to cancel.\n\nAlternatively, maybe use 88 + something else. Let's see: 109 - 88 = 21. So if I can make 21 from the other numbers, but 21 is already a number, so that might not help. Wait, but we need to use all numbers. So perhaps 88 + (some expression using the rest) = 109. So the expression using the rest should equal 21. Let's check: 12,4,7,1,2,5,21. Wait, but 21 is part of the numbers. Wait, the numbers are 12,4,7,1,2,5,21,88. So if we use 88, then the other seven numbers need to combine to 21. But 21 is one of them. So maybe 21 is part of the expression. Wait, the first solution used 21 as part of the sum. Let's see.\n\nAlternatively, maybe 88 + 21 = 109, but we need to use all the other numbers (12,4,7,1,2,5) in a way that doesn't change the sum. So if we can make 0 with those numbers, as before. The first solution used (12-7-5) and (4-2-1), multiplied to get 0. Are there other ways to make 0 with those numbers?\n\nLet's see: 12 - 4 - 7 -1 = 0. Wait, 12 -4=8, 8-7=1, 1-1=0. So (12 -4 -7 -1) = 0. Then we still have 2 and 5 left. So 0 * (something with 2 and 5) = 0. So maybe (12 -4 -7 -1) * (5 - 2) = 0 * 3 = 0. Then 88 +21 + 0 = 109. Let's check all numbers: 88,21,12,4,7,1,5,2. Yes, all used exactly once. So that's another expression.\n\nWait, let's verify:\n\n(12 - 4 -7 -1) = 0\n\n(5 - 2) = 3\n\n0 * 3 = 0\n\n88 +21 +0 = 109.\n\nYes, that works. So the expression would be 88 + 21 + (12 -4 -7 -1) * (5 - 2).\n\nLet's list all numbers used: 88,21,12,4,7,1,5,2. All exactly once. Perfect.\n\nIs this a valid alternative? Let's check.\n\nAnother way: Maybe using division. For example, 88 + (something) = 109. So something = 21. But we need to use all numbers. Wait, 21 is a number, but maybe combine others to make 21. Wait, but we need to use all numbers, so perhaps 88 + (21) + ... but we need to use the others. Hmm.\n\nWait, maybe 88 + 21 is 109, so the rest must sum to zero. So any expression with the other numbers that equals zero. Let's see.\n\nAnother way to get zero: 5 - 2 - 3, but we don't have 3. Wait, 7 - (4 + 1 + 2) = 0? 7 - (4+1+2)=7-7=0. So (7 -4 -1 -2) =0. Then 12 and 5 left. So (7 -4 -1 -2) * (12 -5) =0*7=0. So then 88 +21 +0=109.\n\nNumbers used: 88,21,7,4,1,2,12,5. All used once. That's another way.\n\nSo expression: 88 +21 + (7 -4 -1 -2) * (12 -5).\n\nCheck:\n\n7-4-1-2=0\n\n12-5=7\n\n0*7=0\n\n88+21=109.\n\nYes, that works too.\n\nSo that's a third alternative.\n\nWait, but the user asked for alternative strategies, so maybe these are valid. Let's check if these are different from the first solution.\n\nFirst solution used (12-7-5) * (4-2-1).\n\nThis new one uses (7-4-1-2) * (12-5).\n\nYes, different grouping.\n\nAnother idea: Maybe using multiplication or division to get a non-zero contribution. For example, 88 + something = 109, but the something is not 21. Wait, 109 -88=21, so the something must be 21, but if we can't use 21 directly, but need to make 21 from other numbers. Wait, but 21 is already one of the numbers, so maybe we can use 21 as part of a different operation.\n\nWait, for example, 88 + (21 * something) where something is 1, but that would be 88 +21=109. But then we still need to use the other numbers. So again, the other numbers need to form 1. Wait, but 21*1=21, but then 88 +21*1=109. But then the other numbers need to equal 1. Let's see: can we make 1 from 12,4,7,1,2,5? Wait, but 1 is already a number. So maybe (12 -7 -5) * (4 -2) +1. Wait, but this is getting complicated.\n\nWait, let's think: 88 + 21 * (some expression that equals 1). So 21 *1 =21, so 88 +21=109. Then the expression for 1 should use the remaining numbers: 12,4,7,1,2,5. Wait, but 1 is already a number. So perhaps ( (12 -7 -5) + (4 -2 -1) ) but that's 0 +1=1. Wait, but that's similar to before. Wait, but if we do 21 * [ (12 -7 -5) + (4 -2 -1) ] =21*(0 +1)=21*1=21. Then 88 +21=109. So the full expression would be 88 +21*( (12 -7 -5) + (4 -2 -1) ). Let's check numbers:\n\n88,21,12,7,5,4,2,1. All used once. Let's compute:\n\n12-7-5=0\n\n4-2-1=1\n\n0 +1=1\n\n21*1=21\n\n88+21=109.\n\nYes, that's another valid expression.\n\nSo this is a different structure: multiplication by 21 instead of adding 21. So this is another alternative.\n\nLet's verify all numbers are used: 88,21,12,7,5,4,2,1. Yes, all exactly once.\n\nSo this is a third alternative.\n\nAnother approach: Maybe using division. Let's see. For example, 88 + (something) =109, so something=21. But maybe 21 can be formed via division. Like 42/2=21, but 42 is not a number here. Wait, numbers are 12,4,7,1,2,5,21,88. Let's see: 21 is already there, so maybe 21* (some fraction). Wait, but we need to use all numbers.\n\nWait, another idea: 88 + (21 * (5 - (12 / (7 - (4 - 1)) / 2)))... Hmm, this might get too complicated. Let's check if it's possible.\n\nWait, maybe 12 / something. Let's try to find another way.\n\nWait, let's consider 88 + 21 = 109. So we need to use the other numbers to make 0. So any way to make 0 with 12,4,7,1,2,5. Let's list all possible combinations.\n\nPossible zero expressions:\n\n- 12 - 7 -5 =0, then 4 -2 -1=1, multiply to get 0. (First solution)\n- 12 -4 -7 -1=0, then 5-2=3, multiply to get 0. (Second solution)\n- 7 -4 -1 -2=0, then 12-5=7, multiply to get 0. (Third solution)\n- 5 - (4 + 1) =0, then 12 -7 -2=3, multiply 0*3=0. So (5 -4 -1) * (12 -7 -2) =0*3=0. Then 88+21+0=109. Let's check numbers: 88,21,5,4,1,12,7,2. All used once. Yes.\n\nSo (5 -4 -1) * (12 -7 -2) =0*3=0. So expression: 88 +21 + (5 -4 -1)*(12 -7 -2).\n\nThat's another valid expression.\n\nSo this is a fourth alternative.\n\nLet's verify:\n\n5-4-1=0\n\n12-7-2=3\n\n0*3=0\n\n88+21=109.\n\nYes, correct.\n\nSo there are multiple ways to make the zero using different groupings of the numbers. All of these are valid and use all numbers exactly once.\n\nAnother way: 2*1=2, 4-2=2, but not sure. Wait, maybe (2*1) - (4 - (12 -7 -5)). Let's see:\n\nWait, perhaps not helpful. Let's stick to the zero method.\n\nAnother zero expression: 12 - (7 + 5) =0, and 4 - (2 +1)=1. So same as first solution.\n\nAlternatively, 12 - (5 +7) =0, and (4 -2) -1=1. Same as before.\n\nSo it seems all these variations are based on grouping the numbers to make zero. Since the problem requires using all numbers exactly once, and we need to get 109, which is 88+21, the key is to use the remaining numbers to create a zero.\n\nAnother way to make zero: (12 / (4 + 2)) - (7 -5 -1). Let's compute:\n\n4+2=6, 12/6=2\n\n7-5-1=1\n\n2-1=1. Not zero.\n\nHmm. Not helpful.\n\nHow about (12 - (7 + 5)) * (4 - (2 + 1)) =0*1=0. Which is the same as the first solution.\n\nSo that's the same as before.\n\nAlternatively, ( (12 -7) -5 ) * ( (4 -2) -1 ) = (5-5)*(2-1)=0*1=0. Same thing.\n\nSo all these are variations of the same structure.\n\nAnother possible structure: Maybe not using 88 +21, but using a different combination. Let's see.\n\nSuppose we don't use 88 and 21 as separate numbers. Let's say we use 88 + something else.\n\nWhat's 109 -88=21. So we need the rest to add up to 21. Wait, but 21 is a number, so maybe 88 +21=109. If we use 21 as part of the expression, but perhaps in a different way. Wait, but the numbers must be used once, so 21 is either added, subtracted, multiplied, etc.\n\nWait, what if we do 88 + (21 * (something)) where something is 1. But as before, something would need to be made from other numbers.\n\nWait, 21 * 1 =21, so 88 +21*1=109. Then the 1 can be made from other numbers. But 1 is already a number, so perhaps (21 * 1) +88. But then we still need to use 12,4,7,2,5. So to make the other numbers cancel out. For example, 12 -7 -5=0, 4 -2=2, so 0*2=0. So 88 +21*1 + (12-7-5)*(4-2)=109+0=109.\n\nWait, let's check:\n\nNumbers used: 88,21,1,12,7,5,4,2. All present.\n\nExpression: 88 + 21 * 1 + (12 -7 -5) * (4 -2)\n\nCompute:\n\n12-7-5=0\n\n4-2=2\n\n0*2=0\n\n21*1=21\n\n88+21+0=109.\n\nYes, this works. This is similar to the earlier solution but structured differently. Here, the multiplication by 1 is explicit, and the zero term is multiplied by (4-2).\n\nSo this is another alternative expression.\n\nAnother possibility: Maybe using division. For example, 5 / (1) =5, but not sure. Let's see.\n\nWait, let's think of 88 + 21 = 109. So if we can use the other numbers to form 0, but perhaps using division. For example, (12 / 12) but we don't have 12 twice. Wait, no.\n\nWait, 4 / 2 =2, 7 -5=2, then 2 -2=0. So (4/2) - (7-5)=2-2=0. Then multiply by something. Wait, so ( (4/2) - (7-5) ) * (12 -1) =0*11=0. Then 88 +21 +0=109.\n\nCheck numbers: 88,21,4,2,7,5,12,1. All used once.\n\nYes, that's another valid expression.\n\nLet's verify:\n\n4/2 =2\n\n7-5=2\n\n2-2=0\n\n12-1=11\n\n0*11=0\n\n88+21=109.\n\nPerfect. So expression: 88 + 21 + ((4 / 2) - (7 - 5)) * (12 - 1)\n\nThis uses all numbers exactly once.\n\nSo this is a fifth alternative.\n\nThis uses division and subtraction to create the zero.\n\nAnother way: ((12 - 4) / 2) - (7 - 5) = (8/2) -2=4-2=2. Not zero. Hmm.\n\nWait, let's try ( (12 - 5) -7 ) * (4 -2 -1). 12-5=7, 7-7=0. 4-2-1=1. 0*1=0. So same as first solution.\n\nSo, it seems there are multiple ways to structure the zero term. The key is to find different groupings of the numbers that result in zero when combined with multiplication or addition.\n\nLet's try to see if there's a way that doesn't rely on making zero. For example, maybe 88 + 21 =109, but instead of adding zero, perhaps using the other numbers in a way that contributes to the sum. Wait, but 88 +21 is exactly 109, so any other numbers must cancel out. So the other numbers must sum to zero, which is why the zero approach is necessary.\n\nAlternatively, maybe a different combination. Let's see: 109 is the target. Let's think of other combinations.\n\nWhat's 21 * 5 =105. Then 105 +4=109. So 21*5 +4=109. Then we need to use the remaining numbers:12,7,1,2,88. Wait, but 88 is still there. 88 is a big number. 105+4=109, but 88 is left. So that doesn't work. Unless we do 21*5 +4 + (88 -88), but we can't use 88 twice.\n\nWait, maybe 21*5 =105, 105 + (88 / something) =109. 109-105=4. So 88 / x =4 → x=22. Can we make 22 from the remaining numbers:12,7,1,2. 12+7+2+1=22. Yes. So 21*5 + (88 / (12+7+2+1)) =105 + (88/22)=105+4=109.\n\nLet's check:\n\nNumbers used: 21,5,88,12,7,2,1. Wait, missing the number 4. Oh, we have to use 4 as well. The numbers are 12,4,7,1,2,5,21,88. So in this case, we're using 21,5,88,12,7,2,1, but missing 4. So we need to include 4. Hmm.\n\nWait, 88 / (12 +7 +2 +1 -4) =88/(22-4)=88/18≈4.888, which is not 4. Not helpful.\n\nAlternatively, adjust the denominator to include 4. Let's see: 12+7+2+1+4=26. 88/26≈3.38, not helpful.\n\nWait, maybe 88 / (something) =4, so something=22. To get 22 from 12,7,1,2,4. Let's see: 12+7+2+1=22, but 4 is left. So 12+7+2+1=22, then 4 is unused. So we need to include 4. So maybe (12+7+2+1) -4=18. 88/18 is not 4. Not helpful.\n\nAlternatively, (12+7+2) + (4-1)=21+3=24. 88/24≈3.666. No.\n\nHmm. Maybe this approach isn't working. Let's try another.\n\nWhat about 12 * 9 =108, close to 109. But we don't have 9. 12* (8 +1)=108. Wait, but let's see. 12*8=96, 96+13=109. Not sure.\n\nAlternatively, 88 + 12 + 7 + 2 =109. Let's compute: 88+12=100, +7=107, +2=109. Then we have used 88,12,7,2. Remaining numbers:4,1,5,21. Need to use them. So 109 + (4-4) etc. But we can't add zero unless we make it from remaining numbers. Wait, 4,1,5,21. To make zero: 21 -5 -4 -1=11. Not zero. 21 - (5+4+1)=11. Not helpful.\n\nAlternatively, 88 +12 +7 +2 + (21 -21)=109, but we can't use 21 twice.\n\nHmm. This path doesn't seem to work.\n\nAnother idea: 21 * 5 =105. 105 + 4 =109. Then we need to use 88,12,7,1,2. Let's see: 88 is large. Maybe 88 - (12 +7 +1 +2)=88-22=66. Then 105+4+66=175. Too big. Not helpful.\n\nWait, if we do 21*5 +4 + (88 -88), but again, can't use 88 twice.\n\nAlternatively, 21*5 + (88 / (12 - (7 + 1 + 2))) =105 + (88 / (12 -10))=105 + (88/2)=105+44=149. Too big.\n\nNot helpful.\n\nLet's go back to the zero approach, as it seems the most viable.\n\nAnother way to make zero: (7 - (4 + 2 + 1)) * (12 -5) = (7-7)*(7)=0*7=0. Which is the third alternative I thought of earlier.\n\nYes, that's the same as before.\n\nSo, given that multiple solutions exist based on creating a zero with the remaining numbers, and the user asked for alternative strategies, I can list several of these.\n\nThe key is to find different groupings of the numbers 12,4,7,1,2,5 to form zero via multiplication or addition/subtraction.\n\nLet's formalize some of the alternatives:\n\n1. **First Solution (Given):** \n $ 88 + 21 + (12 - 7 - 5) \\times (4 - 2 - 1) $\n\n2. **Alternative 1:** \n $ 88 + 21 + (12 - 4 - 7 - 1) \\times (5 - 2) $\n\n3. **Alternative 2:** \n $ 88 + 21 + (7 - 4 - 1 - 2) \\times (12 - 5) $\n\n4. **Alternative 3:** \n $ 88 + 21 + (5 - 4 - 1) \\times (12 - 7 - 2) $\n\n5. **Alternative 4:** \n $ 88 + 21 \\times 1 + (12 - 7 - 5) \\times (4 - 2) $\n\n6. **Alternative 5:** \n $ 88 + 21 + \\left( \\frac{4}{2} - (7 - 5) \\right) \\times (12 - 1) $\n\nEach of these uses all numbers exactly once and evaluates to 109.\n\nLet's verify one of the new ones, say Alternative 5:\n\n$ \\frac{4}{2} = 2 $, $ 7 - 5 = 2 $, so $ 2 - 2 = 0 $. Then $ 12 - 1 = 11 $. $ 0 \\times 11 = 0 $. $ 88 + 21 + 0 = 109 $. All numbers used: 88,21,4,2,7,5,12,1. Correct.\n\nAnother check for Alternative 4:\n\n$ 21 \\times 1 =21 $, $ 12-7-5=0 $, $ 4-2=2 $, $ 0 \\times 2=0 $. So $ 88 +21 +0=109 $. Numbers used: 88,21,1,12,7,5,4,2. Correct.\n\nSo all these alternatives are valid.\n\nThe user asked to \"continue exploring alternative solution strategies,\" so providing a few more of these would be appropriate.\n\nAnother possible alternative: Using division in the zero term.\n\nFor example, $ (12 / (7 - 5)) - (4 + 2) = (12/2) -6=6-6=0 $. Then multiply by 1 to keep it zero. So:\n\n$ 88 + 21 + \\left( \\frac{12}{7 - 5} - (4 + 2) \\right) \\times 1 $\n\nCheck:\n\n7-5=2, 12/2=6, 4+2=6, 6-6=0. 0*1=0. 88+21=109.\n\nNumbers used: 88,21,12,7,5,4,2,1. All present. Perfect.\n\nSo this is another valid expression.\n\nExpression: $ 88 + 21 + \\left( \\frac{12}{7 - 5} - 4 - 2 \\right) \\times 1 $\n\nThis uses division in the zero term, which is a different strategy.\n\nYes, this works. So now we have a sixth alternative.\n\nLet's confirm the numbers:\n\n- 88, 21, 12, 7, 5, 4, 2, 1. All used exactly once.\n\nComputation:\n\n7-5=2\n\n12/2=6\n\n4+2=6\n\n6-6=0\n\n0*1=0\n\n88+21+0=109.\n\nPerfect.\n\nSo this is a valid alternative that uses division in the zero expression.\n\nTherefore, there are multiple valid expressions, all based on making zero from the remaining numbers using different arithmetic operations.\n</think>\n\nTo solve the problem of forming an expression equal to **109** using **all** the numbers **12, 4, 7, 1, 2, 5, 21, 88** exactly once with the operations **+**, **-**, **\\***, and **/**, we can explore multiple valid strategies that all rely on the core idea of **constructing a zero** using the remaining numbers after identifying the base sum (88 + 21 = 109). This ensures the total remains unchanged while incorporating all numbers.\n\n---\n\n### ✅ **Alternative Strategy 1: Using Division in Zero Construction**\n\nWe construct a zero using division and subtraction:\n\n$$\n\\left( \\frac{12}{7 - 5} - (4 + 2) \\right) \\times 1\n$$\n\n- $ 7 - 5 = 2 $\n- $ \\frac{12}{2} = 6 $\n- $ 4 + 2 = 6 $\n- $ 6 - 6 = 0 $\n- $ 0 \\times 1 = 0 $\n\nNow add this to the base sum:\n\n$$\n88 + 21 + \\left( \\frac{12}{7 - 5} - (4 + 2) \\right) \\times 1 = 88 + 21 + 0 = 109\n$$\n\nAll numbers used exactly once:\n- **88**, **21**, **12**, **7**, **5**, **4**, **2**, **1**\n\n---\n\n### ✅ **Alternative Strategy 2: Grouping Numbers to Form Zero**\n\nUse a different grouping of the remaining numbers:\n\n$$\n(12 - 4 - 7 - 1) \\times (5 - 2)\n$$\n\n- $ 12 - 4 - 7 - 1 = 0 $\n- $ 5 - 2 = 3 $\n- $ 0 \\times 3 = 0 $\n\nAdd to the base sum:\n\n$$\n88 + 21 + (12 - 4 - 7 - 1) \\times (5 - 2) = 88 + 21 + 0 = 109\n$$\n\nAll numbers used exactly once:\n- **88**, **21**, **12**, **4**, **7**, **1**, **5**, **2**\n\n---\n\n### ✅ **Alternative Strategy 3: Using Multiplication of Two Zeros**\n\n$$\n(7 - 4 - 1 - 2) \\times (12 - 5)\n$$\n\n- $ 7 - 4 - 1 - 2 = 0 $\n- $ 12 - 5 = 7 $\n- $ 0 \\times 7 = 0 $\n\nAdd to the base sum:\n\n$$\n88 + 21 + (7 - 4 - 1 - 2) \\times (12 - 5) = 88 + 21 + 0 = 109\n$$\n\nAll numbers used exactly once:\n- **88**, **21**, **7**, **4**, **1**, **2**, **12**, **5**\n\n---\n\n### ✅ **Alternative Strategy 4: Multiplying by 1**\n\n$$\n88 + 21 \\times 1 + (12 - 7 - 5) \\times (4 - 2)\n$$\n\n- $ 12 - 7 - 5 = 0 $\n- $ 4 - 2 = 2 $\n- $ 0 \\times 2 = 0 $\n- $ 21 \\times 1 = 21 $\n\nAdd to the base:\n\n$$\n88 + 21 + 0 = 109\n$$\n\nAll numbers used exactly once:\n- **88**, **21**, **1**, **12**, **7**, **5**, **4**, **2**\n\n---\n\n### ✅ **Alternative Strategy 5: Using Parentheses and Subtraction**\n\n$$\n88 + 21 + \\left( \\frac{4}{2} - (7 - 5) \\right) \\times (12 - 1)\n$$\n\n- $ \\frac{4}{2} = 2 $\n- $ 7 - 5 = 2 $\n- $ 2 - 2 = 0 $\n- $ 12 - 1 = 11 $\n- $ 0 \\times 11 = 0 $\n\nAdd to the base:\n\n$$\n88 + 21 + 0 = 109\n$$\n\nAll numbers used exactly once:\n- **88**, **21**, **4**, **2**, **7**, **5**, **12**, **1**\n\n---\n\n### ✅ Final Answer (One of the Valid Alternatives)\n\n<answer>88 + 21 + (12 - 4 - 7 - 1) * (5 - 2)</answer>",
"Okay, let's tackle this problem again to find more alternative expressions that equal 109 using all the numbers 12, 4, 7, 1, 2, 5, 21, 88 exactly once. The previous solutions all used the base 88 + 21 = 109 and added a zero constructed from the remaining numbers. Maybe there's another way to approach this without starting with 88 + 21. Let's see.\n\nFirst, let's list all the numbers: 12, 4, 7, 1, 2, 5, 21, 88. We need to combine them with +, -, *, / to get 109. Let's consider if there's a different base sum or maybe a product that gets us close to 109.\n\nFor example, 88 is a large number, so maybe 88 plus something else. 88 + 21 is 109, which we've used. What if we do 88 + 20 = 108, but we need 109. Not sure. Let's check other combinations.\n\nAnother thought: 21 * 5 = 105. Then 105 + 4 = 109. So 21*5 + 4 = 109. Now we have to use the remaining numbers: 12, 7, 1, 2, 88. Wait, but we need to use all numbers. So if we do 21*5 + 4, that's using 21,5,4. Then we need to incorporate 12,7,1,2,88. But 88 is a big number, so maybe 88 - something? Wait, 88 is already a large number, so maybe subtract a number to get to 109? Wait, 88 is less than 109, so 88 + 21 is the obvious way. Let's stick to that for now.\n\nWait, but the problem is that 88 + 21 = 109, so we need to use the rest of the numbers in a way that doesn't change the value. So the key is to make a term that equals 0 using the other numbers. Let's confirm the remaining numbers after using 88 and 21: 12,4,7,1,2,5. So we need to make 0 with those six numbers.\n\nWe can try different ways to make 0. For example:\n\n- (12 - 7 - 5) = 0, and then (4 - 2 - 1) = 1, so 0 * 1 = 0. That's the first solution.\n\nAnother way: (12 - 4 - 7 - 1) = 0, and (5 - 2) = 3, so 0 * 3 = 0.\n\nAnother way: (7 - 4 - 1 - 2) = 0, and (12 - 5) = 7, so 0 * 7 = 0.\n\nWhat if we use division? Like (12 / (7 - 5)) - (4 + 2) = (12/2) - 6 = 6 - 6 = 0, then multiply by 1. So ( (12/(7-5)) - (4+2) ) * 1 = 0.\n\nAlternatively, (5 - 2 - 1) = 2, (12 - 7 - 4) = 1, but 2 * 1 = 2, which isn't zero. Wait, no, we need zero.\n\nWait, let's try another combination. Maybe (12 + 5 - 7 - 4 - 2 - 1) = 12+5=17, 7+4+2+1=14, 17-14=3. Not zero.\n\n(12 - 5) = 7, (7 - 4 - 2 - 1) = 0, so 7 * 0 = 0. Wait, that's similar to the earlier strategy. Let's see: (12 - 5) * (7 - 4 - 2 - 1) = 7 * 0 = 0. Then add to 88 + 21.\n\nYes, that's another way. So (12 - 5) * (7 - 4 - 2 - 1) = 7 * 0 = 0. So the expression would be 88 + 21 + (12 - 5) * (7 - 4 - 2 - 1).\n\nLet's check numbers used: 88,21,12,5,7,4,2,1. All used exactly once. Perfect.\n\nLet's verify:\n\n12 -5 =7\n\n7 -4 -2 -1 = 0\n\n7 * 0 = 0\n\n88 +21 +0 = 109. Correct.\n\nAnother possibility: (4 * 2) - (12 - 7 - 5 - 1). Let's compute:\n\n4*2=8\n\n12 -7 -5 -1= -1\n\nSo 8 - (-1)=9. Not zero.\n\nHmm. Maybe (12 - 7) =5, (5 - 2)=3, (4 - 1)=3. 5*3*3=45. Not helpful.\n\nWait, let's think of other ways to get zero. For example, (21 - 21), but we can't use 21 twice. We already used 21 in the base sum. Wait, no, the base sum is 88+21, so 21 is already used, so we can't use it again.\n\nWait, all numbers must be used exactly once, so 21 is part of the base sum, so the remaining numbers are the other six. So we can't use 21 again.\n\nAnother idea: using division to create a zero. Like (something / something) - (something). For example, (12 / 6) - 2 = 0, but we don't have 6. Wait, 7 -1 =6. Let's see:\n\n(12 / (7 - 1)) - (5 - (4 - 2)). Let's compute:\n\n7-1=6, 12/6=2\n\n4-2=2, 5-2=3\n\nSo 2 -3 = -1. Not zero.\n\nAlternatively, ( (12 / (7 - 5)) - (4 + 2) ) * 1. As before, 12/(2)=6, 4+2=6, 6-6=0, times 1=0.\n\nThat's the same as Strategy 1 earlier.\n\nWhat if we do (5 * 2) - (12 - 7 - 4 - 1). Let's see:\n\n5*2=10\n\n12-7-4-1=0\n\nSo 10 -0=10. Not zero.\n\nWait, (5*2) - (12 -7 -4 -1) =10 -0=10. So if we have 88 +21 + (5*2 - (12-7-4-1)) -10, but that's not helpful.\n\nWait, no, we need to use all numbers once. So 5*2 is using 5 and 2, 12-7-4-1 uses 12,7,4,1. Then we have 88 and 21 left. So 88 +21 + (5*2 - (12-7-4-1)) = 109 + (10 -0) = 119. Too big.\n\nNot helpful.\n\nLet's try another approach. Maybe using multiplication and division to reach 109 without starting with 88+21.\n\nFor example, 88 + 21 =109, but what if we do 88 + (21 * something). Wait, 21*5=105, 88+105=193, too big. 21*4=84, 88+84=172. No. 21*1=21, 88+21=109, which is the original base.\n\nHow about 12 * 9 = 108, close to 109. But where to get 9? 7 + 2 =9. So 12*(7+2)=108. Then 108 +1=109. Now we have 12,7,2,1 used. Remaining numbers: 4,5,21,88. Need to use all. So 12*(7+2) +1 + (88 -21 -5 -4). Let's compute:\n\n88-21=67, 67-5=62, 62-4=58. So 108 +1 +58=167. Not 109.\n\nAlternatively, 12*(7+2) +1 = 109. So we need the rest (4,5,21,88) to cancel out. So 12*(7+2) +1 + (something that equals zero using 4,5,21,88). But 4,5,21,88 are all positive and large. How to make zero? Maybe 88 -21 -5 -4=58, which is not zero. So that approach doesn't work.\n\nAnother idea: 21 * 5 = 105. 105 + 4 = 109. So 21*5 +4. Then need to use 12,7,1,2,88. So 21*5 +4 + (88 - 88) + ... but we can't repeat 88. Wait, we have to use all numbers once. So 21*5 +4 uses 21,5,4. Then we have 12,7,1,2,88 left. So we need to make 0 with those. For example, 88 - (12 +7 +1 +2) =88 -22=66. Not zero. 88 - 12*7 +1 +2=88-84+3=7. Not zero.\n\nAlternatively, 88 - (12*7) =88-84=4. Then 4 +1 +2=7. So 21*5 +4 + (88 -12*7 +1 +2) =105+4+7=116. Not 109.\n\nHmm. Maybe 88 is a key number. Let's consider 88 as part of a product. For example, 88 + (something) =109. So something=21, which is the original base.\n\nAnother angle: Maybe use subtraction. Like 88 + 50 =138, too big. 88 + 21=109, as before.\n\nWait, let's think of fractions. Suppose we do 88 + (21 * (something)) but that might not help. Wait, 21 * (5 - (12/4)) =21*(5-3)=21*2=42. Then 88 +42=130. Not helpful.\n\nWait, 12/4=3. Then 7-3=4. 5-1=4. So 4*4=16. Not sure.\n\nWait, let's try a different base. What if we take 21 * 5 =105, then 105 + 4=109. Then we need to use 12,7,1,2,88 in a way that adds zero. So 105 +4 + (88 - 88) + ... but can't repeat. Wait, we have to use 12,7,1,2. So maybe (88 - 88) but no. Wait, 88 is already used in the expression? Wait, no, if we use 21*5 +4, we haven't used 88 yet. So the full expression would be 21*5 +4 + (88 - something). Wait, 21*5=105, 105+4=109. So we need to add zero using 88 and the rest. But 88 is a large number. So 109 + (88 -88) but we can't use 88 twice. So maybe 21*5 +4 + (88 - (12 +7 +1 +2)). Let's compute:\n\n12+7+1+2=22. So 88-22=66. Then 105+4+66=175. Not 109.\n\nAlternatively, 21*5 +4 + (12 -7 -1 -2) -88. That would be 105+4+2 -88=23. Not 109.\n\nNot helpful.\n\nLet's go back to the original idea. The safest way is to have 88 +21 =109, and then make a zero with the other numbers. Let's find all possible ways to make zero with 12,4,7,1,2,5.\n\nPossible combinations for zero:\n\n1. (12 -7 -5) * (4 -2 -1) =0*1=0\n\n2. (12 -4 -7 -1) * (5 -2)=0*3=0\n\n3. (7 -4 -1 -2) * (12 -5)=0*7=0\n\n4. (12 / (7 -5)) - (4 +2) =6-6=0, then *1=0\n\n5. (12 -5) * (7 -4 -2 -1)=7*0=0\n\n6. (5 -2 -1) * (12 -7 -4)=2*1=2 (not zero)\n\n7. (12 -7) - (5 - (4 -2 -1))=5 - (5 - (1))=5-4=1 (not zero)\n\n8. (4*2) - (12 -7 -5 +1)=8 - (12-7=5; 5-5=0; 0+1=1; 8-1=7) Not zero.\n\nSo the valid ones are 1,2,3,4,5.\n\nWait, let's check if there's another way. For example, (5*2) - (12 -7 -4 -1)=10 -0=10, which is not zero, but if we do (5*2) - (12 -7 -4 -1) -10=0, but we can't introduce 10.\n\nAnother way: ((12 - 5) - (7 - 4)) * (2 -1). Let's compute:\n\n12-5=7, 7-4=3, 7-3=4. 2-1=1. 4*1=4. Not zero.\n\nHmm. Let's confirm the fifth way: (12 -5) * (7 -4 -2 -1). 12-5=7, 7-4=3, 3-2=1, 1-1=0. So 7*0=0. Yes, that's valid.\n\nSo that's another expression: 88 + 21 + (12 -5) * (7 -4 -2 -1)\n\nLet's write it out: 88 + 21 + (12 - 5) * (7 - 4 - 2 - 1)\n\nNumbers used: 88,21,12,5,7,4,2,1. All exactly once.\n\nAnother possibility: (21 - (12 - 7 - 5 - 4 + 1)) * something. Wait, let's compute inside: 12-7=5, 5-5=0, 0-4=-4, -4+1=-3. So 21 - (-3)=24. Not helpful.\n\nWait, maybe using division in the zero. For example, ( (12 / (5 - 1)) - (7 - 4) ) * 2. Let's see:\n\n5-1=4, 12/4=3. 7-4=3. 3-3=0. 0*2=0. So that's a way to make zero: (12/(5-1) - (7-4)) *2 =0.\n\nLet's verify:\n\n5-1=4\n\n12/4=3\n\n7-4=3\n\n3-3=0\n\n0*2=0\n\nSo the expression would be 88 +21 + (12/(5-1) - (7-4)) *2\n\nCheck numbers used: 88,21,12,5,1,7,4,2. All exactly once.\n\nYes! This is another valid solution.\n\nLet's verify step by step:\n\n- 5 - 1 = 4\n\n- 12 / 4 = 3\n\n- 7 - 4 = 3\n\n- 3 - 3 = 0\n\n- 0 * 2 = 0\n\n- 88 + 21 + 0 = 109\n\nPerfect. All numbers used exactly once.\n\nThis is a new alternative strategy. Let's check if this uses all numbers:\n\n- 88: yes\n\n- 21: yes\n\n- 12: yes\n\n- 5: yes\n\n- 1: yes\n\n- 7: yes\n\n- 4: yes\n\n- 2: yes\n\nAll accounted for.\n\nSo this is a valid alternative.\n\nAnother way: ( (7 * 2) - 12 ) * (5 - (4 + 1)) \n\nCompute:\n\n7*2=14, 14-12=2\n\n4+1=5, 5-5=0\n\n2*0=0\n\nThen 88 +21 +0=109.\n\nNumbers used: 7,2,12,5,4,1. Wait, 5 - (4+1) uses 5,4,1. So all numbers: 88,21,7,2,12,5,4,1. All used once.\n\nYes! Let's verify:\n\n- 7*2 =14\n\n- 14 -12=2\n\n- 4+1=5\n\n- 5-5=0 (wait, 5 - (4+1)=5-5=0)\n\n- 2*0=0\n\n- 88+21+0=109\n\nYes, this works.\n\nSo the expression is 88 + 21 + ( (7 * 2) - 12 ) * (5 - (4 + 1))\n\nLet's check numbers: 88,21,7,2,12,5,4,1. All present exactly once.\n\nAnother valid solution.\n\nLet's count how many we have now:\n\n1. 88 + 21 + (12 - 7 - 5) * (4 - 2 - 1)\n\n2. 88 + 21 + (12 - 4 - 7 - 1) * (5 - 2)\n\n3. 88 + 21 + (7 - 4 - 1 - 2) * (12 - 5)\n\n4. 88 + 21 + (12 / (7 - 5) - (4 + 2)) * 1\n\n5. 88 + 21 + (12 - 5) * (7 - 4 - 2 - 1)\n\n6. 88 + 21 + (12 / (5 - 1) - (7 - 4)) * 2\n\n7. 88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1))\n\nLet's verify the seventh one:\n\n(7*2 -12) =14-12=2\n\n(5 - (4+1))=5-5=0\n\n2*0=0\n\nYes, that's correct.\n\nIs there a way to use subtraction in the base sum instead? Like 88 + something =109, so something=21, which is already covered.\n\nAnother idea: 88 + 21 + 0 =109, and 0 can be formed in multiple ways. Let's see if there's a way to use division in a different manner.\n\nFor example, ( (12 + 5) - (7 + 4 + 2 + 1) ) =17 -14=3. Not zero.\n\n( (12 + 7) - (5 + 4 + 2 + 1) )=19-12=7. Not zero.\n\n( (5 + 4 + 2) - (12 - 7 + 1) )=11 - (6)=5. Not zero.\n\nHmm. So the main ways are using products of zero with the remaining numbers.\n\nLet's confirm the sixth solution:\n\n88 + 21 + (12 / (5 - 1) - (7 - 4)) * 2\n\nCompute inside the parentheses:\n\n5-1=4\n\n12/4=3\n\n7-4=3\n\n3-3=0\n\n0*2=0\n\nSo total is 88+21+0=109. Correct.\n\nAnother possible variation: 88 + 21 + ( (4 * 2) - (12 - 7 - 5) ) * 1\n\nCompute:\n\n4*2=8\n\n12-7-5=0\n\n8-0=8\n\n8*1=8\n\nSo 88+21+8=117. Not 109. So that's not good.\n\nWait, but if we do ( (12 - 7 - 5) - (4 - 2) ) *1 = (0 -2)*1=-2. Then 88+21-2=107. Not 109.\n\nSo that's bad.\n\nAnother try: ( (5 * 2) - (12 - 7 - 4 - 1) ) =10 -0=10. So 88+21+10=119. Not good.\n\nWait, but if we do 88 + (21 - 10) = 88+11=99, no.\n\nHmm. Let's stick to the valid ones we found.\n\nSo the seventh solution is valid: 88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1))\n\nLet's write it properly with parentheses:\n\n88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1))\n\nYes.\n\nLet's check the numbers again:\n\n- 7, 2, 12 in the first part.\n\n- 5, 4, 1 in the second part.\n\n- 88 and 21.\n\nAll numbers used once.\n\nYes.\n\nAnother possible way: ( (12 - 4) * (7 - 5) ) - (2 + 1) = (8*2) -3=16-3=13. Not zero.\n\nNot helpful.\n\nWait, let's think of another zero. (21 - 21) but can't reuse 21.\n\nNo.\n\nOkay, so the main alternative strategies are the ones we've found, each using a different way to form zero with the six remaining numbers.\n\nLet's list all the valid expressions we have:\n\n1. 88 + 21 + (12 - 7 - 5) * (4 - 2 - 1)\n\n2. 88 + 21 + (12 - 4 - 7 - 1) * (5 - 2)\n\n3. 88 + 21 + (7 - 4 - 1 - 2) * (12 - 5)\n\n4. 88 + 21 + (12 / (7 - 5) - (4 + 2)) * 1\n\n5. 88 + 21 + (12 - 5) * (7 - 4 - 2 - 1)\n\n6. 88 + 21 + (12 / (5 - 1) - (7 - 4)) * 2\n\n7. 88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1))\n\nEach of these uses all numbers exactly once and evaluates to 109.\n\nThe user asked to continue exploring alternative solution strategies, so we can present one more of these as a new alternative.\n\nLet's pick the seventh one as it's a bit different, using multiplication (7*2) and subtraction.\n\nSo the expression is:\n\n88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1))\n\nLet's verify once more:\n\n- 7 * 2 = 14\n\n- 14 - 12 = 2\n\n- 4 + 1 = 5\n\n- 5 - 5 = 0\n\n- 2 * 0 = 0\n\n- 88 + 21 + 0 = 109\n\nAll numbers used: 88, 21, 7, 2, 12, 5, 4, 1. Perfect.\n\nThis is a valid alternative.\n</think>\n\n<answer>88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1))</answer>",
"Okay, let's see. The user wants me to continue exploring alternative strategies to form 109 using all the numbers 12, 4, 7, 1, 2, 5, 21, 88 exactly once. The previous solutions all used 88 + 21 plus a zero constructed from the other numbers. But maybe there's another approach where we don't start with 88 + 21. Let me think.\n\nFirst, let's list all the numbers again: 12, 4, 7, 1, 2, 5, 21, 88. Total of 8 numbers. We need to use each once with +, -, *, /.\n\nAnother idea: Maybe combine some numbers to get close to 109 and then adjust with the rest. Let's see, 88 is the largest number. 88 + 21 is 109, but maybe if we use other combinations. Wait, 88 + 21 is exactly 109, so that's a good base. But maybe the user wants to see different ways to form zero, not just the same pattern.\n\nWait, the previous answer they provided was 88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1)). Let's check that:\n\nFirst, calculate the parts:\n\n7 * 2 = 14. 14 - 12 = 2.\n\nThen, 4 + 1 = 5. 5 - 5 = 0.\n\nSo 2 * 0 = 0. Then 88 + 21 + 0 = 109. All numbers used: 88,21,7,2,12,5,4,1. Yes, all exactly once.\n\nSo that's another way to make zero. The key is to make a product that equals zero. So either one of the factors is zero, or the whole thing is multiplied by zero.\n\nLet me try to find another way. Maybe using division to create a zero. Wait, division by zero is undefined, so we can't have that. So better to have a subtraction that equals zero.\n\nLet's think of other combinations for the zero part. Let's list the remaining numbers after 88 and 21: 12,4,7,1,2,5.\n\nWe need to make zero using these six numbers. Let's try different groupings.\n\nFor example, (12 - 5 - 7) * (4 - 2 - 1). Wait, 12-5-7=0, 4-2-1=1, so 0*1=0. That's the first solution they had.\n\nAnother way: (5 - (4 + 1)) * (7 - (12 / 2)). Let's check: 4+1=5, so 5-5=0. 12/2=6, 7-6=1. So 0*1=0. So that's similar to the one they provided.\n\nWait, the user's last answer was 88 + 21 + ((7 * 2) - 12) * (5 - (4 + 1)). Let's break that down:\n\n(7*2 -12) = 14-12=2\n\n(5 - (4+1)) =5-5=0\n\n2*0=0. So same as before.\n\nSo the zero comes from the second part being zero. So any way to make the second part zero will work.\n\nAnother possibility: (12 - (7 + 5)) * (4 - 2 - 1). 12-12=0, 4-3=1, so 0*1=0. That's another way.\n\nWait, but maybe using division. Let's see. For example, ( (12 / 4) - 3 ) but 3 isn't a number we have. Wait, numbers are 12,4,7,1,2,5. Let's see:\n\nSuppose we do ( (7 + 5) - 12 ) * ( (4 * 2) - 8 ), but 8 isn't in the numbers. Hmm. Wait, maybe not.\n\nAlternatively, ( (5 * 2) - 10 ) * something. 5*2=10, but 10 isn't a number here. Wait, 12 - 2 =10. So (5*2 - (12 - 2)) but that uses 2 twice. Not allowed.\n\nWait, let's think of another zero. Let's say ( (4 * 1) - 4 ), but 4 is used once. No, we can't use 4 twice.\n\nWait, maybe ( (7 - 1) - 6 ), but 6 isn't a number. Hmm.\n\nAlternatively, ( (12 - 5) - 7 ) * (4 - 2 - 1). 12-5=7, 7-7=0. So 0*1=0. So that's (12 -5 -7) * (4 -2 -1) =0*1=0. Which is the same as the first solution.\n\nAnother way: Let's see if we can get zero using division. For example, ( (7 * 2) / 14 - 1 ), but 14 isn't a number. Wait, but 7*2=14, and 14-14=0. But 14 isn't one of our numbers. Wait, but we have 12. 14-12=2. Not helpful.\n\nWait, maybe ( (5 - 2) - 3 ) * something. But 3 isn't there. Hmm.\n\nAlternatively, ( (4 + 1) - 5 ) * (12 - 7 - 2). Let's check: 4+1=5, 5-5=0. 12-7-2=3. So 0*3=0. Yes! So that's another way.\n\nSo the expression would be 88 + 21 + ( (4 + 1) - 5 ) * (12 - 7 - 2 ). Let's verify:\n\n(4+1)=5, 5-5=0.\n\n12-7=5, 5-2=3.\n\n0*3=0.\n\n88+21+0=109.\n\nNumbers used: 88,21,4,1,5,12,7,2. All exactly once. Perfect.\n\nSo this is another valid solution. Let's write that out:\n\n88 + 21 + ((4 + 1) - 5) * (12 - 7 - 2)\n\nLet me check if all numbers are used once:\n\n- 88: yes\n- 21: yes\n- 4: yes\n- 1: yes\n- 5: yes\n- 12: yes\n- 7: yes\n- 2: yes\n\nAll numbers used. Perfect.\n\nAnother one: ( (2 * 5) - 10 ) * something. Wait, 2*5=10. But 10 isn't a number. Wait, but 12 - 2 =10. So (2*5 - (12 - 2)) but that uses 2 twice. Not allowed.\n\nHow about ( (7 + 5) - (12) ) * ( (4 * 1) - 2 ). Let's compute:\n\n7+5=12, 12-12=0.\n\n4*1=4, 4-2=2.\n\n0*2=0. So 88+21+0=109.\n\nNumbers used: 7,5,12,4,1,2. Plus 88 and 21. All good.\n\nSo expression: 88 + 21 + (7 + 5 - 12) * (4 * 1 - 2)\n\nCheck:\n\n7+5-12=0\n\n4*1-2=2\n\n0*2=0\n\n88+21=109. Correct.\n\nNumbers used: 88,21,7,5,12,4,1,2. All exactly once.\n\nThat's another valid expression.\n\nLet me think of another way. Maybe using division in the zero part. For example:\n\n( (12 / (7 - 5)) - (4 + 2) ) * 1. Let's compute:\n\n7-5=2. 12/2=6. 4+2=6. 6-6=0. 0*1=0.\n\nSo expression: 88 + 21 + (12 / (7 - 5) - (4 + 2)) * 1\n\nNumbers used: 88,21,12,7,5,4,2,1. All good.\n\nThis is the same as one of the earlier alternatives I thought of. So this is valid.\n\nAnother idea: What if we use a different base instead of 88 + 21? Let's see if there's a way to get 109 without using 88 + 21 as the main sum. For example, 88 + something else.\n\nSuppose 88 + 20 +1, but 20 and 1. But 20 would need to be made from other numbers. Let's see.\n\nWait, 21 is a number, so 88 + 21 is the closest. Let's check other combinations. Let's say 88 + 5 * something.\n\n88 + 5 * 4 = 88 + 20 = 108. Close to 109, but need to add 1. But then numbers used: 88,5,4,1. Remaining numbers: 12,7,2,21. Not sure.\n\nWait, 88 + 5 * 4 + 1 = 109, but then we need to use 12,7,2,21. How? If we do 88 + 5*4 +1 + (21 - 12 -7 -2). Let's compute that:\n\n21-12=9, 9-7=2, 2-2=0. So total is 88 +20 +1 +0=109.\n\nSo expression: 88 + 5*4 +1 + (21 -12 -7 -2)\n\nCheck numbers:\n\n88,5,4,1,21,12,7,2. All used once.\n\nYes! Let's verify:\n\n5*4=20\n\n20 +1=21\n\n88 +21=109\n\n21-12-7-2=0\n\nSo total: 109 +0=109.\n\nThis is a different structure where the zero is added at the end, but still uses all numbers.\n\nSo the expression would be 88 + 5 * 4 + 1 + (21 - 12 - 7 - 2).\n\nLet me check the operations: multiplication comes before addition, so it's 88 + (5*4) +1 + (21-12-7-2).\n\nYes, that's correct.\n\nThis is a valid solution that doesn't start with 88 +21 as the main sum. Instead, it's 88 + 20 +1 +0 =109.\n\nThis is a good alternative strategy. Let's confirm all numbers are used:\n\n88, 5, 4, 1, 21, 12, 7, 2. All present once. Perfect.\n\nAnother way: Let's see if we can use division. For example, 88 + (21 * (something)) but 21*5=105, 88+105=193 which is too big. Not helpful.\n\nWait, 88 + 21 =109, so maybe another way to get 21 from other numbers? But 21 is one of the given numbers, so we have to use it as is.\n\nWait, no, we have to use each number once, so 21 is a number we must include. So we can't replace 21 with another expression; it has to be used as 21.\n\nWait, but in the previous solution, 21 is used as part of the zero: (21 -12 -7 -2). So 21 is used in the subtraction.\n\nSo in that solution, the 21 isn't added directly but is part of the zero expression.\n\nSo that's a different approach. So the main sum is 88 +5*4 +1, and then the rest form zero.\n\nThis is a different structure than the previous ones, which is good.\n\nLet's check the arithmetic again:\n\n5*4 =20\n\n88 +20 =108\n\n108 +1 =109\n\n21 -12 =9\n\n9 -7=2\n\n2 -2=0\n\nSo total is 109 +0=109. Correct.\n\nSo this is another valid solution.\n\nAnother possibility: 88 + 21 - (something that equals zero). But 88+21 is already 109, so subtracting zero would still give 109. But same as adding zero.\n\nWait, but the key is to use all numbers. So the zero expression has to use the remaining six numbers.\n\nSo the previous examples all use the remaining numbers to make zero.\n\nLet's think of another zero expression. Let's say ( (12 - 5 - 7) * (4 - 2 - 1) ), which is 0*1=0, as before.\n\nOr ( (5 * 2) - (12 - 2) ) but that uses 2 twice. Not allowed.\n\nWait, how about ( (7 - 5) * (4 - 2) ) - (12 / 6). But 6 isn't a number. Hmm.\n\nAlternatively, ( (7 - 5) * (4 - 2) ) * 1 - (12 / 12). But 12/12 would require using 12 twice. Not allowed.\n\nWait, let's think of using all six numbers in a single expression that equals zero. For example:\n\n(12 - 4 - 7 - 1) * (5 - 2) = (0) * (3) =0. Which we've used before.\n\nAnother one: ( (12 + 5) - (7 + 10) ), but 10 isn't a number. Wait, 12+5=17, 7+ (4*2 +1)=7+9=16. Not zero.\n\nWait, maybe ( (4 * 2) + 1 ) - (12 - 7 + 5). Let's compute:\n\n4*2=8 +1=9.\n\n12-7=5 +5=10.\n\n9 -10= -1. Not zero.\n\nHmm. Not helpful.\n\nWait, let's try ( (5 * 4) - 12 ) * ( (7 - 2) - 1 ). Compute:\n\n5*4=20 -12=8.\n\n7-2=5 -1=4.\n\n8*4=32. Not zero.\n\nNot helpful.\n\nHow about ( (7 * 2) - 14 ) * (12 / (5 + 4 + 1)). 14 isn't a number. 7*2=14. 5+4+1=10. 12/10=1.2. So (14-14)=0. Wait, but 14 isn't a number. Wait, 7*2=14, so (7*2 -14) but 14 isn't a number. So we can't write that. But if we use 12, which is close to 14. 7*2=14, 14-12=2. So (7*2 -12)=2. Then multiply by something to get zero. Like (7*2 -12)*(something that is zero). But that's the same as the user's last answer.\n\nSo maybe we're going in circles here.\n\nLet's go back to the solution where we have 88 + 5*4 +1 + (21 -12 -7 -2). That's a good alternative.\n\nAnother one: 21 * 5 = 105. Then 105 + 4 = 109. So 21*5 +4 =109. Then we need to use the remaining numbers: 12,7,1,2,88. Wait, but 88 is a big number. So 21*5 +4 =109, but then we have to incorporate 88, 12,7,1,2. If we do 21*5 +4 + (88 -88) + (12 -12) etc., but we can't reuse numbers. So we need to use all of them. So perhaps:\n\n21*5 +4 + (88 - 88) + ... but no, we can't use 88 twice.\n\nWait, better to use the remaining numbers to form zero. So 21*5 +4 =109, and then the rest (88,12,7,1,2) need to form zero. But 88 is a large number, so maybe 88 - (12 +7 +1 +2)*something. Wait:\n\n88 - (12 +7 +1 +2) =88 -22=66. Not zero.\n\nBut if we do 88 - (12*7 - (1*2)). Let's compute 12*7=84, 1*2=2, 84-2=82. 88-82=6. Not zero.\n\nHmm. Not helpful.\n\nAlternatively, (88 / (12 - (7 + 1 + 2))) * something. 7+1+2=10. 12-10=2. 88/2=44. Not sure.\n\nThis seems more complicated. The original approach of using 88+21 as the base is probably the most straightforward, as 88+21=109.\n\nBut the user wants to explore other strategies, so let's confirm the solution I came up with earlier:\n\n88 + 5*4 + 1 + (21 - 12 - 7 - 2)\n\nLet's write it out with parentheses to ensure order of operations:\n\n88 + (5 * 4) + 1 + (21 - 12 - 7 - 2)\n\nCalculating step by step:\n\n5 * 4 = 20\n\n21 - 12 = 9\n\n9 - 7 = 2\n\n2 - 2 = 0\n\nSo:\n\n88 + 20 + 1 + 0 = 109\n\nYes, correct.\n\nAll numbers used: 88,5,4,1,21,12,7,2. Perfect.\n\nAnother way: 88 + 21 + ( (12 - 7) - 5 ) * (4 + 2 - 1 )\n\nCompute:\n\n12-7=5, 5-5=0.\n\n4+2=6, 6-1=5.\n\n0*5=0.\n\nSo 88+21+0=109.\n\nNumbers used: 88,21,12,7,5,4,2,1. All present.\n\nYes, this is valid.\n\nSo the expression is 88 + 21 + ((12 - 7) - 5) * (4 + 2 - 1)\n\nLet's verify:\n\n(12-7)=5, 5-5=0\n\n(4+2-1)=5\n\n0*5=0\n\n88+21=109.\n\nCorrect.\n\nSo that's another alternative.\n\nI think the key insight is that as long as we can form a zero with the remaining numbers, we can add it to 88+21 without changing the value. And there are multiple ways to form that zero using different groupings of the six remaining numbers.\n\nSo, to recap, the main strategies are:\n\n1. Use 88 + 21 as the base.\n2. Form a zero using the other six numbers with arithmetic operations.\n3. Add the zero to the base sum.\n\nThe user's last answer was one such example. Now, I need to provide another one.\n\nLet's confirm the one I had: 88 + 5*4 + 1 + (21 - 12 - 7 - 2). This is valid.\n\nAnother one: 88 + 21 + ( (5 - (4 + 1)) * (12 - 7 - 2) )\n\nWait, 4+1=5, 5-5=0. 12-7=5-2=3. 0*3=0. So yes, same as before.\n\nBut let's write it as:\n\n88 + 21 + (5 - (4 + 1)) * (12 - 7 - 2)\n\nNumbers used: 88,21,5,4,1,12,7,2. All good.\n\nThis is another valid expression.\n\nI think this is enough. The user wants to see alternative strategies, so providing another valid expression that uses the zero method but with a different grouping should suffice.\n\nLet me pick one that's different from the previous ones. How about:\n\n88 + 21 + ( (12 + 5) - (7 + 10) ), but wait, 10 isn't a number. No.\n\nWait, let's use the earlier one where we have 88 + 5*4 + 1 + (21 - 12 -7 -2). Let's write that out clearly.\n\nFinal Answer:\n\n<answer>88 + 5 * 4 + 1 + (21 - 12 - 7 - 2)</answer>\n</think>\n\n<answer>88 + 5 * 4 + 1 + (21 - 12 - 7 - 2)</answer>"
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{
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"canonical_form": "x = 21",
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{
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{
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{
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{
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{
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{
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{
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{
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{
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},
{
"canonical_form": "88 + 21 + 0 = 109",
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{
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"span_text": "12 -7 -5=0",
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{
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{
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{
"canonical_form": "12 - 7 - 5 = 0",
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"canonical_form": "(12 - 7 - 5) * (4 - 2 - 1) = 0",
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{
"canonical_form": "109 + 0 = 109",
"canonical_key": "arith:0+109->109",
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"span_text": "109 + 0",
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"canonical_form": "88 + 21 = 109",
"canonical_key": "arith:21+88->109",
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"span_text": "88, 21 used in the main sum",
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"canonical_form": "12 + 7 + 5 = 24",
"canonical_key": "arith:7+12->24",
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},
{
"canonical_form": "4 + 2 + 1 = 7",
"canonical_key": "arith:2+4->7",
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"span_text": "4, 2, 1 used in the second parenthesis",
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{
"canonical_form": "21 * 5 = 105",
"canonical_key": "arith:5*21->105",
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{
"canonical_form": "105 + 4 = 109",
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{
"canonical_form": "12 * 7 = 84",
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{
"canonical_form": "88 + x = 109",
"canonical_key": "expr:88 + x = 109",
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{
"canonical_form": "31 - x = 21",
"canonical_key": "expr:31 - x = 21",
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},
{
"canonical_form": "x = 21",
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},
{
"canonical_form": "88 + 21 + (12 - 7 - 5) * (4 - 2 - 1) = 109",
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"span_text": "88 + 21 + (12 - 7 - 5) × (4 - 2 - 1)",
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},
{
"canonical_form": "12 - 7 - 5 = 0",
"canonical_key": "arith:12-7->0",
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"span_text": "12 - 7 - 5 = 0",
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},
{
"canonical_form": "4 - 2 - 1 = 1",
"canonical_key": "arith:4-2->1",
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"span_text": "4 - 2 - 1 = 1",
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},
{
"canonical_form": "0 * 1 = 0",
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"span_text": "0 \\times 1 = 0",
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},
{
"canonical_form": "88 + 21 + 0 = 109",
"canonical_key": "arith:21+88->109",
"end_char": 30678,
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"span_text": "88 + 21 + 0 = 109",
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},
{
"canonical_form": "x = 109.",
"canonical_key": "expr:x = 109.",
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"span_text": "expression evaluates to **109**",
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},
{
"canonical_form": "x = 109.",
"canonical_key": "expr:x = 109.",
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"span_text": "All numbers are used **exactly once**, and the expression evaluates to **109**.",
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},
{
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},
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},
{
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},
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{
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{
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"canonical_form": "100 - 88 = 12",
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},
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"separator_raw": null,
"span_text": "31 - (something) = 21",
"start_char": 0,
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},
{
"canonical_form": "x = 21",
"canonical_key": "expr:x = 21",
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"separator_raw": null,
"span_text": "make something equal to 21",
"start_char": 0,
"start_char_in_round": null
},
{
"canonical_form": "88 + 21 + (12 + 5) - (7 + 10) = 109",
"canonical_key": "arith:21+88->109",
"end_char": 72360,
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"operator": "+",
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"result": 109,
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"separator_raw": null,
"span_text": "88 + 21 + ( (12 + 5) - (7 + 10) )",
"start_char": 72327,
"start_char_in_round": null
},
{
"canonical_form": "88 + 5 * 4 + 1 + (21 - 12 - 7 - 2) = 109.",
"canonical_key": "arith:5+88->109",
"end_char": 72472,
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"span_text": "88 + 5*4 + 1 + (21 - 12 -7 -2)",
"start_char": 72442,
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},
{
"canonical_form": "5 * 4 = 20",
"canonical_key": "arith:4*5->20",
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"operator": "*",
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"span_text": "5*4",
"start_char": 72447,
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},
{
"canonical_form": "21 - 12 - 7 - 2 = 0",
"canonical_key": "arith:21-12->0",
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}
]
] |
[
[
"88 + 21 = 109.",
"x = 109",
"109 - 88 = 21",
"88 + 21 = 109",
"88 + x = 109",
"88 + x = 109",
"88 + 21 = 109",
"88 + 21 = 109",
"88 + x = 109",
"x = 21",
"12 + 4 + 7 + 1 + 2 + 5 = 31",
"x = y",
"88 + x = 109",
"31 - x = 21",
"109 - 88 = 21",
"88 + 21 = 109",
"12 - 4 - 7 - 1 - 2 - 5 = -7",
"12 - 4 = 8",
"8 - 7 = 1",
"1 - 1 = 0",
"0 - 2 = -2",
"-2 - 5 = -7",
"12 - 12 = 0",
"88 + x = 109",
"x = 0",
"88 + 21 = 109",
"(88 + 21) * x = 1",
"88 + 21 + 12 - 12 = 109",
"88 + 12 = 100",
"100 + 9 = 109",
"21 - 12 = 9",
"88 + 12 = 100",
"100 + 9 = 109",
"x = 21",
"21 - 12 = x",
"88 + 21 = 109",
"88 + 21 + 12 - 12 = 109",
"88 + 21 + 12 - 12 = 109",
"88 + x = 109",
"x + 21 + 88 = 0",
"12 - 12 = 0",
"12 - 4 - 7 - 1 + 2 - 5 = -3",
"12 - 4 = 8",
"8 - 7 = 1",
"1 - 1 = 0",
"0 + 2 = 2",
"2 - 5 = -3",
"88 + 21 = 109",
"12 / 12 = 1",
"x / y = 1",
"12 - 7 - 4 + 1 + 2 - 5 = -1",
"12 - 7 = 5",
"5 - 4 = 1",
"1 + 1 = 2",
"2 + 2 = 4",
"4 - 5 = -1",
"5 - (4 - (2 - 1)) = 2",
"5 - (4 - 1) = 2",
"5 - 3 = 2",
"21 * 5 = 105",
"105 + 4 = 109",
"(21 * 5 + 4) + (88 - 88) = 109",
"88 + 21 = 109",
"88 + 21 + 12 - 12 = 109",
"88 + 21 + (12 - 12) * x = 109",
"12 * 7 = 84",
"84 + 21 = 105",
"105 + 4 = 109",
"(12 * 7 + 21 + 4) + (88 - 88) = 109",
"88 - 88 = 0",
"12 * 7 + 21 + 4 + (5 - 5) = 84 + 21 + 4 + 0 = 109",
"1 * 2 * 5 = 10",
"10 - 88 = -78",
"84 + 21 + 4 - 78 = 109",
"84 + 21 = 105",
"109 - 78 = 31",
"5 - (2 + 1) = 2",
"88 / 2 = 44",
"21 - 44 = -23",
"84 - 23 = 61",
"2 * x = 31",
"88 + 21 = 109.",
"21 - 5 = 16",
"88 + (21 * x) = y",
"21 * 5 = 105",
"88 + 105 = 193",
"21 - x = 21",
"x = 0",
"x = 21",
"5 * 21 = 105",
"105 + 4 = 109",
"5 * 21 + 4 = 109",
"88 - 88 = 0",
"5 * 21 + 4 = 109",
"5 * 21 + 4 = 109",
"88 - 88 = 0",
"88 / 2 = 44",
"(7 - (1 + 2)) = 4",
"(12 / (7 - (1 + 2))) = 3",
"(88 / (12 / (7 - (1 + 2)))) = 29.3333",
"5 * 21 = 105",
"1 + 2 = 3",
"7 - 3 = 4",
"12 / 4 = 3",
"5 * 21 = 105",
"88 + 12 = 100",
"100 + 7 + 2 = 109",
"88 + 12 + 7 + 2 = 109",
"88 + 12 + 7 + 2 + (x - y) = 109",
"(4 - 4) = 0",
"21 - 5 - (4 + 1) = 11",
"21 - 5 - 5 = 11",
"(88 + 12 + 7 + 2) * (21 / 21) = 109 * 1 = 109.",
"88 + 12 + 7 + 2 = 109",
"21 / 21 = 1",
"109 * 1 = 109",
"88 + 21 - x = 109",
"88 + 21 = 109",
"109 - x = 109",
"x = 0",
"x = 0",
"88 + (21 * x) = y",
"21 * (5 - (4 / x)) = y",
"88 + 21 = 109",
"(5 - (1 + 2 + 4)) * (12 - 7) = x",
"5 - 7 = -2",
"12 - 7 = 5",
"-2 * 5 = -10",
"88 + 21 + (-10) = 109 - 10 = 99",
"5 * 4 - 1 - 2 = 17",
"5 * 4 = 20",
"1 + 2 = 3",
"17 * 6 = 102",
"12 * 8 = 96",
"12 * 9 = 108",
"108 + 1 = 109",
"12 * (7 + x) = 108",
"7 + x = 9",
"x = 2",
"108 + 1 = 109",
"12 * (7 + 2) + 1 = 109",
"(88 / 88) = 1",
"(21 - 21) = 0",
"12 * (7 + 2 + (88 - 88)) + 1 = 13",
"88 + (21 * (5 - (4 + 1) / 2)) = 140.5",
"(4 + 1) = 5",
"5 / 2 = 2.5",
"5 - 2.5 = 2.5",
"21 * 2.5 = 52.5",
"88 + 52.5 = 140.5",
"21 * 5 = 105",
"105 + 4 = 109",
"(21 * 5) + (88 / (12 - (7 + (2 - 1)))) = x",
"2 - 1 = 1",
"7 + 1 = 8",
"12 - 8 = 4",
"88 / 4 = 22",
"105 + 22 = 127",
"88 / x = x",
"21 * 5 + x = 109",
"x = 4",
"88 / x = 4",
"x = 22",
"12 + 7 + (2 - 1) = 20",
"12 + 7 + 2 - 1 = 20",
"12 * 2 = 24",
"24 - (7 - 1) = 18",
"12 + (7 * 2) - 1 = 25",
"109 - 88 = 21",
"88 + 21 = 109",
"x * 1 = 0 or x + 0 = 0",
"(x/y) = 1",
"4 - 2 = 2",
"5 - 2 = 3",
"12 - 7 = 5",
"5 - 3 = 2",
"2 / 1 = 2",
"5 - (4 + 2 - 1) = 0",
"0 / 5 = 0",
"4 + 2 = 6",
"12 / 6 = 2",
"7 - 5 = 2",
"2 * 2 = 4",
"4 / 1 = 4",
"4 + 2 = 6",
"7 - 6 = 1",
"5 - 1 = 4",
"12 - 7 = 5",
"5 - 4 = 1",
"2 - 1 = 1",
"4 / 1 = 4",
"12 / 4 = 3",
"5 - 2 = 3",
"3 - 3 = 0",
"0 / 6 = 0",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109",
"5 - 5 = 0",
"88 + 21 = 109",
"88 + 21 + 5 - 5 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 1 - 1 = 109",
"88 + 21 + 12 - 12 = 109",
"5 + 2 - (4 + 3) = x",
"12 - 7 - (5 - (4 - (2 - 1))) = x",
"2 - 1 = 1",
"4 - (2 - 1) = 3",
"5 - 3 = 2",
"12 - 7 = 5",
"5 - 2 = 3",
"21 * 5 = 105",
"105 + 4 = 109",
"88 + 21 = 109",
"100 - 88 = 12",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 12 - 12 = 109",
"x = 21",
"88 + x = 109",
"88 + 21 = 109",
"88 + (21 * ((5 - (4 / 2)) / (12 - 7 - 1))) = x",
"4 / 2 = 2",
"12 - 7 - 1 = 4",
"5 - (4 / 2) = 3",
"21 * ((5 - (4 / 2)) / (12 - 7 - 1)) = x",
"88 + (21 * ((5 - (4 / 2)) / (12 - 7 - 1))) = x",
"4 / 2 = 2",
"5 - 2 = 3",
"12 - 7 - 1 = 4",
"21 * 1 = 21",
"88 + 21 = 109",
"12 - 7 - x = 3",
"12 - 7 = 5",
"5 - x = 3",
"12 - 7 - 2 = 3",
"88 + [21 * ( (5 - (4 / (1 + 2))) / (12 - 7) )] = x",
"12 - 7 = 5",
"21 * ( (5 - (4 / (1 + 2))) / (12 - 7) ) = y",
"(5 - (4 / (1 + 2))) / (12 - 7) = z",
"1 + 2 = 3",
"12 - 7 = 5",
"12 - 7 - 2 = 3",
"21 * (1/3) = 7",
"88 + 7 = 95",
"88 + (21 - x) = 109",
"x = 21 + 88 - 109 = 0",
"x = 0",
"88 + 21 - 12 + 12 = 109",
"88 + (21 * x) = 109",
"21 * 1 = 21",
"88 + 21 = 109",
"x = 1",
"x = 1, 12, 4, 7, 1, 2, 5 = 1.",
"4 - 2 = 2",
"5 - 2 = 3",
"12 - 7 = 5",
"5 - 3 = 2",
"2 / 1 = 2",
"12 / (7 - (5 - 2)) = 3",
"5 - 2 = 3",
"7 - 3 = 4",
"12 / 4 = 3",
"4 - 1 = 3",
"3 - 3 = 0",
"0 * 1 = 0",
"12 - 7 - 5 = 0",
"4 - 2 - 1 = 1",
"(12 - 7 - 5) / (4 - 2 - 1) = 0",
"(5 - 5) / 1 = 0",
"0 / 1 = 0",
"5 - 4 = 1",
"5 - 4 = 1",
"5 - 4 = 1",
"5 - 4 = 1",
"12 - 7 - 2 - 1 = 2",
"12 / (7 + 2 + 1) = 12 / 10 = 1.2",
"5 - 4 = 1",
"x = x",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 * 7 = 84",
"84 + 21 = 105",
"105 + 4 = 109",
"(12 * 7 + 21 + 4) + (88 - 88) = 109",
"5 - (2 + 1) = 2",
"109 * (2 / 2) = 109",
"88 / 88 = 1",
"12 * 7 + 21 + 4 + (5 - 5) = 84 + 21 + 4 + 0 = 109",
"88 + x = 109",
"9 * 12 + 1 = 109",
"9 * 12 + 1 = 109",
"21 - 12 = 9",
"21 - x = 9",
"21 - 12 = 9",
"9 * 12 + 1 = 109 ",
"(5 + 4) * 12 + 1 = 109",
"(5 + 4) * 12 + 1 * (88 / 88) = 109 * 1 = 109.",
"5 + 4 = 9",
"(5 + 4) * 12 = 108",
"88 / 88 = 1",
"109 * 1 = 109",
"(5 + 4) * 12 + 1 + (21 - 21) = 61 + 0 = 61.",
"21 - 21 = 0",
"5 + 4 = 9",
"(5 + 4) * 12 = 108",
"(5 + 4) * 12 + 1 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"88 + 21 = 109",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + (88 / (12 / (7 - (4 - 2)))) + 1 = x",
"7 - (4 - 2) = 5",
"88 / (12 / 5) = x",
"12 / 5 = x",
"4 - 2 = 2",
"4 - 2 = 2",
"7 - 2 = 5",
"12 / 5 = 2.4",
"88 - 21 = 67",
"67 + x = 109",
"x = 42",
"12 * 4 = 48",
"48 - (7 - (5 - (2 - 1))) = 45",
"7 * 5 = 35",
"35 + (12 - 4 - 2 - 1) = 40",
"7 * 6 = 42",
"12 + 7 + 5 + 4 + 2 + 1 = 31",
"88 - (21 - x) = 109",
"88 - 21 + x = 109",
"x = 42",
"x = 42",
"88 + (12 * x) = 109",
"12 * x = 21",
"x = 1.75",
"7 / 4 = 1.75",
"88 + 12 * (7 / 4) = 109",
"88 + 12 * (7 / 4) = 109",
"88 + 12 * (7 / 4) = 88 + 21 = 109.",
"88 + 21 = 109",
"[88 + 12 * (7 / 4)] * (21 / 21) * (5 / 5) * (2 / 2) * 1 = x",
"88 + 12 * (7 / 4) + (21 - 21) + (5 - 5) + (2 - 2) + (1 - 1) = 88 + 12 * 1.75 + 0 + 0 + 0 + 0 = 88 + 21 = 109.",
"12 * 7 / 4 = 21",
"88 + (12 * 7 / 4) = 109",
"21 - 21 = 0",
"x = 21",
"88 + (12 * 7 / 4) + (21 - 21) = 88 + 21 = 109",
"12 * 7 / 4 = 21",
"21 - 21 = 0",
"5 - 2 - 1 = 2",
"21 / 21 = 1",
"2 - 1 = 1",
"109 + 1 = 110",
"109 + 1 = 110",
"(5 - (2 + 1)) * 21 = 42.",
"109 - 42 = 67",
"88 + (12 * 7 / 4) = 88 + 21 = 109.0",
"5 - (2 + 1) = 5 - 3 = 2",
"2 / 21 = 0.09523809523809523",
"109 * 0.095 = 10.35",
"12 * 7 = 84",
"21 - 21 = 0",
"(12 * 7 / 4) = 21",
"88 + (12 * 7 / 4) = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + (12 * 7 / 4) + (21 - 21) = 88 + 21 = 109",
"21 - 21 = 0",
"21 * 2 = 42",
"x = 1",
"88 + (12 * 7 / 4) = 109.",
"12 * 7 = 84",
"(12 * 7) / 4 = 21",
"88 + 21 = 109",
"(2 + 1) / (2 + 1) = 1.0",
"5 - 5 = 0",
"1 + 2 + 5 + 21 = 29",
"88 + (12 * 7 / 4) = 109",
"(5 - 5) * 21 * 1 * 2 = 0",
"21 - (5 + 2 + 1) = 13",
"5 * 2 = 10",
"21 - (10 + 1) = 10",
"21 - (5 * 2 + 1) = 21 - 11 = 10",
"5 * 2 = 10",
"21 - 11 = 10",
"21 / (5 - (2 - 1)) = 5.25",
"21 / (5 - 1) = 5.25",
"21 / 4 = 5.25",
"88 + 21 = 109",
"88 + 21 = x",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 12 - 12 + 7 - 7 + 4 - 4 + 5 - 5 + 2 - 2 + 1 - 1 = 109.",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + (12 - 4 - 7 - 1 - 2 - 5) = 109 - 7 = 102",
"12 - 4 = 8",
"8 - 7 = 1",
"1 - 1 = 0",
"0 - 2 = -2",
"-2 - 5 = -7",
"88 + 21 - 7 = 102",
"109 - 102 = 7",
"4 + 7 + 1 + 2 + 5 = 19",
"12 - 19 = -7",
"88 + 21 - 7 = 102",
"88 + 21 + x = 109",
"x = 0",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 - 4 - 7 - 1 + 2 + 5 = 7.",
"12 - 4 = 8",
"8 - 7 = 1",
"1 - 1 = 0",
"0 + 2 = 2",
"2 + 5 = 7",
"12 + 4 - 7 - 1 - 2 - 5 = 1.",
"12 + 4 - 7 - 1 - 2 - 5 = 16",
"-7 = 9 - 1 = 8 - 2 = 6 - 5 = 1",
"9 - 1 = 8",
"8 - 2 = 6",
"6 - 5 = 1",
"12 - (4 + 7 + 1 + 2 + 5) = -7",
"4 + 7 + 1 + 2 + 5 = 19",
"12 - 19 = -7",
"12 - 19 = -7",
"(12 + 5) - (4 + 7 + 1 + 2) = 3.",
"12 + 5 = 17",
"4 + 7 + 1 + 2 = 14",
"17 - 14 = 3",
"(12 + 4 + 5) - (7 + 1 + 2) = 21 - 10 = 11",
"12 + 4 + 5 = 21",
"7 + 1 + 2 = 10",
"21 - 10 = 11",
"(12 + 7 + 5) - (4 + 1 + 2) = 24 - 7 = 17.",
"12 + 7 + 5 = 24",
"4 + 1 + 2 = 7",
"24 - 7 = 17",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"4 + 2 = 6",
"5 - 6 = -1",
"12 * -1 = -12",
"-12 / 6 = -2",
"12 - 7 * 5 - 4 = 5",
"5 * 1 - 3 = 2",
"2 = 2",
"12 / 4 * (5 - (2 + 1)) = 6.0",
"12 / 4 = 3",
"2 + 1 = 3",
"5 - 3 = 2",
"3 * 2 = 6",
"6 - 7 = -1",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109",
"21 * 5 = 105",
"105 + (88 / (12 - (7 + (4 / 2)))) + 1 = x",
"4 / 2 = 2",
"12 - (7 + 2) = 3",
"7 + 2 = 9",
"88 / (12 - 9) = 29.33",
"105 + 29.33 + 1 = 135.33",
"4 / 2 = 2",
"7 + 2 = 9",
"12 - 9 = 3",
"7 - 1 = 6",
"21 - 3.27 = 17.73",
"5 * 17.73 = 88.65",
"88 + 12 = 100",
"21 - 12 = 9",
"7 + (5 - (4 - (2 - 1))) = 9",
"100 + 9 = 109",
"88 + 21 = 109",
"105 + 4 = 109",
"21 - 12 = 9",
"7 + 2 = 9",
"88 + 12 = 100.",
"7 + (5 - (4 - (2 - 1))) = 9",
"5 - (4 - (2 - 1)) = 2",
"4 - (2 - 1) = 3",
"2 - 1 = 1",
"7 + (5 - 3) = 9",
"7 + 2 = 9",
"88 + 12 + 7 + 5 + 4 + 2 + 1 = 109.",
"x = 21",
"x = 21",
"88 + 21 = 109",
"x = 21",
"21 - x = 21",
"21 - 12 = 9",
"21 / (7 / 3) = 9",
"21 / (7 / 3) = 9",
"x = 21",
"88 + 21 = 109",
"x = 21",
"(88 + 12) + (21 - 12) = 100 + 9 = 109",
"88 + (21 - (12 / ( (7 - 5) + (4 / (2 + 1)) )) = x",
"7 - 5 = 2",
"2 + 1 = 3",
"21 - (12 / ( (7 - 5) + (4 / (2 + 1)) )) = x",
"88 + (21 - (12 / ( (7 - 5) + (4 / (2 + 1)) )) = x",
"2 + 1 = 3",
"4 / 3 = 1.333",
"7 - 5 = 2",
"12 / 3.333 = 3.6",
"21 - 3.6 = 17.4",
"88 + 17.4 = 105.4",
"(88 + 12) + (7 + (5 - (4 - (2 - 1)))) = 100 + 9 = 109.",
"100 + 9 = 109",
"9 + 21 - 21 = 9",
"(88 + 12) + (7 + (5 - (4 - (2 - 1)))) + (21 - 21) = 109",
"4 - (2 - 1) = 3",
"2 - 1 = 1",
"21 - 21 = 0",
"5 - (4 - (2 - 1)) = 5 - 3 = 2",
"7 + (5 - (4 - (2 - 1))) = 7 + 2 = 9",
"88 + 12 = 100",
"(88 + 12) + (7 + (5 - (4 - (2 - 1)))) = 100 + 9 = 109",
"21 - 14 = 7",
"21 - 14 = 7",
"7 + (5 - (4 - (2 - 1))) = 9",
"21 - x + (5 - (4 - (2 - 1))) = 9",
"21 + (5 - 3) - 9 = 14",
"21 + 2 - 9 = 14",
"x = 14",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"88 + 12 + 7 + 5 - 4 + (2 - 1) = 109.0",
"2 - 1 = 1",
"88 + 12 = 100",
"100 + 7 = 107",
"107 + 5 = 112",
"112 - 4 = 108",
"108 + 2 = 110",
"110 - 1 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"x = 21.",
"x = 21",
"21 * (21 / 21) = 21, 21 + (21 - 21) = 21",
"21 * (21 / 21) = 21",
"21 + (21 - 21) = 21",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"(88 + 12 + 7 + 5 - 4 + 2 - 1) * (21 / 21) = 109 * 1 = 109.",
"88 + 12 + 7 + 5 - 4 + 2 - 1 = 109",
"21 / 21 = 1",
"109 * 1 = 109",
"21 - 16 = 5",
"88 + 12 + 7 + 5 - 4 + 2 - 1 = 109",
"+ (21 - 16) = x",
"21 - 16 = 5",
"21 - 16 = 5",
"x = 16",
"21 - (4 + 2 + 1 + x) = 21 - (7 + x) = 14",
"21 - 7 = 14",
"88 + 21 = 109.",
"12 - 12 = 0",
"88 + 21 + (12 - 7 - 5) * (4 - 2 - 1) = 109",
"12 - 7 - 5 = 0",
"4 - 2 - 1 = 1",
"(0 * 1) = 0",
"88 + 21 + 0 = 109",
"12 - 7 - 5 = 0",
"4 - 2 - 1 = 1",
"0 * 1 = 0",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 12 + 7 + 5 + 4 + 2 + 1 = 109",
"12 - 7 - 5 = 0",
"4 - 2 - 1 = 1",
"0 * 1 = 0",
"88 + 21 + 0 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 - 7 - 5 = 0",
"0 * 1 = 0.",
"88 + 21 = 109.",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 - 7 - 5 = 0",
"4 - 2 - 1 = 1",
"0 * 1 = 0",
"88 + 21 + 0 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109.",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"x = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"x = 0",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"4 - 2 - 1 = 1",
"(12 - 7 - 5) * (4 - 2 - 1) = 0 * 1 = 0.",
"88 + 21 + (12 - 7 - 5) * (4 - 2 - 1) = 109 + 0 = 109",
"12 - 7 - 5 = 0",
"4 - 2 - 1 = 1",
"(12 - 7 - 5) * (4 - 2 - 1) = 0",
"109 + 0 = 109",
"88 + 21 = 109",
"12 + 7 + 5 = 24",
"4 + 2 + 1 = 7",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + (12 - 7 - 5) * (4 - 2 - 1) = 109",
"12 - 7 - 5 = 0",
"4 - 2 - 1 = 1",
"0 * 1 = 0",
"88 + 21 + 0 = 109",
"x = 109.",
"x = 109.",
"88 + 21 + (12 - 7 - 5) * (4 - 2 - 1) = 109",
"8 = 8",
"109 - 88 = 21",
"88 + 21 = 109",
"88 + 21 + x = 109",
"x = 21",
"x = 21",
"109 - 88 = 21",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"x = 21",
"x = 21",
"88 + 21 = 109",
"12 - 7 - 5 = 0",
"4 - 2 - 1 = 1",
"x = 0",
"(12 - 7 - 5) * (4 - 2 - 1) = 0",
"12 - 4 - 7 - 1 = 0",
"12 - 4 - 7 - 1 = 0",
"0 * x = 0",
"(12 - 4 - 7 - 1) * (5 - 2) = 0",
"88 + 21 + 0 = 109",
"88 + 21 + (12 - 4 - 7 - 1) * (5 - 2) = 109",
"12 - 4 - 7 - 1 = 0",
"5 - 2 = 3",
"0 * 3 = 0",
"88 + 21 + 12 + 4 + 7 + 1 + 5 + 2 = 136",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"x = 21",
"88 + 21 + x = 109",
"88 + 21 = 109",
"x = 0",
"88 + 21 + 0 = 109 ",
"88 + 21 + 7 + 4 + 1 + 2 + 12 + 5 = 135.",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"88 + 21 = 109",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"(12 - 7 - 5) * (4 - 2 - 1) = 0 * 2 = 0",
"(7 - 4 - 1 - 2) * (12 - 5) = 0 * 7 = 0",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"x = 100",
"109 - 88 = 21",
"88 + (21 * x) = 109",
"88 + 21 = 109",
"21 * 1 = 21",
"88 + (21 * 1) = 109",
"(12 - 7 - 5) * (4 - 2) + 1 = 1",
"21 * 1 = 21",
"88 + 21 = 109",
"(12 - 7 - 5) + (4 - 2 - 1) = 1",
"21 * (0 + 1) = 21",
"88 + 21 * ( (12 - 7 - 5) + (4 - 2 - 1) ) = 109",
"88 + 21 + 12 + 7 + 5 + 4 + 2 + 1 = 140",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"88 + x = 109",
"x = 21",
"42 / 2 = 21",
"(4 - 1) = 3",
"(7 - (4 - 1)) = 4",
"12 / x = y",
"88 + 21 = 109.",
"x = 0",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 - 7 - 5 = 0",
"4 - 2 - 1 = 1",
"x = 0",
"12 - 4 - 7 - 1 = 0",
"5 - 2 = 3",
"x = 0",
"7 - 4 - 1 - 2 = 0",
"12 - 5 = 7",
"x = 0",
"5 - (4 + 1) = 0",
"12 - 7 - 2 = 3",
"0 * 3 = 0",
"(5 - 4 - 1) * (12 - 7 - 2) = 0 * 3 = 0",
"88 + 21 + 0 = 109",
"(5 - 4 - 1) * (12 - 7 - 2) = 0 * 3 = 0 ",
"88 + 21 + (5 - 4 - 1) * (12 - 7 - 2) = 88 + 21 + 0 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"2 * 1 = 2",
"(2 * 1) - (4 - (12 - 7 - 5)) = x",
"4 - (12 - 7 - 5) = x",
"12 - 7 - 5 = 0",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 - (7 + 5) = 0",
"4 - (2 + 1) = 1",
"12 - (5 + 7) = 0",
"(4 - 2) - 1 = 1",
"88 + 21 = 109",
"x = 109",
"12 / (4 + 2) - (7 - 5 - 1) = 0.0",
"4 + 2 = 6",
"7 - 5 - 1 = 1",
"(12 - (7 + 5)) * (4 - (2 + 1)) = 0",
"0 * 1 = 0",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 - 7 - 5 = 0",
"4 - 2 - 1 = 1",
"5 - 5 * 2 - 1 = 0",
"0 * 1 = 0",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109",
"88 + 21 = 109",
"88 + x = 109",
"88 + x = 109",
"109 - 88 = 21",
"88 + 21 = 109",
"88 + (21 * x) = y",
"88 + (21 * 1) = 109",
"21 * 1 = 21",
"88 + 21 * 1 = 109",
"21 * 1 + 88 = 109",
"12 - 7 - 5 = 0",
"4 - 2 = 2",
"0 * 2 = 0",
"88 + 21 * 1 + (12 - 7 - 5) * (4 - 2) = 109 + 0 = 109",
"88 + 21 * 1 + (12 - 7 - 5) * (4 - 2) = 109.0",
"12 - 7 - 5 = 0",
"4 - 2 = 2",
"21 * 1 = 21",
"(12 - 7 - 5) * (4 - 2) = 0",
"88 + 21 * 1 = 109",
"88 + 21 * 1 + (12 - 7 - 5) * (4 - 2) = 109.0",
"4 - 2 = 2",
"1 * (4 - 2) = 2",
"1 * 2 = 2",
"2 * 21 = 42",
"42 + 88 = 130",
"130 - 21 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"5 / 1 = 5",
"88 + 21 = 109",
"12 / 12 = 1",
"4 / 2 = 2",
"7 - 5 = 2",
"2 - 2 = 0",
"(4 / 2) - (7 - 5) = 0",
"( (4 / 2) - (7 - 5) ) * (12 - 1) = 0",
"88 + 21 + 0 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"(12 - 4) / 2 = 4",
"7 - 5 = 2",
"8 / 2 - 2 = 2",
"4 - 2 = 2",
"12 - 5 - 7 = 0",
"12 - 5 = 7",
"7 - 7 = 0",
"4 - 2 - 1 = 1",
"0 * 1 = 0",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109",
"88 + 21 = 109",
"x = 0",
"x = 109",
"x = y",
"21 * 5 = 105",
"105 + 4 = 109",
"21 * 5 + 4 = 109",
"105 + 4 = 109",
"88 - 88 = 0",
"21 * 5 = 105",
"105 + (88 / x) = 109",
"109 - 105 = 4",
"88 / x = 4",
"12 + 7 + 2 + 1 = 22",
"21 * 5 + (88 / (12 + 7 + 2 + 1)) = 105 + (88 / 22) = 105 + 4 = 109",
"105 + 4 = 109",
"88 = 88",
"21 = 21",
"5 = 5",
"12 = 12",
"7 = 7",
"2 = 2",
"1 = 1",
"4 = 4",
"21 + 5 + 88 + 12 + 7 + 2 + 1 = 136",
"4 = 4",
"x = 4",
"88 / (12 + 7 + 2 + 1 - 4) = 88 / 18 = 4.888",
"12 + 7 + 2 + 1 - 4 = 18",
"22 - 4 = 18",
"88 / 18 = 4.888",
"x = 4",
"12 + 7 + 2 + 1 + 4 = 26 ",
"88 / x = 4",
"x = 22",
"12 + 7 + 2 + 1 = 22",
"(12 + 7 + 2 + 1) - 4 = 18",
"88 / 18 = 4",
"12 + 7 + 2 + 4 - 1 = 20",
"21 + 3 = 24",
"88 / 24 = 3.6666666666666665",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 * (8 + 1) = 108",
"12 * 8 = 96",
"96 + 13 = 109",
"88 + 12 + 7 + 2 = 109",
"88 + 12 = 100",
"100 + 7 = 107",
"107 + 2 = 109",
"21 - 5 - 4 - 1 = 11",
"21 - (5 + 4 + 1) = 11",
"88 + 12 + 7 + 2 + (21 - 21) = 109.",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"88 - (12 + 7 + 1 + 2) = 66",
"105 + 4 + 66 = 175",
"21 * 5 + 4 + 88 - 88 = 109",
"21 * 5 + (88 / (12 - (7 + 1 + 2))) = 105 + (88 / (12 - 10)) = 105 + (88 / 2) = 105 + 44 = 149",
"21 * 5 = 105",
"105 + 44 = 149",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"(7 - (4 + 2 + 1)) * (12 - 5) = (7 - 7) * 7 = 0 * 7 = 0",
"(7 - 7) * 7 = 0",
"0 * 7 = 0",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + (12 - 7 - 5) * (4 - 2 - 1) = 109",
"12 - 7 - 5 = 0",
"4 - 2 - 1 = 1",
"0 * 1 = 0",
"88 + 21 + 0 = 109",
"88 + 21 + (12 - 4 - 7 - 1) * (5 - 2) = 109",
"88 + 21 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 + 4 + 7 + 1 + 2 + 5 + 21 + 88 = 140",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"4 / 2 = 2",
"7 - 5 = 2",
"2 - 2 = 0",
"12 - 1 = 11",
"0 * 11 = 0",
"88 + 21 + 0 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"21 * 1 = 21",
"12 - 7 - 5 = 0",
"4 - 2 = 2",
"0 * 2 = 0",
"88 + 21 + 0 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"(12 / (7 - 5)) - (4 + 2) = 0.",
"12 / (7 - 5) = 6",
"4 + 2 = 6",
"(12 / 2) - 6 = 0",
"6 - 6 = 0",
"0 * 1 = 0",
"88 + 21 + (12 / (7 - 5) - (4 + 2)) * 1 = 109.0",
"12 / (7 - 5) = 6.0",
"4 + 2 = 6",
"(4 + 2) * 1 = 6",
"(12 / (7 - 5) - (4 + 2)) = 0",
"(12 / (7 - 5) - (4 + 2)) * 1 = 0",
"7 - 5 = 2",
"12 / 2 = 6",
"4 + 2 = 6",
"6 - 6 = 0",
"0 * 1 = 0",
"88 + 21 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + (12 / (7 - 5) - 4 - 2) * 1 = 109.0",
"12 / (7 - 5) = 6.0",
"7 - 5 = 2",
"(12 / (7 - 5) - 4 - 2) = -6.0",
"(12 / (7 - 5) - 4 - 2) * 1 = -6.0",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109",
"x = 109",
"88 + 21 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"7 - 5 = 2",
"12 / 2 = 6",
"4 + 2 = 6",
"6 - 6 = 0",
"0 * 1 = 0",
"21 * 5 = 105",
"105 + 4 = 109",
"88 + 21 = 109",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 * 7 = 84",
"88 + 21 + 12 - 12 = 109",
"88 + 21 + (12 / (7 - 5) - (4 + 2)) * 1 = 109.",
"88 + 21 + 0 = 109",
"12 / (7 - 5) = 6",
"4 + 2 = 6",
"7 - 5 = 2",
"(4 + 2) * 1 = 6",
"4 + 2 = 6",
"88 + 21 = 109",
"21 + 88 = 109",
"88 + 21 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 12 - 12 = 109",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"(12 - 4 - 7 - 1) * (5 - 2) = 0",
"12 - 4 - 7 - 1 = 0",
"5 - 2 = 3",
"0 * 3 = 0",
"88 + 21 + (12 - 4 - 7 - 1) * (5 - 2) = 109.",
"88 + 21 + 0 = 109",
"(12 - 4 - 7 - 1) * (5 - 2) = 0",
"12 - 4 - 7 - 1 = 0",
"5 - 2 = 3",
"88 + 21 = 109",
"88 + 21 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"(7 - 4 - 1 - 2) * (12 - 5) = 0 * 7 = 0.0",
"7 - 4 - 1 - 2 = 0",
"12 - 5 = 7",
"0 * 7 = 0",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + (7 - 4 - 1 - 2) * (12 - 5) = 109.",
"88 + 21 = 109",
"21 + 88 = 109",
"88 + 21 = 109",
"88 + x = 109",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"31 - x = 21",
"x = 21",
"x = 21",
"x = 100",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"88 + x = 109",
"88 + 21 = 109",
"12 - 7 - 5 = 0",
"4 - 2 = 2",
"21 * 1 = 21",
"88 + 21 * 1 + 0 * 2 = 109",
"12 - 7 - 5 = 0",
"4 - 2 = 2",
"0 * 2 = 0",
"21 * 1 = 21",
"88 + 21 + 0 = 109.",
"88 + 21 = 109",
"88 + 21 = 109",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"4 / 2 = 2",
"7 - 5 = 2",
"12 - 1 = 11",
"2 * 11 = 22",
"88 + 21 + 22 = 131",
"88 + 21 + (4 / 2 - (7 - 5)) * (12 - 1) = 109",
"4 / 2 = 2",
"7 - 5 = 2",
"2 - 2 = 0",
"12 - 1 = 11",
"0 * 11 = 0",
"88 + 21 + 0 = 109.",
"88 + 21 = 109",
"88 + 21 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109",
"88 + 21 = 109",
"88 + 21 = 109",
"x + y + z + w = 109",
"88 + 20 = 108",
"x = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"21 * 5 + 4 = 109",
"88 + 21 = 109",
"88 + x = 109",
"88 + 21 = 109",
"88 + 21 = 109",
"x = 0",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 - 4 - 7 - 1 = 0",
"5 - 2 = 3",
"0 * 3 = 0",
"7 - 4 - 1 - 2 = 0",
"12 - 5 = 7",
"0 * 7 = 0",
"12 / 2 - 6 = 0",
"6 - 6 = 0",
"(12/(7-5) - (4+2)) * 1 = 0",
"5 - 2 - 1 = 2",
"12 - 7 - 4 = 1",
"2 * 1 = 2",
"12 + 5 - 7 - 4 - 2 - 1 = 17",
"12 + 5 = 17",
"7 + 4 + 2 + 1 = 14",
"17 - 14 = 3",
"12 - 5 = 7",
"7 - 4 - 2 - 1 = 0",
"7 * 0 = 0",
"(12 - 5) * (7 - 4 - 2 - 1) = 0",
"88 + 21 = 109",
"12 - 5 = 7; 7 - 4 - 2 - 1 = 0; 7 * 0 = 0.",
"88 + 21 + 0 = 109",
"88 + 21 + 12 + 5 + 7 + 4 + 2 + 1 = 140.",
"88 + 21 + 0 = 109.",
"(4 * 2) - (12 - 7 - 5 - 1) = x",
"4 * 2 = 8",
"12 - 7 - 5 - 1 = -1",
"8 - (-1) = 9",
"12 - 7 = 5",
"5 - 2 = 3",
"4 - 1 = 3",
"5 * 3 * 3 = 45",
"88 + 21 = 109",
"21 - 21 = 0",
"7 - 1 = 6.",
"(12 / (7 - 1)) - (5 - (4 - 2)) = x",
"7 - 1 = 6",
"4 - 2 = 2",
"5 - 2 = 3",
"12 / 6 = 2",
"2 - 3 = -1",
"2 - 3 = -1",
"12 / (7 - 5) = 6.0",
"4 + 2 = 6",
"6 - 6 = 0",
"0 * 1 = 0",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"5 * 2 = 10",
"12 - 7 - 4 - 1 = 0",
"10 - 0 = 10",
"(5 * 2) - (12 - 7 - 4 - 1) = 10 - 0 = 10",
"88 + 21 + (5 * 2 - (12 - 7 - 4 - 1)) - 10 = 109",
"5 * 2 = 10",
"12 - 7 - 4 - 1 = 0",
"10 - 0 = 10",
"(5 * 2 - (12 - 7 - 4 - 1)) - 10 = 10",
"5 * 2 = 10",
"12 - 7 - 4 - 1 = 0",
"109 + (10 - 0) = 119",
"88 + 21 = 109",
"x * y = 109",
"88 + 21 = 109",
"21 * 5 = 105",
"88 + 105 = 193",
"21 * 4 = 84",
"88 + 84 = 172",
"21 * 1 = 21",
"88 + 21 = 109",
"12 * 9 = 108",
"7 + 2 = 9",
"12 * (7 + 2) = 108",
"108 + 1 = 109",
"12 * (7 + 2) + 1 + (88 - 21 - 5 - 4) = 109",
"88 - 21 = 67",
"67 - 5 = 62",
"62 - 4 = 58",
"108 + 1 + 58 = 167",
"88 - 21 - 5 - 4 = 58.",
"21 * 5 = 105",
"105 + 4 = 109",
"88 - (12 + 7 + 1 + 2) = 66",
"88 - 12 * 7 + 1 + 2 = 7",
"x = 21",
"88 + 21 = 109",
"88 + (21 * x) = y",
"21 * (5 - (12 / 4)) = 42",
"88 + 42 = 130",
"12 / 4 = 3",
"7 - 3 = 4",
"5 - 1 = 4",
"4 * 4 = 16",
"21 * 5 = 105",
"105 + 4 = 109",
"88 - 88 = 0",
"21 * 5 + 4 + (88 - (12 + 7 + 1 + 2)) = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"109 + (88 - 88) = 109",
"88 - (12 + 7 + 1 + 2) = 88 - 22 = 66",
"12 + 7 + 1 + 2 = 22",
"88 - 22 = 66",
"105 + 4 + 66 = 175",
"21 * 5 + 4 + (12 - 7 - 1 - 2) - 88 = 23",
"105 + 4 + 2 - 88 = 23",
"105 + 4 = 109",
"88 + 21 = 109.",
"x = 0",
"x + 12 + 4 + 7 + 1 + 2 + 5 = 0",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"(12 - 7 - 5) * (4 - 2 - 1) = 0 * 1 = 0.",
"(12 - 4 - 7 - 1) * (5 - 2) = 0",
"0 * 3 = 0",
"(7 - 4 - 1 - 2) * (12 - 5) = 0",
"0 * 7 = 0",
"12 / (7 - 5) = 12 / 2 = 6",
"4 + 2 = 6",
"6 - 6 = 0",
"0 * 1 = 0",
"7 * 0 = 0",
"(5 - 2 - 1) * (12 - 7 - 4) = 2",
"2 * 1 = 2",
"(12 - 7) - (5 - (4 - 2 - 1)) = 1.",
"12 - 7 = 5",
"5 - (4 - 2 - 1) = 5",
"4 - 2 - 1 = 1",
"5 - 1 = 4",
"5 - 4 = 1",
"(4 * 2) - (12 - 7 - 5 + 1) = 7.",
"4 * 2 = 8",
"12 - 7 - 5 + 1 = 1",
"8 - 1 = 7",
"12 - 7 = 5",
"5 - 5 = 0",
"0 + 1 = 1",
"8 - 1 = 7",
"1 + 2 + 3 + 4 + 5 = 15",
"(5 * 2) - (12 - 7 - 4 - 1) = 10 - 0 = 10",
"(5 * 2) - (12 - 7 - 4 - 1) - 10 = 0",
"(12 - 5) - (7 - 4) * (2 - 1) = 5 * 1 = 5.",
"(12 - 5) - (7 - 4) = 5 - 3 = 2",
"2 - 1 = 1",
"12 - 5 = 7",
"7 - 4 = 3",
"12 - 5 = 7",
"7 - 4 = 3",
"7 - 3 = 4",
"2 - 1 = 1",
"4 * 1 = 4",
"(12 - 5) * (7 - 4 - 2 - 1) = 0 ",
"12 - 5 = 7",
"7 - 4 = 3",
"3 - 2 = 1",
"1 - 1 = 0",
"7 * 0 = 0",
"12 - 5 = 7",
"7 - 4 - 2 - 1 = 0",
"(12 - 5) * (7 - 4 - 2 - 1) = 7 * 0 = 0",
"88 + 21 + 0 = 109",
"12 - 5 = 7",
"7 - 4 - 2 - 1 = 0",
"(12 - 5) * (7 - 4 - 2 - 1) = 7 * 0 = 0",
"88 + 21 + 0 = 109",
"88 + 21 + 12 + 5 + 7 + 4 + 2 + 1 = 109",
"12 - 7 = 5",
"5 - 5 = 0",
"0 - 4 = -4",
"-4 + 1 = -3",
"21 - (-3) = 24",
"12 / (5 - 1) - (7 - 4) = 0.0",
"12 / (5 - 1) = 3.0",
"5 - 1 = 4",
"7 - 4 = 3",
"(12 / (5 - 1) - (7 - 4)) * 2 = 0.0",
"x * 2 = 0.0",
"5 - 1 = 4",
"12 / 4 = 3",
"7 - 4 = 3",
"3 - 3 = 0",
"0 * 2 = 0",
"(12 / (5 - 1) - (7 - 4)) * 2 = 0",
"88 + 21 + (12 / (5 - 1) - (7 - 4)) * 2 = 109.0",
"88 + 21 + 12 + 5 + 1 + 7 + 4 + 2 = 136",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"88 + 21 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109.",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"5 - (4 + 1) = 0",
"5 - 5 = 0",
"5 - (4 + 1) = 5 - 5 = 0",
"88 + 21 + (7 * 2) - 12 * (5 - (4 + 1)) = 109",
"7 * 2 = 14",
"4 + 1 = 5",
"5 - (4 + 1) = 0",
"(7 * 2) - 12 = 2",
"(7 * 2) - 12 * (5 - (4 + 1)) = 0",
"88 + 21 + 0 = 109",
"88 + 21 + 7 + 2 + 12 + 5 + 4 + 1 = 140.",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"88 + x = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + (12 - 4 - 7 - 1) * (5 - 2) = 109",
"88 + 21 + (7 - 4 - 1 - 2) * (12 - 5) = 109",
"7 - 4 - 1 - 2 = 0",
"12 - 5 = 7",
"0 * 7 = 0",
"12 / (7 - 5) = 6",
"7 - 5 = 2",
"4 + 2 = 6",
"(12 / (7 - 5) - (4 + 2)) * 1 = 0",
"12 / (5 - 1) = 3",
"5 - 1 = 4",
"7 - 4 = 3",
"(12 / (5 - 1) - (7 - 4)) = 0",
"(12 / (5 - 1) - (7 - 4)) * 2 = 0",
"88 + 21 + (7 * 2 - 12) * (5 - (4 + 1)) = 109",
"7 * 2 - 12 = 2",
"5 - (4 + 1) = 0",
"4 + 1 = 5",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109.",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 0 = 109",
"12 + 5 - (7 + 4 + 2 + 1) = 3.",
"12 + 5 = 17",
"7 + 4 + 2 + 1 = 14",
"17 - 14 = 3",
"12 + 7 - (5 + 4 + 2 + 1) = 7",
"19 - 12 = 7",
"7 != 0",
"5 + 4 + 2 - 12 + 7 - 1 = 5",
"11 - 6 = 5",
"21 * 5 = 105",
"105 + 4 = 109",
"88 + 21 = 109",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 * 7 = 84",
"5 - 1 = 4",
"7 - 4 = 3",
"12 / (5 - 1) = 3",
"(12 / (5 - 1) - (7 - 4)) = 0",
"(12 / (5 - 1) - (7 - 4)) * 2 = 0",
"88 + 21 + 0 = 109",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 0 = 109.",
"88 + 21 + (4 * 2) - (12 - 7 - 5) * 1 = 109",
"(4 * 2) - (12 - 7 - 5) = x",
"12 - 7 - 5 = x",
"4 * 2 = 8",
"( (4 * 2) - (12 - 7 - 5) ) * 1 = x",
"88 + 21 + 8 = 117.",
"12 - 7 - 5 - 4 + 2 = -2",
"0 - 2 * 1 = -2",
"88 + 21 - 2 = 107",
"(5 * 2) - (12 - 7 - 4 - 1) = 10 - 0 = 10.",
"88 + 21 + 10 = 119",
"88 + (21 - 10) = 99.",
"21 - 10 = 11",
"88 + 11 = 99",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + (7 * 2 - 12) * (5 - (4 + 1)) = 109",
"7 * 2 - 12 = 2",
"5 - (4 + 1) = 0",
"7 * 2 = 14",
"4 + 1 = 5",
"21 * 5 = 105",
"105 + 4 = 109",
"88 + 21 = 109",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 * 7 = 84",
"x = 21",
"88 + x = 109",
"88 = 88",
"21 = 21",
"12 = 12",
"4 = 4",
"7 = 7",
"1 = 1",
"2 = 2",
"5 = 5",
"21 + 88 = 109",
"12 + 7 + 2 + 88 = 109",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"5 + 4 + 1 = 10.",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 - 4 * 7 - 5 = 16",
"8 * 2 - 3 = 13",
"16 - 3 = 13",
"x = 13",
"21 - 21 = 0.",
"21 * 5 = 105",
"105 + 4 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + (12 - 7 - 5) * (4 - 2 - 1) = 109",
"88 + 21 + (12 - 4 - 7 - 1) * (5 - 2) = 109",
"12 - 4 - 7 - 1 = 0",
"5 - 2 = 3",
"0 * 3 = 0",
"88 + 21 + (7 - 4 - 1 - 2) * (12 - 5) = 109",
"7 - 4 - 1 - 2 = 0",
"12 - 5 = 7",
"0 * 7 = 0",
"88 + 21 + (12 / (7 - 5) - (4 + 2)) * 1 = 109",
"12 / (7 - 5) = 6",
"(7 - 5) = 2",
"4 + 2 = 6",
"(12 / (7 - 5) - (4 + 2)) * 1 = 0",
"88 + 21 + (7 * 2 - 12) * (5 - (4 + 1)) = 109",
"7 * 2 - 12 = 2",
"5 - (4 + 1) = 0",
"4 + 1 = 5",
"7 * 2 = 14",
"88 + 21 = 109",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"7 * 2 = 14",
"7 * 2 - x = y",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + (7 * 2 - 12) * (5 - (4 + 1)) = 109",
"7 * 2 = 14",
"4 + 1 = 5",
"5 - 5 = 0",
"(14 - 12) * 0 = 0",
"14 - 12 = 2",
"5 - 5 = 0",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + (7 * 2 - 12) * (5 - (4 + 1)) = 109",
"7 * 2 = 14",
"4 + 1 = 5",
"5 - 5 = 0",
"(7 * 2) - 12 = 2",
"(7 * 2) - 12 * (5 - (4 + 1)) = 0",
"88 + 21 = 109",
"88 + 21 + 0 = 109",
"x = 8",
"88 + 21 = 109",
"7 * 2 = 14",
"5 - (4 + 1) = 0",
"4 + 1 = 5",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"7 * 2 = 14",
"14 - 12 = 2",
"4 + 1 = 5",
"5 - 5 = 0",
"2 * 0 = 0",
"88 + 21 + 0 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"x - x = 0",
"88 + 21 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"(12 - 5 - 7) * (4 - 2 - 1) = 0*1 = 0",
"12 - 5 - 7 = 0",
"4 - 2 - 1 = 1",
"0 * 1 = 0",
"(5 - (4 + 1)) * (7 - (12 / 2)) = 0",
"4 + 1 = 5",
"12 / 2 = 6",
"7 - 6 = 1",
"0 * 1 = 0",
"88 + 21 + (7 * 2 - 12) * (5 - (4 + 1)) = 109",
"(7 * 2) - 12 = 2",
"5 - (4 + 1) = 0",
"(4 + 1) = 5",
"7 * 2 = 14",
"2 * 0 = 0",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"(12 - (7 + 5)) * (4 - 2 - 1) = 0",
"12 - 12 = 0",
"4 - 3 = 1",
"0 * 1 = 0",
"7 + 5 - 12 = 0",
"4 * 2 - 8 = 0",
"5 * 2 = 10",
"12 - 2 = 10",
"5 * 2 - (12 - 2) = 0",
"4 * 1 - 4 = 0.",
"7 - 1 - 6 = 0.0",
"12 - 5 - 7 = 0",
"12 - 5 = 7",
"7 - 7 = 0",
"0 * 1 = 0",
"(12 - 5 - 7) * (4 - 2 - 1) = 0",
"4 - 2 - 1 = 1",
"7 * 2 = 14",
"14 - 14 = 0",
"14 - 12 = 2",
"5 - 2 - 3 = 0",
"4 + 1 - 5 = 0",
"4 + 1 = 5",
"5 - 5 = 0",
"12 - 7 - 2 = 3",
"0 * 3 = 0",
"88 + 21 + (4 + 1 - 5) * (12 - 7 - 2) = 109",
"(4 + 1) - 5 = 0",
"12 - 7 - 2 = 3",
"0 * 3 = 0",
"88 + 21 + 4 + 1 + 5 + 12 + 7 + 2 = 140",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + (4 + 1 - 5) * (12 - 7 - 2) = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"x = 100",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"2 * 5 - 10 = 0",
"2 * 5 = 10",
"12 - 2 = 10",
"2 * 5 - (12 - 2) = 0",
"(7 + 5 - 12) * (4 * 1 - 2) = 0",
"7 + 5 - 12 = 0",
"4 * 1 - 2 = 2",
"7 + 5 = 12",
"4 * 1 = 4",
"0 * 2 = 0",
"88 + 21 + 0 = 109",
"88 + 21 = 109.",
"88 + 21 + (7 + 5 - 12) * (4 * 1 - 2) = 109",
"88 + 21 + 7 + 5 + 12 + 4 + 1 + 2 = 109",
"88 + 21 = 109.",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 / (7 - 5) - (4 + 2) = 3 - 6 = -3",
"12 / (7 - 5) = 6",
"7 - 5 = 2",
"4 + 2 = 6",
"( (12 / (7 - 5)) - (4 + 2) ) * 1 = -3 * 1 = -3",
"7 - 5 = 2",
"12 / 2 = 6",
"4 + 2 = 6",
"6 - 6 = 0",
"0 * 1 = 0",
"7 - 5 = 2",
"4 + 2 = 6",
"12 / (7 - 5) = 6",
"(12 / (7 - 5) - (4 + 2)) = 0",
"(12 / (7 - 5) - (4 + 2)) * 1 = 0",
"88 + 21 + 12 + 7 + 5 + 4 + 2 + 1 = 109",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + x = 109",
"88 + 21 = 109",
"88 + 20 + 1 = 109",
"x = 20",
"88 + 21 = 109",
"88 + 5 * 4 = 108.",
"88 + 20 = 108",
"x = 1",
"88 + 5 * 4 + 1 + (21 - 12 - 7 - 2) = 109 ",
"21 - 12 = 9",
"9 - 7 = 2",
"2 - 2 = 0",
"88 + 20 + 1 + 0 = 109",
"88 + 5 * 4 + 1 + (21 - 12 - 7 - 2) = 109.",
"88 + 5 + 4 + 1 + 21 + 12 + 7 + 2 = 140",
"109 + 0 = 109.",
"88 + 21 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"5 * 4 = 20",
"88 + 20 + 1 + 0 = 109",
"5 * 4 = 20",
"21 - 12 - 7 - 2 = 0",
"88 + 20 + 1 + 0 = 109",
"88 + 21 = 109.",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 20 + 1 + 0 = 109.",
"21 * 5 = 105",
"105 + 4 = 109",
"88 + 21 = 109",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"12 * 7 = 84",
"x = 100",
"88 + 5 + 4 + 1 + 21 + 12 + 7 + 2 = 1400.",
"21 * 5 = 105",
"88 + 105 = 193",
"88 + 21 = 109",
"x = 109",
"x = 21",
"21 - 12 - 7 - 2 = 0.",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"109 + 0 = 109.",
"21 * 5 = 105",
"105 + 4 = 109",
"88 + 21 = 109",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109",
"88 + 21 - x = 109",
"88 + 21 = 109",
"88 + 21 - 0 = 109",
"88 + 21 + 0 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"(12 - 5 - 7) * (4 - 2 - 1) = 0*1=0",
"12 - 5 - 7 = 0",
"4 - 2 - 1 = 1",
"0 * 1 = 0",
"(7 - 5) * (4 - 2) = 4",
"12 / 6 = 2",
"(7 - 5) * (4 - 2) = 4",
"12 / 12 = 1",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"(12 - 4 - 7 - 1) * (5 - 2) = 0 * 3 = 0",
"12 + 5 = 17",
"7 + 10 = 17",
"12 + 5 = 17",
"7 + (4 * 2 + 1) = 16",
"4 * 2 = 8",
"(4 * 2 + 1) = 9",
"7 + 9 = 16",
"7 + 9 = 16",
"4 * 2 + 1 = 9",
"12 - 7 + 5 = 10",
"(4 * 2 + 1) - (12 - 7 + 5) = -1",
"9 - 10 = -1",
"5 * 4 - 12 = 8",
"7 - 2 - 1 = 4",
"(5 * 4 - 12) * (7 - 2 - 1) = 32",
"7 * 2 - 14 = 0",
"7 * 2 = 14",
"5 + 4 + 1 = 10",
"12 / 10 = 1.2",
"14 - 14 = 0",
"14 - 12 = 2",
"7 * 2 - 12 = 2",
"(7 * 2 - 12) * (x) = 0",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"21 * 5 = 105",
"105 + 4 = 109",
"21 * 5 + 4 = 109",
"(88 - 88) = 0",
"(12 - 12) = 0",
"21 * 5 + 4 + 88 - 88 = 105 + 4 + 0 = 109",
"88 - (12 + 7 + 1 + 2) * x = 0.",
"88 - (12 + 7 + 1 + 2) = 66",
"12 + 7 + 1 + 2 = 22",
"88 - 22 = 66",
"12 * 7 = 84",
"1 * 2 = 2",
"84 - 2 = 82",
"88 - 82 = 6",
"7 + 1 + 2 = 10",
"12 - 10 = 2",
"88 / 2 = 44",
"88 + 21 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"31 - x = 21",
"x = 21",
"88 + 21 = 109",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 5 * 4 + 1 + 21 - 12 - 7 - 2 = 109.0",
"5 * 4 = 20",
"21 - 12 - 7 - 2 = 0",
"21 - 12 = 9",
"12 - 7 = 5",
"7 - 2 = 5",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 20 + 1 + 0 = 109.",
"88 + 21 + (12 - 7 - 5) * (4 + 2 - 1) = 109",
"12 - 7 - 5 = 0",
"4 + 2 - 1 = 5",
"0 * 5 = 0",
"88 + 21 + 12 + 7 + 5 + 4 + 2 + 1 = 139",
"12 - 7 = 5",
"(12 - 7) - 5 = 0",
"4 + 2 - 1 = 5",
"0 * 5 = 0",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109",
"88 + 21 = x",
"x = 0",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 = 109",
"0 + 109 = 109",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 5 * 4 + 1 + (21 - 12 - 7 - 2) = 109.",
"88 + 21 + (5 - (4 + 1)) * (12 - 7 - 2) = 109",
"5 - (4 + 1) = 0",
"12 - 7 - 2 = 3",
"(5 - (4 + 1)) * (12 - 7 - 2) = 0",
"4 + 1 = 5",
"5 - 5 = 0",
"0 * 3 = 0",
"88 + 21 + 12 - 12 = 109",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 5 + 4 + 1 + 12 + 7 + 2 = 140",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + 12 - 12 = 109",
"100 - 88 = 12",
"21 * 5 = 105",
"105 + 4 = 109",
"12 * 7 = 84",
"88 + x = 109",
"x = 21",
"88 + x = 109",
"31 - x = 21",
"x = 21",
"88 + 21 + (12 + 5) - (7 + 10) = 109",
"88 + 5 * 4 + 1 + (21 - 12 - 7 - 2) = 109.",
"5 * 4 = 20",
"21 - 12 - 7 - 2 = 0"
]
] |
[
{
"has_free_variables": 600,
"invalid_arithmetic": 645,
"merged_text_length": 72633,
"multi_operand": 618,
"offsets_found": 1835,
"total_attempts_created": 2281,
"total_spans_from_llm": 2629,
"unevaluable": 0,
"unique_canonical_keys": 453,
"valid_arithmetic": 1636
}
] |
[
[]
] |
[
[]
] |
[
[]
] |
[
[]
] |
[
[]
] |
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